# Funktsiyani to'ldiring, shunda u o'ziga berilgan uchta
# ballning o'rtacha qiymatini topadi va shu baho bilan bog'liq
# harf qiymatini qaytaradi.


# Numerical Score Letter Grade
# 90 <= score <= 100 'A'
# 80 <= score < 90 'B'
# 70 <= score < 80 'C'
# 60 <= score < 70 'D'
# 0 <= score < 60 'F'
def get_grade(s1, s2, s3):
if 0<=s1<60:
return "F"
if 60<=s1<70:
return "F"
if 70<=s1<80:
return "F"
if 80<=s1<90:
return "F"
if 90<=s1<100:
return "F"

# Berilgan massivning barcha raqamlarini yig'ing
# # ( cq. list ), eng yuqori va eng past elementdan tashqari
# # (indeks bo'yicha emas, qiymat bo'yicha! ).

# # Bir xil qiymatga ega bo'lgan bir nechta element bo'lsa
# # ham, mos ravishda eng yuqori yoki eng past element har
# # bir chekkada bitta elementdir.
# l=[1,2,3,4,5,6,7,8,9]
# s=sum(l)-(max(l)+min(l))
# print(s)

# Qahramon o'z vazifasini bajarish uchun qasrga ketmoqda.
# Biroq, unga qasr bir nechta kuchli ajdarlar bilan
# o'ralganligini aytishdi! Har bir ajdaho mag'lub bo'lish
# uchun 2 ta o'q oladi, bizning qahramonimiz qancha o'q olib
# yurishi kerakligini bilmaydi. Agar u ma'lum miqdordagi o'qni
# ushlab, boshqa ma'lum miqdordagi ajdarlar bilan jang qilish
# uchun oldinga siljiydi deb faraz qilsak, u omon qoladimi?

# Ha bo'lsa rost, aks holda noto'g'ri deb qaytaring :)
x=int(input("ajdarlar soni="))
n=int(input("oqlar son="))
if n>=2**x:
print("rost")
else:
print("Yolg'on")

# Massivni qaytaring, bunda birinchi element musbat sonlar soni,
# ikkinchi element esa manfiy sonlar yig‘indisidir.

l=[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, -11, -12, -13, -14, -15]
# , siz [10, -65] ni qaytarishingiz kerak.

n=0
s=0
for i in range(len(l)):
if l[i]>0:
n+=1

else:
s+=l[i]

print(n,"musbat elementlari soni")
print(s,"manfiy elementlari yig'indisi")

# Ta'tilda sayohat qilish uchun sizga ijara mashinasi kerak bo'ladi.
# \Avtomobil ijarasi menejeri sizga yaxshi takliflar beradi.

# Har kuni mashina ijarasi 40 dollar turadi.
# Agar siz mashinani 7 yoki undan ortiq kunga ijaraga olsangiz,
# jami 50 dollar chegirma olasiz. Shu bilan bir qatorda, agar siz
# mashinani 3 yoki undan ortiq kunga ijaraga olsangiz, jami 20 AQSh
# dollari miqdorida chegirma olasiz.

# Turli kunlar uchun umumiy miqdorni ko'rsatadigan kodni yozing(d).
n=int(input("car="))
d=int(input("day="))
if d<7 and n<3:
s=40*d*n
print("Jami:",s)
if d>7 and n<3:
s=40*d*n-50
print("Jami:",s)
if d>7 and n>3:
s=40*d*n-70
print("Jami:",s)
if d<7 and n>3:
s=40*d*n-20
print("Jami:",s)

# Oy 1 dan 12 gacha butun son sifatida berilgan bo'lsa,
# u butun son sifatida yilning qaysi choragiga tegishli
# \ekanligini qaytaring.

# Masalan: 2-oy (fevral), birinchi chorakning bir qismi;
# 6-oy (iyun), ikkinchi chorakning bir qismidir; va 11-oy (noyabr),
# to'rtinchi chorakning bir qismidir.

# Cheklov:

# 1 <= oy <= 12

n=int(input(" Nechinchi oy="))
if 1<=n<=3:
print("yilning 1- choragi")
if 4<=n<=6:
print("yilning 2- choragi")
if 7<=n<=9:
print("yilning 3- choragi")
if 10<=n<=12:
print("yilning 4- choragi")
else:
print("oy noto'g'ri kiritilgan")

# 1-vazifa
# n=input("n=")
# s=0

# n=int(n)
# try:
# for i in range(0,n+1):
# s+=n
# print(s)
# except:
# print('Butun son kiriting')
# # 2- vazifa

# n=int(input('n='))
# l=[1,2,3,4,45,7,8,99,97]
# try:
# print(l[n])
# except IndexError:
# print('indexda xatolik!')


# 3-vazifa


# l={"apple":"olma", "banana":"banan","apricos":"o'rik"}
# key=" vino"
# try:
# print(f'meva turi: {l[key]}')
# except KeyError:
# print("Bunday kalit mavjud emas")

# 4-vazifa
# cars={"car1":'mercedes','car2':" Bmw", "car3": 'Ferrari'}
# key='car4'
# try:
# print(f' men yoqtirgan moshina {cars[key]}')
# except KeyError:
# print("keyda xatolik bor")
# 5-vazifaa
# x=float(input('x='))
# y=float(input('y='))
# try:
# d=(x*y)/(x-y)
# print(f'natija {d}')
# except ZeroDivisionError:
# print(" 0 ga bo'lish mumkin emas")

# 6- vazifa

# import math
# x=float(input("x="))
# try:
# a=math.sqrt(x)
# print(a)
# except:
# print('manfiy sondan ildiz chiqmaydi')

# 7-vazifa
# l=[13,45,6,34,64,2,45,6,32,134,5]
# n=int(input("n="))
# m=int(input("m="))
# try:
# print(l[n-1]+l[m-1])
# print(l[m-1]-l[m-1])
# except IndexError:
# print(" Iindexni xato kiritdiz")

#8-vazifa
# x=input('x=')
# try:
# x=float(x)
# a=x**2
# print(a)
# except:
# print('son xato kiritildi')

# 9-vazifa
# n=float(input("n="))
# m=float(input("m="))
# import math
# try:
# A=m*n/(math.sin(n)-math.cos(m))
# print(A)
# except ZeroDivisionError:
# print(" m va n lar 45 gradus va unga karrali burchakka teng bo'lishi mumkin emas")

# 10- vazifa
# yosh=input("Yoshizni kiriting ")

# try:
# yosh=int(yosh)
# print(f'{2023-yosh}-yilda tug\'ilgansiz')
# except ValueError:
# print('Yosh xato kiritildi')