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#include <iostream>
using namespace std;

// Returns sum of minimum sum subsequence
// such that one of every four consecutive
// elements is picked from arr[].
int minSum(int arr[], int n)
{
int dp[n];
if (n == 1)
return arr[0];
if (n == 2)
return min(arr[0], arr[1]);

if (n == 3)
return min(arr[0], min(arr[1], arr[2]));

if (n == 4)
return min(min(arr[0], arr[1]),
min(arr[2], arr[3]));

dp[0] = arr[0];
dp[1] = arr[1];
dp[2] = arr[2];
dp[3] = arr[3];

for (int i = 4; i < n; i++)
dp[i] = arr[i] + min(min(dp[i - 1], dp[i - 2]),
min(dp[i - 3], dp[i - 4]));

return min(min(dp[n - 1], dp[n - 2]),
min(dp[n - 4], dp[n - 3]));
}

int main()
{
int n;
cin>>n;
int arr[n];
for(int i=0;i<n;i++)
{
cin>>arr[i];
}
cout << minSum(arr, n);
return 0;
}


Paul and peter code 100% working and say thanks to me atleast

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All test cases are passed

It was good. Answers were fast and accurate. Code also all test cases passed 🙌 will recommend you to others.

It was good. Answers were fast and accurate. Code also all test cases passed 🙌 will recommend you to others.

Thanks all test cases passed

Both code sucessfully excuted thank you so much

@codeboss 64 thanks bro for your help.

Unix done thanks brother @codeboss65

Thankyou
All test cases passed for unix and python

Love u bro

Thank you codeboss65 all test cases passed successful

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Thank you bhai for ur help🙏
Thnk u so much for this help
All of the test cases are passed successfully thnk u so much once again
Thnk 🙏

Thanks alot bro
Good work done by you