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Comparing tuples

A comparison operator in Python can work with tuples.
The comparison starts with a first element of each tuple. If they do not compare to =,< or > then it proceed to the second element and so on.
It starts with comparing the first element from each of the tuples
Let’s study this with an example-

#case 1

a=(5,6)
b=(1,4)
if (a>b):print("a is bigger")
else: print("b is bigger")

#case 2

a=(5,6)
b=(5,4)
if (a>b):print("a is bigger")
else: print ("b is bigger")

#case 3

a=(5,6)
b=(6,4)
if (a>b):print("a is bigger")
else: print("b is bigger")

Case1: Comparison starts with a first element of each tuple. In this case 5>1, so the output a is bigger

Case 2: Comparison starts with a first element of each tuple. In this case 5>5 which is inconclusive. So it proceeds to the next element. 6>4, so the output a is bigger

Case 3: Comparison starts with a first element of each tuple. In this case 5>6 which is false. So it goes into the else block and prints “b is bigger.”

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Python OOP : Object Oriented Programming in Python

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Using tuples as keys in dictionaries
Since tuples are hashable, and list is not, we must use tuple as the key if we need to create a composite key to use in a dictionary.

Example: We would come across a composite key if we need to create a telephone directory that maps, first-name, last-name, pairs of telephone numbers, etc. Assuming that we have declared the variables as last and first number, we could write a dictionary assignment statement as shown below:

directory[last,first] = number

Inside the brackets, the expression is a tuple. We could use tuple assignment in a for loop to navigate this dictionary.

for last, first in directory:
print first, last, directory[last, first]

This loop navigates the keys in the directory, which are tuples. It assigns the elements of each tuple to last and first and then prints the name and corresponding telephone number.

Tuples and dictionary

Dictionary can return the list of tuples by calling items, where each tuple is a key value pair.

a = {'x':100, 'y':200}
b = list(a.items())
print(b)

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