给你一个数组 points 和一个整数 k 。数组中每个元素都表示二维平面上的点的坐标，并按照横坐标 x 的值从小到大排序。也就是说 points[i] = [xi, yi] ，并且在 1 <= i < j <= points.length 的前提下， xi < xj 总成立。 请你找出 yi + yj + |xi - xj| 的 最大值，其中 |xi - xj| <= k 且 1 <= i < j <= points.length。 题目测试数据保证至少存在一对能够满足 |xi - xj| <= k 的点。…

You are given an array of integers nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves right by one position. Return…

Implement a last-in-first-out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal stack (push, top, pop, and empty). Implement the MyStack class:

You are given a nested list of integers nestedList. Each element is either an integer or a list whose elements may also be integers or other lists. Implement an iterator to flatten it. Implement the NestedIterator class:

Given an integer array nums and an integer k, return the maximum sum of a non-empty subsequence of that array such that for every two consecutive integers in the subsequence, nums[i] and nums[j], where i < j, the condition j - i <= k is satisfied. A subsequence…

请你设计一个队列，支持在前，中，后三个位置的 push 和 pop 操作。 请你完成 FrontMiddleBack 类：

Implement a first in first out (FIFO) queue using only two stacks. The implemented queue should support all the functions of a normal queue (push, peek, pop, and empty). Implement the MyQueue class:

给你一个下标从 0 开始的整数数组 nums 和一个整数 k 。 一开始你在下标 0 处。每一步，你最多可以往前跳 k 步，但你不能跳出数组的边界。也就是说，你可以从下标 i 跳到 [i + 1， min(n - 1, i + k)] 包含 两个端点的任意位置。 你的目标是到达数组最后一个位置（下标为 n - 1 ），你的 得分 为经过的所有数字之和。 请你返回你能得到的 最大得分 。   示例 1： 输入：nums = [1,-1,-2,4,-7,3], k = 2 输出：7 解释：你可以选择子序列 [1…