Python Codes Basic to Advance
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Python Codes Basic to Advance

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Forwarded from Cᴏᴅᴇs Sɴɪᴘᴘᴇᴛs (</> ᴍᴜᴋᴇsʜ </>)
Top 5 Coding Challenge Platforms for Programmers 👩‍💻🚀

1. LeetCode
   - URL: https://leetcode.com
   - Description: Enhance problem-solving skills with a vast collection of coding challenges on LeetCode.

2. HackerRank
   - URL: https://www.hackerrank.com
   - Description: HackerRank offers diverse coding challenges for algorithm, data structure, and language proficiency improvement.

3. CodeSignal
   - URL: https://codesignal.com
   - Description: CodeSignal provides coding challenges and assessments to enhance coding skills for interviews and practice.

4. Codewars
   - URL: https://www.codewars.com
   - Description: Codewars engages developers in creative problem-solving through kata challenges, fostering skill development.

5. Exercism
   - URL: https://exercism.io
   - Description: Exercism offers coding exercises in various languages, providing mentorship and community support.

All the best 👍👍

Jᴏɪɴ ᴜs :- @CodesSnippet
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Kaun jeetega?
Anonymous Poll
62%
BJP(NDA)
38%
Congress(INDI)
Python Oops challenge

What is the output of following Python Code?
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Jᴏɪɴ ᴜs :- @Python_Codes_Pro

Support group :- @python_group_pro
1
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Rotate character using python.

import time
rotation_chars = ['-', '\\', '|', '/']
while True:
for char in rotation_chars:
print(char, end='\r')
time.sleep(0.5)

Language: Python
Jᴏɪɴ ᴜs :- @CodesSnippet
2
Convert Image to text

import pytesseract as t
from PIL import Image

img = Image.open("photo.jpg")
text = t.image_to_string(img)

print(text)


Language: Python

Jᴏɪɴ ᴜs :- @Python_Codes_Pro

Support group :- @python_group_pro
2
1
Convert Animated Gif to video

from os import remove,popen
import subprocess

def sprocess(a, b="utf-8"):
p = subprocess.Popen(a,shell=True,stdout=subprocess.PIPE, stderr=subprocess.PIPE).communicate()
return str(p[0].decode(b)+p[1].decode(b))

vid = await message.reply_to_message.download()

print(sprocess("ffmpeg -y -i '" + vid + "' -map_metadata -1 s.mp4"))

durasi = popen("ffprobe -i '" + vid + "' -show_entries format=duration -v quiet -of csv='p=0'").read()

await message.reply_video(video="s.mp4")

remove("s.mp4")
remove(vid)


Sample response https://t.me/the_support_chat/146439
1👍1
y, z = 10, 15
y *= y + z
# What is the value of y. Explain How?
Anonymous Quiz
9%
10
7%
15
26%
25
21%
115
26%
250
5%
None of the above
6%
Show me the answer
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Which of the following operators has the lowest precedence?
Anonymous Quiz
26%
not
16%
and
19%
**
21%
+
19%
%
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Comment your answer
Comment your answer
Convert Timestamp to Indian Time Zone Using Python.

import datetime
import pytz

def convert_timestamp_to_ist(timestamp: int) -> str:
utc_date_time = datetime.datetime.utcfromtimestamp(timestamp)

utc_time_zone = pytz.timezone('UTC')
utc_aware_datetime = utc_time_zone.localize(utc_date_time)

ist_time_zone = pytz.timezone('Asia/Kolkata')
ist_aware_datetime = utc_aware_datetime.astimezone(ist_time_zone)

formatted_date = ist_aware_datetime.strftime('%A, %Y-%m-%d %H:%M:%S')

return formatted_date

# print(convert_timestamp_to_ist(1717000920))


Output:
  Wednesday, 2024-05-29 22:12:00
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Guess the Output???
def foo(a,b=10,c=17):

return a+b+c

print(foo(a=1,b=8))
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Check either string is an
Anagram or not?

An anagram is a word or phrase that is created by rearranging the letters of another word or phrase.

def is_anagram(str1,str2):

return sorted(str1)==sorted(str2)

print(is_anagram("astronomer","moonstarer"))

#Output : True
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X=['h', 'i']
Y=['i','h']
print(X==Y)
Anonymous Quiz
52%
True
48%
False
X=['h', 'i']
Y=sorted(['i','h'])
print(X==Y)
Anonymous Quiz
61%
True
39%
False
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Task:
You have to create a program where a list of numbers is given and a number of rotation is given. Now you to bring last number of list in front and swift each number to the right. Do this till the given number of rotation.

Sample :-
input - [1,2,3,4] , 2
output - [4,1,2,3] -> [3,4,1,2]

Good luck!
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print(len(34))
Anonymous Quiz
17%
1
44%
2
40%
TypeError
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y=lambda x: x*False
print(y(5))
Anonymous Quiz
25%
Error
34%
0
31%
5
9%
None