public class LargestNumber {
public static void main(String[] args) {
int N = 139;
int D = 3;

int L = 0;

for (int i = N - 1; i >= 0; i--) {
String number = String.valueOf(i);
if (!number.contains(String.valueOf(D))) {
L = i;
break;
}
}

System.out.println("Largest number less than " + N +
" and not containing " + D + " is " + L);
}
}

public class BiggestNumber {

public static void main(String[] args) {

int a = 50, b = 20, c = 40;

if (a > b && a > c)
System.out.println("a is Biggest number");
else if (b > c)
System.out.println("b is Biggest number");
else
System.out.println("c is Biggest number");
}
}

Can use ternary operator also that will be just one line code

public class DuplicateElementsInArray {
public static void main(String[] args) {
//Initialize array
int [] arr = new int [] {1, 2, 3, 4, 2, 7, 8, 8, 3};
System.out.println("Duplicate elements in given array: ");
//Searches for duplicate element
for(int i = 0; i < arr.length; i++) {
for(int j = i + 1; j < arr.length; j++) {
if(arr[i] == arr[j])
System.out.println(arr[j]);
}
}
}
}

public class DuplicateFinder {
public static void main(String[] args) {
int[] arr = {1,2,3,4,5,3,4,7};
for (int i = 0; i < arr.length; i++) {
int element = arr[i];
boolean found = false;
for (int j = 0; j < i; j++) {
found = (arr[i] == arr[j]) ? true : false;
if (found) {
System.out.println("Duplicate element: " + element);
break;
}
}
}
}
}

Same question using ternary operator

Get ready with strings concepts , jsp.

Interface , abstract class

Conceptual knowledge on above topics and also exception handling

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