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What is the output of this program?

#include <stdio.h>
int main() {
printf("%d", printf("ABCD"));
return 0;
}

In this question we use formal a×2^k and
-(2^n -k) here k is the number and n is the no. of bit

Therefore
We have n = 8 , (char size)
K = 21

- ( 2⁸ -168) = - (256-168)
= -88

#include <stdio.h>
int main() {
int i = -1;
for (++i; i++; i++)
printf("Untoldcoding");
return 0;
}

Think and give answer ... In quiz

Consider the following C program:

#include <stdio.h>
int main( )
{
int i, j, k = 0;

j=2*3/4+2.0/5+8/5;

k -= --j;

for (i=0; i<5; i++)
{
switch(i+k)
{
case 1:

case 2: printf("\n%d", i+k);

case 3: printf("\n%d", i+k)

default: printf("\n%d", i+k);

}

}
return 0;
}

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#include <stdio.h>

int main()

{
int i;
for(i=1; i<=10; i++){
if(i>5){
break;
}
}
printf("%d",i);

return 0;
}

Consider the C Programming

#include<stdio.h>

void print (int n) {
if (n <= 0) return;
print(n--);
printf ("%d", n);

}

int main() {
print(5);
return 0;

}