Eff=32/6=16/3,40/5=8
Time=110/(16/3+8)
110/(40/3)
33/4=8,1/4hr
8 hr 15min

Ab. Bc. Ca
12. 10. 15
60
5. 6. 4
2(abc)=15
Abc=7.5
A=7.5-6=1.5
A=1/5*13500=2700

60
12---5
10--6
15---4
abc--7.5
a----1.5
7.5---13500
1.5-------------------2700

15 10 30
30
2:3:1
2+3-1=4*2=8
rem=22/5=4.4=2+4.4=6.4
22/5=4.4hr
actual tym
30/5=6
6.4-6=.4hr

Vicky:
8. 12
24
3. 2

39. - 26
24
50. 15
10. 3

Inlets = 10
Outlet =3

20. 30. -15
60
3. 2. -4

1cycle---3min----1unit
55cyc--165min--55unit
167 min--55+3+2=60

=> 167 min

Shivam is ordered to complete a work in 36 hours.He starred working ,but after 24 hours he realised that 75% of the work is still remaining.By what percentage he must increase his efficiency compared to his original efficiency to complete the work on time?

24*1/25= 12*x/75
X= 6

1---6
500% increase

Solve frm basic

A:b=2:1
C=(2+1)×3/5=9/5

a:b:c=2:1:9/5
a:b:c=10:5:9

Tw=24×36

B=24×36/5= 172.8

720

360.....180

1st
720/12+720/9+720/6+720/4+720/3=680

2nd
360/12+360/9+360/6+360/4+360/3=340

680+340-10x=720
X=30

Tym=720/30= 24

correction - 12.5%

576

Ank-Shu = 64 = 9
Shu-Kar = 72 = 8

Anu:Kar = 7:4

22*9+6*8+30(Kar+Anu) = 576

30(kar+Anu) = 330
kar + Anu = 11
11k = 11
k = 1

Ank:Shu:Kar:Anu = 5:4:4:7

11x + 9(x + 8/3) = 576*87.5%

20x+24 = 504
x = 24.

6----12.5%
36-------------75%

75% = 3/4

Three labourers, working together can dig a pit 324 m deep in 6 days. In one shift, third labour digs as many extra metres from second labour as second labour digs extra from first labour. Work done by the third labour in 10 days is equivalent to the work done by first labour in 14 days. How many metres does the first labour dig in one shift?

10c=14a
a:c= 5:7
....
6= 324
1= 54
...
b= 5+x.
C= x+5+x
7=2x+5
x=1
b= 5+1= 6
...
5:6:7
18=54
5= 15