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βœ…Guys i can share answers fast if you share our channel answers screebshots to large groups
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TCS Exam 10 AM Mrng PLEASE HELP

Numerical Ability
1. 18.7
2. 2+√3
3.7.14
4. 11
5. 210
6. 4.89
7. 543218
8. 143.82
9. 5 5/7
10.96
11.44
12.37/2
13.210%
14.1.570
15. 62
16. 3 Days
Telegram -
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Forwarded from Off Campus Job Update
Tcs NQT Answers 10 AM

Verbal Ability
❀️❀️❀️

1. D
2. B
3. B
4. B
5. RP
6.

Add your Answer in this
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Forwarded from Off Campus Job Update
Tcs NQT Answers 10 AM

Verbal Ability
❀️❀️❀️

1. D
2. B
3. B
4. B
5. RP
6. B
7. B
8. Parity

Add your Answer in this
https://t.me/Coding_solution_0
Forwarded from Off Campus Job Update
Daily Off Campus Job UpdatesπŸš€πŸš€

Join Now πŸ’―

https://t.me/offcampusjobs_0
https://t.me/offcampusjobs_0
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🚢Hurry Up ,few enrollment left
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Join this for IRA Exam
πŸ“›πŸ“›πŸ“›
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🎯Cognizant- Infra Off Campus

Post Name: Graduate Trainee/Engineer Trainee
Salary : β‚Ή 2,52,000.00 – β‚Ή 4,00,000.00 per Annum

*Apply link:* https://jobforfreshar.in/index.php/cognizant-infra/

JOIN Us For More❀️❀️
https://t.me/offcampusjobs_0
Tech Mahindra Off Campus | πŸŽ–2020/21 Batch | πŸ’°3.5LPA

⚠️ Deadline - 23rd Feb
registration.techmahindra.com/Candidate/Instructions.aspx

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Wipro Solution Available HereπŸš€πŸš€
https://t.me/Coding_solution_0
https://t.me/Coding_solution_0
Forwarded from Off Campus Job Update
def getprime(n):
sum = 0
for digit in str(n):
num=int(n)

if num > 1:
for i in range(2, int(num/2)+1):
if (num% i) == 0:
break
else:
sum += int(num)

Return sum


n = input()
Print (getprime(n))

Wipro Solution Available HereπŸš€πŸš€
https://t.me/Coding_solution_0
https://t.me/Coding_solution_0
Forwarded from Off Campus Job Update
num = 6172975
reversed_num = 0

while num != 0:
digit = num % 10
reversed_num = reversed_num * 10 + digit
num //= 10

print("Reversed Number: " + str(reversed_num))

Wipro Solution Available HereπŸš€πŸš€
https://t.me/Coding_solution_0
https://t.me/Coding_solution_0
Forwarded from Off Campus Job Update
int main() {
char s[100];
int i;
printf("\nEnter a string : ");
gets(s);
for (i = 0; s[i]!='\0'; i++) {
if(s[i] >= 'a' && s[i] <= 'z') {
s[i] = s[i] - 32;
}
}
printf("\nString in Upper Case = %s", s);
return 0;
}

Warehouse Code

Wipro Solution Available HereπŸš€πŸš€
https://t.me/Coding_solution_0
https://t.me/Coding_solution_0
Forwarded from Off Campus Job Update
IRA
Anonymous Poll
65%
Python
35%
Java
Forwarded from Off Campus Job Update
PYTHON
========
1.Robotics
2.True
3.all of the above
4. Value
5. Inexpensive
6. 13 4
7. option B
8. A&b
9. Prioritize.....
10. Interest level of the users
11. D
12. A
13. B
14.C
15.c
16.b
17. Inner
18. B
19.c
20.B
21.A
22. B
23. B
24. D
25. B
26. A
27. B
28. apple
29. A
30. C
31. A
32. B
33. A
34. C
35. B
36. Error
37. n
38. A
39. A
40. A
41. 5
42. [('123', 'Ayansh'), ('125', 'Aadil'), ('126', 'Barkha')]
43. HELLO
44. [76,54,99]
45. Error
46. {3,a}
47. b
48. a
49. 1
50. 3210.

https://t.me/Coding_solution_0
Forwarded from Off Campus Job Update
Anyone have this unix code
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*Only few seats remain*!!
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Last date for the registration- 27th Feb
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Job Job Job Updates πŸ“£
For 2021 and 2022 batch
Lot of Job Opportunity ❀️


https://t.me/offcampusjobs_0
https://t.me/offcampusjobs_0
Forwarded from Off Campus Job Update
X=input()
Y=input()
If y in x:
Print ("Yes")
Else:
Print ("No")
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https://t.me/Coding_solution_0
https://t.me/Coding_solution_0