input: arr[] = [1,2,3,4], x = 3 output: 2 Explanation: For array [1, 2, 3, 4], the element to be searched is 3. Since 3 is present at index 2, the output is 2. Input: arr[] = [10, 8, 30], x = 6
Output: -1
Explanation: The element to be searched is 6 and it is not present, so we return -1.

class Solution:
def search(self, arr, x):
# Code with the logical error fixed
for n in range(len(arr)):
if arr[n] == x:
return n # Return the index if found

# Only return -1 after the entire loop has completed,
# meaning the element was not found in the entire list.
return -1

arr = [1, 2, 3, 4]
x = 3
# Create an instance of the class to call the instance method
sol_instance = Solution()
print(sol_instance.search(arr, x))

Unsorted Lists:

When we have an unsorted array or list, linear search is most commonly used to find any element in the collection.
Small Data Sets: Linear Search is preferred over binary search when we have small data sets with
Searching Linked Lists: In linked list implementations, linear search is commonly used to find elements within the list. Each node is checked sequentially until the desired element is found.
Simple Implementation: Linear Search is much easier to understand and implement as compared to Binary Search or Ternary Search.

👆🏻Understanding this process is important in binary search. So try to think about it how we can search for 7 after you understand this you'll gain different between binary & linear search. In addition you can say which is more efficient and not😁 Don't be hesitate this course it's truly interesting👌

2️⃣POINTER TECHNIQUE Still now on studying...🧑‍💻

after then chatgpt gives me this👇 First: Forget the Name “Two Pointer”
Don’t think “two pointer technique”.
Think only this:
“How can I look at two places in the array at the same time and move intelligently?”
That’s it.

Easy way to understand Two-Pointer: Step 1: Starts from human way: imagine this array [1, 3, 4, 6, 8, 10] Question:
👉 “Is there a pair that adds up to 11?” How beginner think to get 11 the same as true it follows this 1 + 3, 1 + 4, 1 + 6 ... Too many checks😇 Your brain already feels this's wasteful Step 2: In other way (this's where two pointer is important) : If I add smallest + largest, what happens? 1(smallest) + (largest)10 = 11 👆🏻This thinking is two pointer Step 3: Why moving pointer make sense? Suppose target = 9 here 1 = L and 10 = R CASE 1: 1 + 10 = 11 (too big) Question:
👉 Should you increase 1 or decrease 10? — 1 is already smallest, but big sum comes from 10 So move right pointer left 1 + 8 = 9 ✅ 👉🏽Two Pointer is not trick it's just using position + logic to avoid waste.

You're given this sorted array: [2, 3, 5, 7, 11, 15], target sum = 10 your task explain👇: 1.Which two numbers would you look at first?
2.What is their sum?
3.Is the sum too big, too small, or exact?
4.Which number would you change and why? 👉🏽Key point: this thinking foster our thinking capacity. Therefore, just go ahead and try to explain it by your own word.👉🏽 No need to code.🧑‍💻

If we're given the array of sorted list and duplicated elements what shall do?👆🏻 In general the logic skip the duplicated and take the unique then it compared with the other element to get the target. In this process target is sum of the two numbers. So this image is solving for what we're talking about.👆🏻