What will be the output of the code?

✅ __str called
❌ __repr__ called
❌ Error
❌ Nothing is printed

Explanation:
__str __is used for producing a string representation of an object’s value that is most readable for humans

What will be the output of the Python code?

❌ 0 1 2
❌ 0 1 2 0 1 2 0 1 2 …
✅ None None None
❌ None of the mentioned

Explanation:
Variable x takes the values 0, 1 and 2. set.add() returns None which is printed.

What will be the output of the Python code?

❌ 6
❌ 12
✅ 24
❌ Error
❌ None of the mentioned

Explanation:
In the above program r and s are lambda functions or anonymous functions and q is the argument to both of the functions. In first step we have initialized x to 2. In second step we have passed x as argument to the lambda function r, this will return x*2 which is stored in x. That is, x = 4 now. Similarly in third step we have passed x to lambda function s, So x = 4*3. i.e, x = 12 now. Again in the last step, x is multiplied by 2 by passing it to function r. Therefore, x = 24.

What will the Python code return?

❌ 70251
❌ 7
❌ 15
✅ Error
❌ None of the mentioned

Explanation:
list1 contains integers as its elements. Hence these cannot be concatenated to string str1 by simple "+" operand. These should be converted to string first by use of str() function,then only these will get concatenated.

Which statement is correct?

❌ id(a1) and id(a2) will have same value
✅ id(a1) and id(a2) will have different values
❌ Two objects with same value of attribute cannot be created
❌ None of the above

Explanation:
Although both a1 and a2 have same value of attributes,but these two point to two different object. Hence, their id will be different.

What will be the output of the code?

❌ 113
❌ 14
❌ 12
✅ Error
❌ None of the mentioned

Explanation:
As you can see the variable ‘b’ is of type integer and the variable ‘a’ is of type string. Also as Python is a strongly typed language we cannot simply concatenate an integer with a string. We have to first convert the integer variable to the type string to concatenate it with a string variable. So, trying to concatenate an integer variable to a string variable, an exception of type “TypeError” is occurred.

What will be output for the code?

❌ A. Error, the syntax of the invoking method is wrong
❌ B. The program runs fine but nothing is printed
❌ C. 1 0
✅ D. 1 2

Explanation:
In the above piece of code, the invoking method has been properly implemented and hence x=1 and y=2.