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Computer Science student and software developer focused on building impactful products, exploring AI, and solving real-world challenges with technology.
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GM Fam🌅
The next point is O(n): If an operation has an O(n) (pronounced ‘O of N’), what this means is that, as ’n’ increases, so does the amount of operations needed to complete the problem. This is simple to understand, cuz it’s an entirely linear relationship. Here O(n) code looks like
def findNum(n):
for i in range(n):
print(i)

findNum(5)

To say it's linear Big O notation: Look at there is only one for loop it's not nested. when our n = 5 the time to complete this operation is also increase, and if n = 100 the time to complete this operation is also further increases, 👉🏾that's why O(1) is preferably than O(n). and then the graph of O(n) is👇
The Diagram of O(n) or Linear algorithm:👆
SamiTech Code pinned «The next point is O(n): If an operation has…»
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I wish u're doing well and we'll keep learning without any stress💪Thanks for being with me🙏
What we've to understand is: An O(n) operation inside of an O(n) operation is an O(n * n) operation. In other words, O(n ²). This is the slowest and least efficient, and therefore the least desirable Big O Expression when considering time complexity. Here eg; of O(n ²)
def calc(n, m):
for i in range(n):
for j in range(m):
print(i, j)
calc(4, 5)

Since it's nested loop it's O(n ²) algorithm,
Diagram of O(n ²) 👆
List: List is a built-in dynamic array which can store elements of different data types. It is an ordered collection of item, that is elements are stored in the same order as they were inserted into the list. List stores references to the objects (elements) rather than storing the actual data itself.
b = [2, 4, "word", True]
print(b)

a = list((1, 4, 3.2, 'banana', 5))
print(a)
b = list('STC')
print(b)
# Creating list with repeated elements
# we can use * for repeated items
a = [3] * 3
print(a)

# Accessing list elements
# elements in a list are accessed using indexing.
# Python indexes start at 0
a = [12,13,15,18]
print(a[0])
print(a[1])
print(a[2])
print(a[1:-1])
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Key concept we've to know👇
#Adding elements into list
"""we can add elements to a list using the following methods:
append(): add at the end of the list
extend(): adds multiple elements to the end of the list
insert(): adds at a specific position
clear(): removes all items"""
x = []
x.append(15)
x.append(2)
x.append(3)
print("After append:", x)

x.insert(0, 1)
print("After insert", x)

x.extend([4, "list", True])
print("After extend", x)

x.clear()
print("After clear:", x)

Don't worry this course might be confusion, however what we learn in this course is very interesting and important! you've to use different resourses, we're on our way to understand, analysis, solve problem, but we must've to consistence 💪
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Good Morning Fam🌅
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Python list looks like this👆 and the first box is index of 0 then 1,2,3,4 to understand list of index we can calculate like this index = length - 1. eg; a[0] = 10, a[1] = 20, a[2] =' GfG', a[3] = 40, a[4] = 'True' questions what's a[-1] your answer in the comment sections↩️
here I've prepared the topics we'll going to focus one by one
DATA STRUCTURE:
Array DS, String in DS, Set, Dictionary, Recursion, Linked List DS, Stack DS, Queue DS, hash in DS, Tree DS, Heap in DS, Graph DS, Trie DS

ALGORITHMS: Searching Algorithms, Sorting Algorithms, Tree Traversal, Graph Algorithms,

PROBLEM SOLVING TECHNIQUES: Two Pointers, Sliding Window, Recursion, Dynamic Programming(DP), Greedy

May be this course takes time don't worry we'll learn from each others, ask questions, and share info. Let's go together and become mastered in DSA💪
Searching Algorithm: There are 2 types of SA 1. Linear Search & 2. Binary Search from them here; 1. Linear Search in diagram in easy way👆 let me know what you've understand from this 👀
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SamiTech Code pinned «here I've prepared the topics we'll going to focus one by one DATA STRUCTURE: Array DS, …»
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Good Morning Guys🌄
We'll not stop our learning journey to ML
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Array Search: Given an array, arr[] of n integers, and an integer element x, find whether element x is present in the array. Return the index of the first occurrence of x in the array, or -1 if it doesn't exist
input: arr[] = [1,2,3,4], x = 3 output: 2 Explanation: For array [1, 2, 3, 4], the element to be searched is 3. Since 3 is present at index 2, the output is 2. Input: arr[] = [10, 8, 30], x = 6
Output: -1
Explanation: The element to be searched is 6 and it is not present, so we return -1.

This's Linear Search O(n)👆🏻 Try to think this problem before jumping into code🤔