an exercise in which participants attempt to find text strings, called "flags", which are secretly hidden in purposefully-vulnerable programs or websites.

I can safely say the results of AlphaCode exceeded my expectations. I was sceptical because even in simple competitive problems it is often required not only to implement the algorithm, but also (and this is the most difficult part) to invent it. AlphaCode managed to perform at the level of a promising new competitor. I can't wait to see what lies ahead!

Hi there fellas 👋,
Anyone of you with previous experience in CTFs, oh for those of you who say what the heck is CTF, oh wait a moment we will investigate what they are in no time. But if anyone participated before comment below. .......soon

# Python program implementing Image Steganography
 
# PIL module is used to extract
# pixels of image and modify it
from PIL import Image
 
# Convert encoding data into 8-bit binary
# form using ASCII value of characters
def genData(data):
 
        # list of binary codes
        # of given data
        newd = []
 
        for i in data:
            newd.append(format(ord(i), '08b'))
        return newd
 
# Pixels are modified according to the
# 8-bit binary data and finally returned
def modPix(pix, data):
 
    datalist = genData(data)
    lendata = len(datalist)
    imdata = iter(pix)
 
    for i in range(lendata):
 
        # Extracting 3 pixels at a time
        pix = [value for value in imdata.next()[:3] +
                                imdata.next()[:3] +
                                imdata.next()[:3]]
 
        # Pixel value should be made
        # odd for 1 and even for 0
        for j in range(0, 8):
            if (datalist[i][j] == '0' and pix[j]% 2 != 0):
                pix[j] -= 1
 
            elif (datalist[i][j] == '1' and pix[j] % 2 == 0):
                if(pix[j] != 0):
                    pix[j] -= 1
                else:
                    pix[j] += 1
                # pix[j] -= 1
 
        # Eighth pixel of every set tells
        # whether to stop ot read further.
        # 0 means keep reading; 1 means thec
        # message is over.
        if (i == lendata - 1):
            if (pix[-1] % 2 == 0):
                if(pix[-1] != 0):
                    pix[-1] -= 1
                else:
                    pix[-1] += 1
 
        else:
            if (pix[-1] % 2 != 0):
                pix[-1] -= 1
 
        pix = tuple(pix)
        yield pix[0:3]
        yield pix[3:6]
        yield pix[6:9]
 
def encode_enc(newimg, data):
    w = newimg.size[0]
    (x, y) = (0, 0)
 
    for pixel in modPix(newimg.getdata(), data):
 
        # Putting modified pixels in the new image
        newimg.putpixel((x, y), pixel)
        if (x == w - 1):
            x = 0
            y += 1
        else:
            x += 1
 
# Encode data into image
def encode():
    img = input("Enter image name(with extension) : ")
    image = Image.open(img, 'r')
 
    data = input("Enter data to be encoded : ")
    if (len(data) == 0):
        raise ValueError('Data is empty')
 
    newimg = image.copy()
    encode_enc(newimg, data)
 
    new_img_name = input("Enter the name of new image(with extension) : ")
    newimg.save(new_img_name, str(new_img_name.split(".")[1].upper()))
 
# Decode the data in the image
def decode():
    img = input("Enter image name(with extension) : ")
    image = Image.open(img, 'r')
 
    data = ''
    imgdata = iter(image.getdata())
 
    while (True):
        pixels = [value for value in imgdata.next()[:3] +
                                imgdata.next()[:3] +
                                imgdata.next()[:3]]
 
        # string of binary data
        binstr = ''
 
        for i in pixels[:8]:
            if (i % 2 == 0):
                binstr += '0'
            else:
                binstr += '1'
 
        data += chr(int(binstr, 2))
        if (pixels[-1] % 2 != 0):
            return data
 
# Main Function
def main():
    a = int(input(":: Welcome to Steganography ::\n"
                        "1. Encode\n2. Decode\n"))
    if (a == 1):
        encode()
 
    elif (a == 2):
        print("Decoded Word :  " + decode())
    else:
        raise Exception("Enter correct input")
 
# Driver Code
if name == 'main' :
 
    # Calling main function
    main()