**If a b - c = 0, then what is the value of $$ \\frac{(b-c)^2}{4bc}\\frac{(c-a)^2}{4ca}\\frac{(a b)^2}{4ab} $$ ?** A) $$ -\\frac{1}{2} $$ B) $$ \\frac{1}{64} $$ C) $$ \\frac{3}{4} $$ D) $$ -\\frac{3}{4} $$ Click Link for Answer