What will be the output of the code?

❌ The program has an error because there isn’t any function to return self.a
❌ The program has an error because b is private and display(self) is returning a private member
✅ The program has an error because b is private and hence can’t be printed
❌ The program runs fine and 1 is printed

Explanation:
Variables beginning with two underscores are said to be private members of the class and they can’t be accessed directly.

What is the output of the program?

❌ ['a', 'b', 'c']
❌ ['c', 'b', 'a']
❌ ['a', 'b', 'c', 'a', 'b', 'c', 'a', 'b', 'c']
❌ ['c', 'b', 'a', 'c', 'b', 'a', 'c', 'b', 'a']
✅ []
❌ Error
❌ None of the mentioned

Explanation:
A expression list[listelements]*N where N is a integer appends N copies of list elements in the original list. If N is a negative integer or 0 output will be a empty list else if N is positive list elements will be added N times to the original list.

What is the true statement about the code snippet?

❌ Class B inherits all the data fields of class A
❌ Class B needs an argument
❌ The data field ‘j’ cannot be accessed by object b
✅ Class B is inheriting class A but the data field ‘i’ in A cannot be inherited

Explanation:
Program ends with error 'B' object has no attribute 'i'.
Reason being that i is initiated with self thus making it a instantiate variable of that class which cannot be inherited by the above way.

What is the output of the code?

❌ {0: 1, 7: 0, 1: 1, 8: 0}
❌ {1: 1, 7: 2, 0: 1, 8: 1}
✅ {0: 0, 7: 0, 1: 1, 8: 1}
❌ KeyError

Explanation:
enumerate() will return a tuple, the loop will have x = (0, 0), (1, 1). Thus D[0] = 0, D[1] = 1, D[0 + 7] = D[7] = 0 and D[1 + 7] = D[8] = 1.
Note:
Dictionary is unordered, so the sequence of the key-value pair may differ in each output.

What is the output of the program?

❌ 0-0-5
❌ 1-2-10
❌ 2-1-5
✅ 2-0-5
❌ 3-1-10
❌ 3-2-6
❌ Error

Explanation:
First off, the * and % have the same operator precedence, so the expression is evaluated from left to right unless parentheses are present. The first expression evaluates to 8 % 3, which leaves a remainder of 2. The second expression is just evaluated left to right since * and % have the same operator precedence, and it reduces to 6 % 3, which is 0. The last expression reduces to 5 * 1, which is 5. Therefore, the output on line 6 is 2-0-5.

What is the output of the code snippet?

❌ False False True True False
❌ False False True True True
❌ True True True True True
❌ True True True True False
❌ True True 0 0 False
✅ True True 3 1 False
❌ True True 3 1 True
❌ Error
❌ None of the above

Explanation:
True: This keyword is used to represent a boolean true. If a statement is true, “True” is printed.
False: This keyword is used to represent a boolean false. If a statement is false, “False” is printed.
None: This is a special constant used to denote a null value or a void. It’s important to remember, 0, any empty container(e.g empty list) does not compute to None.
It is an object of its datatype – NoneType. It is not possible to create multiple None objects and can assign them to variables.
Additionally, in Python, True == 1 and False == 0, as True and False are type bool, which is a subtype of int. When you use the operator +, it is implicitly adding the integer values of True and False.
That's why True + True + True = 1 + 1 + 1 = 3 and True + False + False = 1 + 0 + 0 = 1.

What will be the output of the code?

❌ 0
❌ 1
✅ 10
❌ 20
❌ 50
❌ Error
❌ None of the above

Explanation:
The above function basically calculates the greatest common divisor of 2 numbers recursively.
During 1st call of "solve" function a = 20, b = 50, b % a = 10. During 2nd: a = 10, b = 20, b % a = 0.
Finally during the next call a = 0, b = 10 so value of b (equal to 10) is returned.