Nature representation of market monopoly😁

Thats why you rarely see small businesses (pigeons) in Dublin

Well well well. So I am again looking for new country?

I would be okay with waiting till citizenship even for 10-15 years in Ireland as I really like country and people here, but it is not easy/or even not possible to renew passport for some men from Ukraine.

Fucking shit. Gov didn’t accept this as part of the law yet, but overall - can be very bad sign for me. Cause I wouldn’t fit 8 years window. And then Idk, Argentina probably is the next station😅 or international refugee living in the tent.

Thanks folks, unexpectedly many people helped with some info about that, thank you❤️

Today, something like 20:30 UTC+1 - stream marathon again.

In the beginning we will solve problem that was really asked in one big tech company recently (somebody has shared with me)

10 mins

5/16

https://www.youtube.com/live/lGO5Wjy18bw?is=3ynvfnAG4RybpFN-

#leetcode #stream

For those who are on the stream:

https://algo.monster/liteproblems/2534

from collections import deque

def time_taken_to_cross_the_door(arrival: list[int], state: list[int]) -> list[int]:
    entering = deque()
    exiting = deque()
    doorstate = 0
    
    t = arrival[0]
    person = 0
    res = [0] * len(arrival)
    while person < len(arrival) or entering or exiting:
        if person < len(arrival) and t < arrival[person] and len(entering) == len(exiting) == 0:
            t = arrival[person]
            doorstate = 0
            continue
        elif person < len(arrival) and t == arrival[person]:
            while person < len(arrival) and arrival[person] == t:
                if state[person] == 1:
                    exiting.append(person)
                else:
                    entering.append(person)
                person += 1
        
        competitive = len(entering) > 0 and len(exiting) > 0
        
        if not competitive:
            if entering:
                res[entering.popleft()] = t
                doorstate = 1   
            else:
                res[exiting.popleft()] = t
                doorstate = 2
        else:
            if doorstate == 0 or doorstate == 2:
                p = exiting.popleft()
                res[p] = t
                doorstate = 2
            elif doorstate == 1:
                p = entering.popleft()
                res[p] = t
                doorstate = 1            
                    
        t += 1
    
    return res

if __name__ == "__main__":
    arrival = [int(x) for x in input().split()]
    state = [int(x) for x in input().split()]
    res = time_taken_to_cross_the_door(arrival, state)
    print(" ".join(map(str, res)))

This is the q that was recently asked one guy from here in Bigtech (very famous, but cannot say which one due to nda)

The guy solved it in 25 mins😅😅😅

I did in 1 hour 15 mins

Daily 383d day streak

A bit tough problem, but not enough to be hard, but it has a pattern, so I would still recommend.

https://leetcode.com/problems/lexicographically-smallest-permutation-greater-than-target/description/?envType=daily-question&envId=2026-08-27

#daily #medium #pattern

From now on - please call me sensei

IMHO, wdyt?

Burnout therapy. Just before training I wanted to resign. Now I even want to work a bit.

Lately it was first time for past 8 years (whole career) that I wanted to take vacation.
But I literally cannot, because manager nicely hinted that I should be around due to some important thing, and also I should deliver stuff noone else knows how to deliver on time😅

Remember, if you cannot take single day off, cause there is no one else that can take it over - this is huge redflag.

In Microsoft you can safely die, and it will be alright. Generally there are at least 2 engineers per feature who have knowledge.

Quick food and I start the stream, +- in 20

6/16

https://www.youtube.com/watch?v=S0t_gvOFplo

#leetcode #stream

Daily 384 day streak

For me - seems very complicated and I have to skip such long/hard problems while we are doing Leetcode marathon. But it has pattern, so I cannot say skip, as well as I cannot say musthave.

https://leetcode.com/problems/lexicographically-smallest-palindromic-permutation-greater-than-target/description/?envType=daily-question&envId=2026-08-28

#daily #hard #pattern

10 minutes and we go leetcode marathon

Come and join I will do small announcement, and then leave. I know it is boring to watch somebody struggling with leetcode. So I understand.

It is only for duration of marathon, and then I will switch to regular content: networks, system design and finally will finish Prague -> Dublin relocation