Real case :
PH : 7.49
PCO2 : 49.7
PO2 : 37.4
Na : 128
HCO3 : 36
BE: 14.5
What is your interpretation ?

Consider a case where the PaCO2 = 23 mm Hg, the pH = 7.54, and the HCO3 = 38 mEq/L ?

This case metabolic alkalosis

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A 78-year-old man is brought in from home after a 3-day history of diarrhoea. His Arterial blood gas
shows:
• pH 7.27 (7.35–7.45)
• HCO3 −. 14 mmol/L (22–24)
• PCO2 28 mmol/L (35–45)
• K+ 2.6 mmol/L (3.5–5.0)
• Na+ 134 mmol/L (135–145)
• Cl− 113 mmol/L (95–105)
• Ur 14 mmol/L (2–7)
• Cr 320 mmol/L (50–100)
• lactate 1.5 mmol/L (<2.2).
Which ONE of the following options would BEST explain the clinical scenario?
A. High AG metabolic acidosis secondary to renal failure
B. High AG metabolic acidosis secondary to dehydration and lactic acidosis
C. Normal AG metabolic acidosis secondary to diarrhoea
D. Concurrent normal AG metabolic acidosis and respiratory alkalosis

Answer in Detail :
https://t.me/Yaqob_Hamood/70

C

👨🏻‍⚕Is mmol/L equal mEq/ L ?

A 35-year-old female presents with a prolongedseizure. Her initial ABG is shown.
• pH 7.25 (7.35–7.45)
• PCO2 55 mmol/L (35–45)
• PO2 100 mmol/L (80–100)
• HCO3 15 mmol/L (22–24)
• Na+ 135 mmol/L (135–145)
• K+ 4.5 mmol/L (3.5–5)
• Cl- 98 mmol/L (95–105).
Which ONE of the following explains the aboveblood gas?
A. Mixed normal AG metabolic acidosis andrespiratory acidosis
B. High AG metabolic acidosis
C. Mixed high AG metabolic acidosis and metabolicalkalosis
D. Mixed high AG metabolic acidosis andrespiratory acidosis

D is the best Answer

in text books and lectures , statement : excess CO2 production in the body leads to acidosis

my confusion : even if tons of CO2 being produced , what matters ??

CO2 reacts with H20 and is converted to H2CO3 and dissociates to H+ & HCO3-

H+ is an acid while bicarbonate is a base , which neutralizes each other .

so what's the problem with excess CO2 ??

isn't it a self-solved issue ??

،this question is from member ?

👨🏻‍⚕ why No one Answer?

🧑‍⚕A. As follows:
✓ Tricuspid regurgitation (TR)
✓ Ventricular septal defect (VSD).