What will be the output of the Python code?
❌ Error
❌ 4
❌ Junk value
✅ 1
Explanation: In the code shown above, when we call the function f, a new namespace is created. The assignment x=4 is performed in the local namespace and does not affect the global namespace. Hence the output is 1.
❌ Error
❌ 4
❌ Junk value
✅ 1
Explanation: In the code shown above, when we call the function f, a new namespace is created. The assignment x=4 is performed in the local namespace and does not affect the global namespace. Hence the output is 1.
What is the output of the code?
❌ 2
❌ 4
✅ 5
❌ 6
Explanation:
The slice expression on the right side of the assignment produces the tuple (2, 5, 8):
The assignment is thus equivalent to this compound tuple packing/unpacking assignment: a, b, c = (2, 5, 8)
b is given the value 5.
❌ 2
❌ 4
✅ 5
❌ 6
Explanation:
The slice expression on the right side of the assignment produces the tuple (2, 5, 8):
The assignment is thus equivalent to this compound tuple packing/unpacking assignment: a, b, c = (2, 5, 8)
b is given the value 5.
What will be the output of the code?
✅ __str called
❌ __repr__ called
❌ Error
❌ Nothing is printed
Explanation:
__str __is used for producing a string representation of an object’s value that is most readable for humans
✅ __str called
❌ __repr__ called
❌ Error
❌ Nothing is printed
Explanation:
__str __is used for producing a string representation of an object’s value that is most readable for humans
What will be the output of the Python code?
❌ 0 1 2
❌ 0 1 2 0 1 2 0 1 2 …
✅ None None None
❌ None of the mentioned
Explanation:
Variable x takes the values 0, 1 and 2. set.add() returns None which is printed.
❌ 0 1 2
❌ 0 1 2 0 1 2 0 1 2 …
✅ None None None
❌ None of the mentioned
Explanation:
Variable x takes the values 0, 1 and 2. set.add() returns None which is printed.
What will be the output of the Python code?
❌ 6
❌ 12
✅ 24
❌ Error
❌ None of the mentioned
Explanation:
In the above program r and s are lambda functions or anonymous functions and q is the argument to both of the functions. In first step we have initialized x to 2. In second step we have passed x as argument to the lambda function r, this will return x*2 which is stored in x. That is, x = 4 now. Similarly in third step we have passed x to lambda function s, So x = 4*3. i.e, x = 12 now. Again in the last step, x is multiplied by 2 by passing it to function r. Therefore, x = 24.
❌ 6
❌ 12
✅ 24
❌ Error
❌ None of the mentioned
Explanation:
In the above program r and s are lambda functions or anonymous functions and q is the argument to both of the functions. In first step we have initialized x to 2. In second step we have passed x as argument to the lambda function r, this will return x*2 which is stored in x. That is, x = 4 now. Similarly in third step we have passed x to lambda function s, So x = 4*3. i.e, x = 12 now. Again in the last step, x is multiplied by 2 by passing it to function r. Therefore, x = 24.
What will the Python code return?
❌ 70251
❌ 7
❌ 15
✅ Error
❌ None of the mentioned
Explanation:
list1 contains integers as its elements. Hence these cannot be concatenated to string str1 by simple "+" operand. These should be converted to string first by use of str() function,then only these will get concatenated.
❌ 70251
❌ 7
❌ 15
✅ Error
❌ None of the mentioned
Explanation:
list1 contains integers as its elements. Hence these cannot be concatenated to string str1 by simple "+" operand. These should be converted to string first by use of str() function,then only these will get concatenated.
Which statement is correct?
❌ id(a1) and id(a2) will have same value
✅ id(a1) and id(a2) will have different values
❌ Two objects with same value of attribute cannot be created
❌ None of the above
Explanation:
Although both a1 and a2 have same value of attributes,but these two point to two different object. Hence, their id will be different.
❌ id(a1) and id(a2) will have same value
✅ id(a1) and id(a2) will have different values
❌ Two objects with same value of attribute cannot be created
❌ None of the above
Explanation:
Although both a1 and a2 have same value of attributes,but these two point to two different object. Hence, their id will be different.