Kompyuter injineringi 1-kurs 1-Tajriba ishi 1-topshiriq javoblari👇

1.1#include <iostream>
using namespace std;

int main() {
double x, V;
cin >> x;
V = x * x * x;
cout << V;
}

1.2 #include <iostream>
using namespace std;

int main() {
double r1, r2, r3;
cin >> r1 >> r2 >> r3;
double S1 = 3.14 * r1 * r1;
double S2 = 3.14 * r2 * r2;
double S3 = 3.14 * r3 * r3;
cout << S1 << " " << S2 << " " << S3;
}

3. Teng yonli uchburchak peremetri P berilgan, uchburchak tomoni va yuzini toping

#include <iostream>
#include <cmath>
using namespace std;

int main() {
double P, a, S;
cin >> P;
a = P / 3;
S = sqrt(3) / 4 * a * a;
cout << a << " " << S;
}

4. Tekislikda uchta nuqta A(x1,y1), B(x2,y2), C(x3,y3) berilgan AB va AC nuqtalar orasidagi masofani toping.

#include <iostream>
#include <cmath>
using namespace std;

int main() {
double x1,y1,x2,y2,x3,y3;
cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
double AB = sqrt((x2-x1)*(x2-x1) + (y2-y1)*(y2-y1));
double AC = sqrt((x3-x1)*(x3-x1) + (y3-y1)*(y3-y1));
cout << AB << " " << AC;
}

5. To’g’ri burchakli uchburchak katetlari a va b berilgan, uchburchak gipotenuzasini, yuzini va burchaklari sinusini toping.

#include <iostream>
#include <cmath>
using namespace std;

int main() {
double a, b;
cin >> a >> b;
double c = sqrt(a*a + b*b);
double S = a*b/2;
double sinA = a / c;
double sinB = b / c;
cout << c << " " << S << " " << sinA << " " << sinB;
}

6. Ikki xonali son berilgan raqamlar yig’indisini toping.

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;
int s = (n / 10) + (n % 10);
cout << s;
}

7. Uzunlik a metr b detsimetr va c santimetrda berilgan ularni m, dm va sm da ifodalng. (M: 3m 50dm 20sm – 8,2m, 82 dm, 820 sm)

#include <iostream>
using namespace std;

int main() {
int a, b, c;
cin >> a >> b >> c;

int t = a*100 + b*10 + c;

double m = t / 100.0;
int dm = t / 10;
int sm = t;

cout << m << " " << dm << " " << sm;
}

8. Uch xonali a son berilgan bu sonning yuzlar, o’nlar va birlar xonasidagi raqamlarini alohida alohida yozing.

#include <iostream>
using namespace std;

int main() {
int a;
cin >> a;

int y = a / 100;
int o = (a % 100) / 10;
int b = a % 10;

cout << y<< " " << o<< " " << b;

return 0;
}