leetcode.com 2025-07-11
🔴2402.meeting-rooms-iii
🏷️ Tags
#array #hash_table #sorting #simulation #heap_priority_queue
🔴2402.meeting-rooms-iii
🏷️ Tags
#array #hash_table #sorting #simulation #heap_priority_queue
Telegraph
meeting-rooms-iii
You are given an integer n. There are n rooms numbered from 0 to n - 1. You are given a 2D integer array meetings where meetings[i] = [starti, endi] means that a meeting will be held during the half-closed time interval [starti, endi). All the values of starti…
leetcode.cn 2025-07-18
🔴2163.minimum-difference-in-sums-after-removal-of-elements
🏷️ Tags
#array #dynamic_programming #heap_priority_queue
🔴2163.minimum-difference-in-sums-after-removal-of-elements
🏷️ Tags
#array #dynamic_programming #heap_priority_queue
Telegraph
minimum-difference-in-sums-after-removal-of-elements
给你一个下标从 0 开始的整数数组 nums ,它包含 3 * n 个元素。 你可以从 nums 中删除 恰好 n 个元素,剩下的 2 * n 个元素将会被分成两个 相同大小 的部分。
leetcode.com 2025-07-18
🔴2163.minimum-difference-in-sums-after-removal-of-elements
🏷️ Tags
#array #dynamic_programming #heap_priority_queue
🔴2163.minimum-difference-in-sums-after-removal-of-elements
🏷️ Tags
#array #dynamic_programming #heap_priority_queue
Telegraph
minimum-difference-in-sums-after-removal-of-elements
You are given a 0-indexed integer array nums consisting of 3 * n elements. You are allowed to remove any subsequence of elements of size exactly n from nums. The remaining 2 * n elements will be divided into two equal parts:
leetcode.cn 2025-09-17
🟡2349.design-a-number-container-system
🏷️ Tags
#design #hash_table #ordered_set #heap_priority_queue
🟡2349.design-a-number-container-system
🏷️ Tags
#design #hash_table #ordered_set #heap_priority_queue
Telegraph
design-a-number-container-system
设计一个数字容器系统,可以实现以下功能:
leetcode.com 2025-09-17
🟡2353.design-a-food-rating-system
🏷️ Tags
#design #array #hash_table #string #ordered_set #heap_priority_queue
🟡2353.design-a-food-rating-system
🏷️ Tags
#design #array #hash_table #string #ordered_set #heap_priority_queue
Telegraph
design-a-food-rating-system
Design a food rating system that can do the following:
leetcode.cn 2025-09-18
🟡3408.design-task-manager
🏷️ Tags
#design #hash_table #ordered_set #heap_priority_queue
🟡3408.design-task-manager
🏷️ Tags
#design #hash_table #ordered_set #heap_priority_queue
Telegraph
design-task-manager
一个任务管理器系统可以让用户管理他们的任务,每个任务有一个优先级。这个系统需要高效地处理添加、修改、执行和删除任务的操作。 请你设计一个 TaskManager 类:
leetcode.com 2025-09-18
🟡3408.design-task-manager
🏷️ Tags
#design #hash_table #ordered_set #heap_priority_queue
🟡3408.design-task-manager
🏷️ Tags
#design #hash_table #ordered_set #heap_priority_queue
Telegraph
design-task-manager
There is a task management system that allows users to manage their tasks, each associated with a priority. The system should efficiently handle adding, modifying, executing, and removing tasks. Implement the TaskManager class:
leetcode.cn 2025-09-21
🔴1912.design-movie-rental-system
🏷️ Tags
#design #array #hash_table #ordered_set #heap_priority_queue
🔴1912.design-movie-rental-system
🏷️ Tags
#design #array #hash_table #ordered_set #heap_priority_queue
Telegraph
design-movie-rental-system
你有一个电影租借公司和 n 个电影商店。你想要实现一个电影租借系统,它支持查询、预订和返还电影的操作。同时系统还能生成一份当前被借出电影的报告。 所有电影用二维整数数组 entries 表示,其中 entries[i] = [shopi, moviei, pricei] 表示商店 shopi 有一份电影 moviei 的拷贝,租借价格为 pricei 。每个商店有 至多一份 编号为 moviei 的电影拷贝。 系统需要支持以下操作:
leetcode.com 2025-09-21
🔴1912.design-movie-rental-system
🏷️ Tags
#design #array #hash_table #ordered_set #heap_priority_queue
🔴1912.design-movie-rental-system
🏷️ Tags
#design #array #hash_table #ordered_set #heap_priority_queue
Telegraph
design-movie-rental-system
You have a movie renting company consisting of n shops. You want to implement a renting system that supports searching for, booking, and returning movies. The system should also support generating a report of the currently rented movies. Each movie is given…
leetcode.cn 2025-10-03
🔴407.trapping-rain-water-ii
🏷️ Tags
#breadth_first_search #array #matrix #heap_priority_queue
🔴407.trapping-rain-water-ii
🏷️ Tags
#breadth_first_search #array #matrix #heap_priority_queue
Telegraph
trapping-rain-water-ii
给你一个 m x n 的矩阵,其中的值均为非负整数,代表二维高度图每个单元的高度,请计算图中形状最多能接多少体积的雨水。 示例 1: 输入: heightMap = [[1,4,3,1,3,2],[3,2,1,3,2,4],[2,3,3,2,3,1]] 输出: 4 解释: 下雨后,雨水将会被上图蓝色的方块中。总的接雨水量为1+2+1=4。 示例 2: 输入: heightMap = [[3,3,3,3,3],[3,2,2,2,3],[3,2,1,2,3],[3,2,2,2,3],[3,3,3,3,3]]…