What is the output of the program?

❌ [1, 2, 3, 4, 5]
❌ [1, 2, 3, 4, 5, 6]
❌ [2, 3, 4, 5]
✅ [2, 3, 4, 5, 6]
❌ Error will occur
❌ None of the mentioned

Explanation:
The code line “second = first ” creates the shallow copy of the list. It means there will be a single list in memory. The first and second variables are pointed to the same list.
It does not maintain two separate lists, but only one. If you modify using one list variable, it will make the changes in the list for both variables.
If you want to maintain two separate lists for two list objects, you need to create a deep copy of the list.

What is the output of the program?

❌ 2 4
❌ 0 0
✅ 1 2 1 2
❌ -1 -2 -1 -2
❌ Error will occur
❌ None of the mentioned

Explanation:
"a * 2" means, string prints 2 times. "a * 0" means, string is empty.
Any string cannot be negative. Therefore, the string in the 3rd case will not print any word.

What is the result of the code?

❌ 300 400
✅ 100 400
❌ 100 200
❌ 300 200
❌ None of the above
❌ Error

Explanation:
In the above code x is a private variable declared in the class P. Thus value of x cannot be changed in the class C which inherits class P. But y is not a private variable thus its value can be changed.

What is the output of the code?

❌ 1 2 3
❌ 1 3 2
❌ 1 (3, 2)
❌ 1 (2, 3)
✅ 1 {'c': 3, 'b': 2}
❌ 1 {'c': 2, 'b': 3}
❌ Error
❌ None of the above

Explanation:
The code prints '1 {'c': 3, 'b': 2}', because 1 is passed to a by name and the **kargs collects the remaining keyword arguments into a dictionary. We could step through the extra keyword arguments dictionary by key with any iteration tool (e.g., for key in kargs: ...)

What is the output of the code?

❌ [1, 2, 3, 1, 2, 3] and [1, 2, 3, 1, 2, 3]
✅ [1, 2, 3] and [1, 2, 3, 1, 2, 3]
❌ [1, 2, 3, 1, 2, 3] and [1, 2, 3]
❌ [1, 2, 3] and [1, 2, 3]
❌ Error
❌ None of the above

Explanation:
The statement listA = listA * 2 inside the funcA creates a new list instead of modifying the original one.
Whereas the list extend() method modifies the original list.

What is the output of the code?

❌ 'Finally Block!'
❌ 'Index out of bound!'
❌ 'Done!' followed by 'Nothing is wrong!'
❌ 'Nothing is wrong!' followed by 'Finally block!'
✅ 'Done!' followed by 'Nothing is wrong!' followed by 'Finally block'
❌ 'Index out of bound!' followed by 'Finally block'
❌ Error
❌ None of the above

Explanation:
In the above Try block we make a list of total 10 elements by adding 5 times zero and 5 times 10. Thus when we try to find out the element at index 9 no error is raised by Python.
Accordingly, firstly the 'Done!' will be printed. Then 'Nothing is wrong!' will be printed because no excpetion was raised. And then 'Finally block' is printed because finally block is executed in any case.