IIT JEE Mains Advance Notes Materials
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🌿 Important Increasing Order 🌱

✔️ BOND ANGLE :-
(i) CH4 , C2H4 , C2H2
(ii) H2O, NH3 , CH4 , CO2
(iii) H2O, NH3 , CH4 , BH3
(iv) NO2—, NO2 , NO2+
(v) H2Se, H2S, H2O
(vi) AsH3 , PH3 , NH3
(vii) PF3 , PCl3 , PBr3 , PI3
(viii) NF3 , NCl3
(ix) NF3 , NH3 , NCl3
(x) OF2 , OH2 , Cl2O

✔️ MELTING POINT :-
(i) Cs, Rb, K, Na, Li
(ii) Mg, Ba, Sr, Ca, Be
(iii) CaI2 , CaBr2 , CaCl2 , CaF2
(iv) BeCl2 , MgCl2 , CaCl2 , SrCl2 , BaCl2
(v) NaI, NaBr, NaCl, NaF
(vi) CsCl, RbCl, KCl, NaCl
(vii) AlCl3 , MgCl2 , NaCl

✔️ BOILING POINT :-
(i) PH3 , AsH3 , NH3 , SbH3
(ii) H2S, H2Se, H2O
(iii) HCl, HBr, HI, HF
(iv) NH3 , HF, H2O
(v) He, Ne, Ar, Kr
(vi) H2O, D2O
(vii) H2 , Cl2 , Br2

✔️ DIPOLE MOMENTS :-
(i) CCl4 , CHCl3 , CH2Cl2 ,CH3Cl
(ii) NF3 , NH3 , H2O, HF
(iii) Cis-chloropropene, Trans-chloropropene
(iv) p, m, o-dichlorobenzene
(v) CH3I, CH3Br, CH3F, CH3Cl
(vi) NH3 , SO2 , H2O, HF
(vii) H2S, H2O
(viii) HI, HBr, HCl, HF
(ix) PH3 , ASH3 , SbH3 , NH3
(x) H2O, H2O2
————————————————
Trick to Remember Some bi-carboxylic acid

1.Oxalic acid-0 carbon- Oh

2.Maleic acid- 1 carbon- My

3.Succinic acid- 2 carbon- Sun

4.Glutamic acid-3 carbon-Go

5.Adipic acid- 4 carbon- And

6.Palmitic acid- 5 carbon- play

Number of carbons refers number of -CH2 group between two COOH group.

For e.g HOOC-COOH (OXALIC ACID) there is no CH2 group between carboxyl. Maleic acid is HOOC-CH2-COOH there is one CH2 group in betwen. This is how you can remember some bi-carboxylic acid.
☑️ Very Important formula

1. (α+в)²= α²+2αв+в²
2. (α+в)²= (α-в)²+4αв
3. (α-в)²= α²-2αв+в²       
4. (α-в)²= (α+в)²-4αв
5. α² + в²= (α+в)² - 2αв.
6. α² + в²= (α-в)² + 2αв.
7. α²-в² =(α + в)(α - в)
8. 2(α² + в²) = (α+ в)² + (α - в)²
9. 4αв = (α + в)² -(α-в)²
10. αв ={(α+в)/2}²-{(α-в)/2}²
11. (α + в + ¢)² = α² + в² + ¢² + 2(αв + в¢ + ¢α)
12. (α + в)³ = α³ + 3α²в + 3αв² + в³
13. (α + в)³ = α³ + в³ + 3αв(α + в)
14. (α-в)³=α³-3α²в+3αв²-в³
15. α³ + в³ = (α + в) (α² -αв + в²)
16. α³ + в³ = (α+ в)³ -3αв(α+ в)
17. α³ -в³ = (α -в) (α² + αв + в²)
18. α³ -в³ = (α-в)³ + 3αв(α-в)

ѕιη0° =0
ѕιη30° = 1/2
ѕιη45° = 1/√2
ѕιη60° = √3/2
ѕιη90° = 1

➡️ ¢σѕ ιѕ σρρσѕιтє σƒ ѕιη

тαη0° = 0
тαη30° = 1/√3
тαη45° = 1
тαη60° = √3
тαη90° = ∞

➡️ ¢σт ιѕ σρρσѕιтє σƒ тαη

ѕє¢0° = 1
ѕє¢30° = 2/√3
ѕє¢45° = √2
ѕє¢60° = 2
ѕє¢90° = ∞

➡️ ¢σѕє¢ ιѕ σρρσѕιтє σƒ ѕє¢

1. ѕιη2α = 2ѕιηα¢σѕα
2. ¢σѕ2α = ¢σѕ²α − ѕιη²α
3. ¢σѕ2α = 2¢σѕ²α − 1
4. ¢σѕ2α = 1 − ѕιη²α
5. 2ѕιη²α = 1 − ¢σѕ2α
6. 1 + ѕιη2α = (ѕιηα + ¢σѕα)²
7. 1 − ѕιη2α = (ѕιηα − ¢σѕα)²
8. тαη2α = 2тαηα / (1 − тαη²α)
9. ѕιη2α = 2тαηα / (1 + тαη²α)
10. ¢σѕ2α = (1 − тαη²α) / (1 + тαη²α)
11. 4ѕιη³α = 3ѕιηα − ѕιη3α
12. 4¢σѕ³α = 3¢σѕα + ¢σѕ3α

» ѕιη²Θ+¢σѕ²Θ=1
» ѕє¢²Θ-тαη²Θ=1
» ¢σѕє¢²Θ-¢σт²Θ=1
» ѕιηΘ=1/¢σѕє¢Θ
» ¢σѕє¢Θ=1/ѕιηΘ
» ¢σѕΘ=1/ѕє¢Θ
» ѕє¢Θ=1/¢σѕΘ
» тαηΘ=1/¢σтΘ
» ¢σтΘ=1/тαηΘ
» тαηΘ=ѕιηΘ/¢σѕΘ
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💡 Important Increasing Order

BOND ANGLE :-
(i) CH4 , C2H4 , C2H2
(ii) H2O, NH3 , CH4 , CO2
(iii) H2O, NH3 , CH4 , BH3
(iv) NO2—, NO2 , NO2+
(v) H2Se, H2S, H2O
(vi) AsH3 , PH3 , NH3
(vii) PF3 , PCl3 , PBr3 , PI3
(viii) NF3 , NCl3
(ix) NF3 , NH3 , NCl3
(x) OF2 , OH2 , Cl2O

MELTING POINT :-
(i) Cs, Rb, K, Na, Li
(ii) Mg, Ba, Sr, Ca, Be
(iii) CaI2 , CaBr2 , CaCl2 , CaF2
(iv) BeCl2 , MgCl2 , CaCl2 , SrCl2 , BaCl2
(v) NaI, NaBr, NaCl, NaF
(vi) CsCl, RbCl, KCl, NaCl
(vii) AlCl3 , MgCl2 , NaCl

BOILING POINT :-
(i) PH3 , AsH3 , NH3 , SbH3
(ii) H2S, H2Se, H2O
(iii) HCl, HBr, HI, HF
(iv) NH3 , HF, H2O
(v) He, Ne, Ar, Kr
(vi) H2O, D2O
(vii) H2 , Cl2 , Br2

DIPOLE MOMENTS :-
(i) CCl4 , CHCl3 , CH2Cl2 ,CH3Cl
(ii) NF3 , NH3 , H2O, HF
(iii) Cis-chloropropene, Trans-chloropropene
(iv) p, m, o-dichlorobenzene
(v) CH3I, CH3Br, CH3F, CH3Cl
(vi) NH3 , SO2 , H2O, HF
(vii) H2S, H2O
(viii) HI, HBr, HCl, HF
(ix) PH3 , ASH3 , SbH3 , NH3
(x) H2O, H2O2