kenapa guna resistance wire dalam electrical cooker?
➡️sebab resistance wire resists electric current to produce heat
➡️ resistance wire perlu
•coiled
•high resistivity
•nichrome material
so the heating element will lasts longer and only need a short period of time to heat up the food
➡️sebab resistance wire resists electric current to produce heat
➡️ resistance wire perlu
•coiled
•high resistivity
•nichrome material
so the heating element will lasts longer and only need a short period of time to heat up the food
zaira
happened to bump onto this question and got confused sebab dlm textbook dia explain induction cooker and yes induction cooker and electrical cooker aren't the same thing even though both are electrical-powered and lazimnya look just the same. •induction cooker…
this is strictly NOT an exact way to answer the question ‼️
Siapa ambik subjek sains sukan? Subjek yang entahla..sepertinya dilupakan😂
👍1
Mesti subjek ni jadi subjek back up A dalam sijil kan?
Kita pun begitu🙈
Kita pun begitu🙈
Forwarded from Amazing Physics🥰
✨Road to SPM 2024✨
Chapter 1 (F5): Daya & Gerakan II (Force & Motion II)
Daya geseran: 150 N
Daya selari dgn satah:
= mg sin30
= 1000 (0.5)
= 500 N
Daya tarik: 850 N
Daya paduan:
= daya tarik - (daya geseran + daya selari dgn satah)
= 850 - (150 + 500)
= 200 N
Jawapan: A
📖SPM 2021
🇵🇸amazingPhysics🇵🇸
Chapter 1 (F5): Daya & Gerakan II (Force & Motion II)
Daya geseran: 150 N
Daya selari dgn satah:
= mg sin30
= 1000 (0.5)
= 500 N
Daya tarik: 850 N
Daya paduan:
= daya tarik - (daya geseran + daya selari dgn satah)
= 850 - (150 + 500)
= 200 N
Jawapan: A
📖SPM 2021
🇵🇸amazingPhysics🇵🇸
❤2
Forwarded from Amazing Physics🥰
✨Road to SPM 2024✨
Chapter 2 (F5): Tekanan (Pressure)
🇵🇸amazingPhysics🇵🇸
Chapter 2 (F5): Tekanan (Pressure)
🇵🇸amazingPhysics🇵🇸
zaira
✨Road to SPM 2024✨ Chapter 2 (F5): Tekanan (Pressure) 🇵🇸amazingPhysics🇵🇸
ingat.. principal/law huruf besar ya
Forwarded from Amazing Physics🥰
✨Road to SPM 2024✨
Chapter 5 (F5): Elektrik (Electric)
E = V + Ir
E = I(R + r)
E = 0.2(4.5 + 0.5)
E = 1 V
Tiada jawapan sebab label arus dalam rajah salah
Soalan sebenar I = 1.2 A
E = V + Ir
E = I(R + r)
E = 1.2(4.5 + 0.5)
E = 6 V
📖SPM 2023
🇵🇸amazingPhysics🇵🇸
Chapter 5 (F5): Elektrik (Electric)
E = V + Ir
E = I(R + r)
E = 0.2(4.5 + 0.5)
E = 1 V
Tiada jawapan sebab label arus dalam rajah salah
Soalan sebenar I = 1.2 A
E = V + Ir
E = I(R + r)
E = 1.2(4.5 + 0.5)
E = 6 V
📖SPM 2023
🇵🇸amazingPhysics🇵🇸
Forwarded from Amazing Physics🥰
F5 CH7 QUANTUM PHYSICS (question).pdf
2.9 MB
✨Road to SPM 2024✨
Revision:
PAPER 1 (F5) by chapter
🇵🇸amazingPhysics🇵🇸
Revision:
PAPER 1 (F5) by chapter
🇵🇸amazingPhysics🇵🇸
👍1
Forwarded from Amazing Physics🥰
✨Road to SPM 2024✨
Chapter 6 (F4): Cahaya & Optik
📸Panjang fokus bagi kamera
panjang fokus bertambah,
Sudut pandangan berkurang,
Saiz imej bertambah
Pembesaran linear bertambah
-----------------------------------
📸The focal length of the camera
focal length increases,
The angle of view decreases,
Size of image increases
Linear magnification increases
🇵🇸amazingPhysics🇵🇸
Chapter 6 (F4): Cahaya & Optik
📸Panjang fokus bagi kamera
panjang fokus bertambah,
Sudut pandangan berkurang,
Saiz imej bertambah
Pembesaran linear bertambah
-----------------------------------
📸The focal length of the camera
focal length increases,
The angle of view decreases,
Size of image increases
Linear magnification increases
🇵🇸amazingPhysics🇵🇸
👍1