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C_Language_Coding

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C_Language_Coding

1.33K subscribers

C_Language_Coding

Hello guyzz,🙏

Want to learn coding?

If your basic concept is strong then you can easily switch to any programming language efficiently.

This awesome channel on telegram will serve you C language program from basic to advance in a serial order that help you in crack any examination in effective way .

Check out this incomparable channel on telegram for all update and subscribe them to understand the concept of C language nd get a job in top MNC.

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C_Language_Coding
This channel will serve you C language program from basic to advance in a serial order that help you in understand the basic and crack any IT examination in easy way .

Invite other to Subscribe this channel on telegram
@Programming_and_Coding
https://t.me/programming_and_coding

C_Language_Coding

This channel will serve you C language program from basic to advance in a serial order that help you in understand the basic and crack any IT examination in easy way .

Invite other to Subscribe this channel on telegram
@Programming_and_Coding

3.17K viewsedited 05:47

C_Language_Coding

GOOGLE Hiring Application Engineering Intern, Summer 2021

Last Date: 8 Dec 2020

Click Here to Apply👇

https://careers.google.com/jobs/results/89086682550149830-application-engineering-intern-summer-2021/

@programming_and_coding

#Update 1

1.72K viewsedited 05:58

C_Language_Coding

26. Pattern 6

A
B C
D E F
G H I J
K L M N O

#include<stdio.h>
#include<conio.h>

void main()
{
int i, j, n;
clrscr();

printf("Enter number : ");
scanf("%d", &n);
int c = 'A';

for (i = 0; i < n; i++)
{
for (j = 0; j <= i; j++)
{
printf("%c", c);
c = c + 1;
}
printf("\n");
}
getch();
}
#pattern
@programming_and_coding

1.74K views07:03

C_Language_Coding

27. Pattern 7

1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
1 2 3 4 5 4 3 2 1

#include<stdio.h>
#include<conio.h>

void main()
{
int i, j, n;
clrscr();

printf("Enter number : ");
scanf("%d", &n);

for (i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
printf("%d", j);
}
for (j = i - 1; j >= 1; j--)
{
printf("%d", j);
}
printf("\n");
}
getch();
}
#pattern
@programming_and_coding

1.73K views07:03

C_Language_Coding

28. Pattern 8 (Binary Pattern)

1
0 1
1 0 1
0 1 0 1
1 0 1 0 1

#include<stdio.h>
#include<conio.h>

void main()
{
int i, j;
int count = 1;
clrscr();

for (i = 1; i <= 5; i++)
{
for (j = 1; j <= i; j++)
{
printf("%d", count++ % 2);
if (j == i && i != 5)
printf("\n");
}
if (i % 2 == 0)
count = 1;
else
count = 0;
}
getch();
}
#pattern
@programming_and_coding

1.71K views07:04

C_Language_Coding

29. Pattern 9

1 2 3 4 5
1 2 3 4
1 2 3
1 2
1

#include<stdio.h>
#include<conio.h>
void main()
{
int i, j, k, l, n;
clrscr();

printf("Enter number : ");
scanf("%d", &n);
printf("\n");

for (i = n; i >= 1; i--)
{
for (j = 1; j <= i; j++)
printf("%d", j);

printf("\n");
}
getch();
}
@programming_and_coding

1.72K views07:05

C_Language_Coding

30. Pattern 10

1
2 1
3 2 1
4 3 2 1
5 4 3 2 1

#include<stdio.h>
#include<conio.h>
void main()
{
int i, j, k;
clrscr();

for (i = 1; i <= 5; i++)
{
for (j = 5; j >= 1; j--)
{
if (j <= i)
{
printf("%d", j);
}
else
{
printf(" ");
}
}
printf("\n");
}
getch();
}
@programming_and_coding

1.73K views07:06

C_Language_Coding

31. Pattern 11

1 1
1 2 2 1
1 2 3 3 2 1
1 2 3 4 4 3 2 1

#include<stdio.h>
#include<conio.h>
void main()
{
int i, j, k;
clrscr();

for (i = 1; i <= 5; i++)
{
for (j = 1; j <= 5; j++)
{
if (j <= i)
{
printf("%d ", j);
}
else
{
printf(" ");
}
}
for (j = 5; j >= 1; j--)
{
if (j <= i)
{
printf("%d ", j);
}
else
{
printf(" ");
}
}
printf("\n");
}
getch();
}
@programming_and_coding

1.77K views07:06

C_Language_Coding

32. Floyd's triangle

1
2 3
4 5 6
7 8 9 10
11 12 13 14

#include<stdio.h>
#include<conio.h>
void main()
{
int n, i, c, a = 1;
clrscr();

printf("Enter the number of rows : ");
scanf("%d", &n);

for (i = 1; i <= n; i++) {

for (c = 1; c <= i; c++) {

printf("%d ", a);
a++;

}

printf("\n");
}
getch();
}
@programming_and_coding

2.25K views07:07

C_Language_Coding

33. Pyramid

*
* *
* * *
* * * *
* * * * *

#include<stdio.h>
#include<conio.h>
void main()
{
int row, c, n, temp;
clrscr();

printf("Enter the number of rows : ");
scanf("%d", &n);

temp = n;

for (row = 1; row <= n; row++)
{
for (c = 1; c < temp; c++)
printf(" ");

temp--;

for (c = 1; c <= 2 * row - 1; c++)
printf("*");

printf("\n");
}
getch();
}
@programming_and_coding

1.8K views07:07

C_Language_Coding

34. Pyramid 2

*
*A*
*A*A*
*A*A*A*
*A*A*A*A*

#include<stdio.h>
#include<conio.h>
void main()
{
int n, c, k, space, count = 1;
clrscr();

printf("Enter the number of rows : ");
scanf("%d", &n);

space = n;

for (c = 1; c <= n; c++)
{

for (k = 1; k < space; k++)
printf(" ");

for (k = 1; k <= c; k++)
{
printf("*");

if (c > 1 && count < c)
{
printf("A");
count++;
}
}

printf("\n");
space--;
count = 1;
}
getch();
}
@programming_and_coding

1.83K views07:08

C_Language_Coding

35. Number Pyramid

1
232
34543
4567654
567898765

#include<stdio.h>
#include<conio.h>
void main()
{
int n, c, d, num = 1, space;
clrscr();

printf("Enter the number of rows : ");
scanf("%d", &n);

space = n - 1;

for (d = 1; d <= n; d++)
{
num = d;

for (c = 1; c <= space; c++)
printf(" ");

space--;

for (c = 1; c <= d; c++)
{
printf("%d", num);
num++;
}

num--;
num--;

for (c = 1; c < d; c++)
{
printf("%d", num);
num--;
}
printf("\n");
}
getch();
}
@programming_and_coding

1.86K views07:09

C_Language_Coding

36. Pascal triangle

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1

#include<stdio.h>
#include<conio.h>

long fact(int);

void main()
{
int line, i, j;
clrscr();

printf("Enter the number : ");
scanf("%d", &line);

for (i = 0; i < line; i++)
{
for (j = 0; j < line - i - 1; j++)
{
printf(" ");
}

for (j = 0; j <= i; j++)
{
printf("%ld ", fact(i) / (fact(j) * fact(i - j)));
}

printf("\n");
}
getch();
}

long fact(int num)
{
long f = 1;
int i = 1;

while (i <= num)
{
f = f * i;
i++;
}
return f;
}
@programming_and_coding

1.94K views07:09

C_Language_Coding

37. Pascal triangle without using function

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1

#include<stdio.h>
#include<conio.h>
void main()
{
int x, y, n, a, z, s;
clrscr();

printf("Enter the number : ");
scanf("%d", &n);
s = n;

for (x = 0; x <= n; x++)
{
a = 1;
for (z = s; z >= 0; z--)
printf(" ");

s--;

for (y = 0; y <= x; y++)
{
printf("%d ", a);
a = (a * (x - y) / (y + 1));
}
printf("\n");
}
getch();
}
@programming_and_coding

2.03K views07:10

C_Language_Coding

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#Update 2

1.4K viewsedited 08:00

C_Language_Coding

38. Pascal triangle 2

1
121
12321
1234321
123454321

#include<stdio.h>
#include<conio.h>
void main()
{
int n, c, k, number = 1, space = n;
clrscr();

printf("Enter number of rows : ");
scanf("%d", &n);
printf("\n");
space = n;

for (c = 1; c <= n; c++)
{
for (k = space; k > 1; k--)
printf(" ");

space--;

for (k = 1; k <= 2 * c - 1; k++)
{
if (k <= c)
{
printf("%d", number);

if (k < c)
number++;
}
else
{
number--;
printf("%d", number);
}
}
number = 1;
printf("\n");
}
getch();
}
@programming_and_coding

1.41K views03:20

C_Language_Coding

39. Number Alphabet Pattern

1
A B
2 3 4
C D E F
5 6 7 8 9
G H I J K L

#include<stdio.h>
#include<conio.h>
void main()
{
int num, r, c;
int i = 1;
char ch = 'A';
clrscr();

printf("Enter the number of rows : ");
scanf("%d", &num);
printf("\n");

for (r = 1; r <= num; r++)
{
for (c = 1; c <= r; c++)
{
if (r % 2 == 0)
{
printf(" %c", ch++);
}
else
{
printf(" %d", i++);
}
}
printf("\n");
}
getch();
}
@programming_and_coding

1.89K views03:21

C_Language_Coding

40. Number Diamond Pattern

1
1 2 3
1 2 3 4 5
1 2 3 4 5 6 7
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7
1 2 3 4 5
1 2 3
1

#include<stdio.h>
#include<conio.h>
void main()
{
int i, j, k;
clrscr();

for(i=1;i<=5;i++)
{
for(j=i;j<5;j++)
{
printf(" ");
}
for(k=1;k<(i*2);k++)
{
printf("%d",k);
}
printf("\n");
}
for(i=4;i>=1;i--)
{
for(j=5;j>i;j--)
{
printf(" ");
}
for(k=1;k<(i*2);k++)
{
printf("%d",k);
}
printf("\n");
}
getch();
}
@programming_and_coding

1.4K views03:21

C_Language_Coding

41. Diamond of Numbers

1
2 2 2
3 3 3 3 3
4 4 4 4 4 4 4
5 5 5 5 5 5 5 5 5
4 4 4 4 4 4 4
3 3 3 3 3
2 2 2
1

#include<stdio.h>
#include<conio.h>

void main()
{
int i, j, k;
clrscr();

for (i = 1; i <= 5; i++)
{
for (j = i; j < 5; j++)
{
printf(" ");
}
for (k = 1; k < (i * 2); k++)
{
printf("%d", i);
}
printf("\n");
}

for (i = 4; i >= 1; i--)
{
for (j = 5; j > i; j--)
{
printf(" ");
}
for (k = 1; k < (i * 2); k++)
{
printf("%d", i);
}
printf("\n");
}
getch();
}
@programming_and_coding

1.41K views03:22

C_Language_Coding

42. Diamond Pattern

•
• • •
• • • • •
• • •
•

#include<stdio.h>
#include<conio.h>

void main()
{

int n, c, k, space = 1;
clrscr();

printf("Enter number of rows : ");
scanf("%d", &n);

space = n - 1;

for (k = 1; k <= n; k++)
{

for (c = 1; c <= space; c++)
printf(" ");

space--;

for (c = 1; c <= 2 * k - 1; c++)
printf("•");

printf("\n");
}

space = 1;

for (k = 1; k <= n - 1; k++)
{

for (c = 1; c <= space; c++)
printf(" ");

space++;

for (c = 1; c <= 2 * (n - k) - 1; c++)
printf("•");

printf("\n");
}

getch();
}
@programming_and_coding

1.42K views03:23

C_Language_Coding

43. Diamond star outline

*
* *
* *
* *
* *
* *
*

#include<stdio.h>
#include<conio.h>

void main()
{
int i, j;
clrscr();

for (i = 1; i <= 5; i++)
{
for (j = 5; j > i; j--)
{
printf(" ");
}

printf("*");

for (j = 1; j < (i - 1) * 2; j++)
{
printf(" ");
}

if (i == 1)
{
printf("\n");
}

else
{ printf("*\n"); }
}

for (i = 4; i >= 1; i--)
{
for (j = 5; j > i; j--)
{
printf(" ");
}

printf("*");

for (j = 1; j < (i - 1) * 2; j++)
{
printf(" ");
}

if (i == 1)
{
printf("\n");
}
else
{ printf("*\n"); }
}

getch();
}
@programming_and_coding

1.43K views03:23