#leet_code_Q1 #Array Given a non-empty array of integers nums, every element appears twice except for one. Find that single one.
You must implement a solution with a linear runtime complexity and use only constant extra space.
Example 1:
Input: nums = [2,2,1]
Output: 1
Example 2:
Input: nums = [4,1,2,1,2]
Output: 4
Example 3:
Input: nums = [1]
Output: 1 Each element in the array appears twice except for one element which appears only once.
You must implement a solution with a linear runtime complexity and use only constant extra space.
Example 1:
Input: nums = [2,2,1]
Output: 1
Example 2:
Input: nums = [4,1,2,1,2]
Output: 4
Example 3:
Input: nums = [1]
Output: 1 Each element in the array appears twice except for one element which appears only once.
π4
#leet_code_Q2 #Array #leet_code_169 #Majority_Element Given an array nums of size n, return the majority element.
The majority element is the element that appears more than (n / 2)times. You may assume that the majority element always exists in the array.
Example 1:
Input: nums = [3,2,3]
Output: 3
Example 2:
Input: nums = [2,2,1,1,1,2,2]
Output: 2
The majority element is the element that appears more than (n / 2)times. You may assume that the majority element always exists in the array.
Example 1:
Input: nums = [3,2,3]
Output: 3
Example 2:
Input: nums = [2,2,1,1,1,2,2]
Output: 2
Day 5
π Daily Challenge #1
π§© Build Array from Permutation
Given an array nums, build a new array ans where ans[i] = nums[nums[i]] for every index i.
Can you solve it without extra space? (Hint: Think modulo!)
π Problem Link:
π Difficulty: Easy
π· Tags: #Array #InPlace
π‘ Letβs see your optimized solutions!
π Drop your approach in the comments!
π Problem Breakdown #2
π Matrix Rotation Check
Given two n x n matrices, determine if one can be obtained by rotating the other 90Β°, 180Β°, or 270Β°.
How would you efficiently check all possible rotations?
π Problem Link:
π Difficulty: Medium
π· Tags: #Matrix #Transpose
π€ Think about transpose + reverse vs. brute force. Which is better?
π Share your code snippets!
π Advanced Problem Alert!
π’ Tuple with Same Product
Find the number of tuples (a, b, c, d) such that a*b = c*d where all elements are distinct.
Can you avoid an O(nβ΄) solution? (Hint: Hash maps are your friend!)
π Problem Link:
π Difficulty: Medium
π· Tags: #HashTable #Combinatorics
π₯ Challenge: Optimize for large arrays!
π Post your best time complexity in the comments!
π Daily Challenge #1
π§© Build Array from Permutation
Given an array nums, build a new array ans where ans[i] = nums[nums[i]] for every index i.
Can you solve it without extra space? (Hint: Think modulo!)
π Problem Link:
π Difficulty: Easy
π· Tags: #Array #InPlace
π‘ Letβs see your optimized solutions!
π Drop your approach in the comments!
π Problem Breakdown #2
π Matrix Rotation Check
Given two n x n matrices, determine if one can be obtained by rotating the other 90Β°, 180Β°, or 270Β°.
How would you efficiently check all possible rotations?
π Problem Link:
π Difficulty: Medium
π· Tags: #Matrix #Transpose
π€ Think about transpose + reverse vs. brute force. Which is better?
π Share your code snippets!
π Advanced Problem Alert!
π’ Tuple with Same Product
Find the number of tuples (a, b, c, d) such that a*b = c*d where all elements are distinct.
Can you avoid an O(nβ΄) solution? (Hint: Hash maps are your friend!)
π Problem Link:
π Difficulty: Medium
π· Tags: #HashTable #Combinatorics
π₯ Challenge: Optimize for large arrays!
π Post your best time complexity in the comments!
LeetCode
Build Array from Permutation - LeetCode
Can you solve this real interview question? Build Array from Permutation - Given a zero-based permutation nums (0-indexed), build an array ans of the same length where ans[i] = nums[nums[i]] for each 0 <= i < nums.length and return it.
A zero-based permutationβ¦
A zero-based permutationβ¦
π3