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chemistry remidial exam በ Ai ሥሩ ሲልክ ከያዛችሁ
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GEOGRAPHY REMEDIAL EXAM
Geography remedial answers
Chemistry remidial exam answer
𝚎𝚙_𝚔 𝚡𝚘:
1. A. All atoms of a given element are identical in mass and in all other properties.

2. D. James Chadwick discovered the neutrons, an electrically neutral particle of a mass approximately equal to that of the proton.

3. A. They must be atoms of the same element.

4. D. The first ionization energy of S is smaller than Al because removing an electron from S is easier than removing an electron from Al, as electron repulsions build up in S.

6. The correct answer is D.

The spin quantum number (m) describes the electron spin and it gives an electron a magnetic property.

7. The correct answer is A.

The development of atomic models from the earliest view up to the modern view is as follows:

* Dalton Model
* Thomson's Model
* Rutherford's Model
* Bohr's Model
* Quantum Mechanical Model

8. The correct answer is C.

The electron configuration of the cation, M, is [Ar] 3d4s2. This is the electron configuration of vanadium.

9. The correct answer is C.

A chemical bond is formed by losing, gaining, or sharing electrons.
The correct answers are:

11. B. 4
12. C. CO2
13. C. N2
14. B. strong repulsive forces between bonding pair and bonding pair electrons.
15. C. A gas has neither a definite shape nor a definite volume.
16. C. Bent or V-shape
17. C. XeOF4
18. B. C2

For question #42, the volume of 2.0 M NaOH required to neutralize 250 ml of 2.70 M H2SO4 can be calculated using the equation:

(Molarity of Acid) × (Volume of Acid) = (Molarity of Base) × (Volume of Base)

(2.70 M) × (250 ml) = (2.0 M) × (Volume of NaOH)

Solving for the volume of NaOH, we get:

Volume of NaOH = (2.70 M × 250 ml) / 2.0 M = 337.5 ml

Thus, the correct answer is B: 338 ml.

For question #43, the correct statement describing the similarity between voltaic cells and electrolytic cells is:

B. Both types of cells contain two electrodes in contact with electrolytes.

For question #44, the correct answer is:

D. The metal in the salt will deposit on the cathode.

For question #45, the false statement regarding the electrolysis of dilute sulfuric acid solution is:

D. At the cathode, H+ ions are discharged.

For question #46, the false statement regarding electrolysis is:

D. The electrical conduction of electrolytes is due to the movement of delocalized electrons.

For question #47, to calculate the mass of copper deposited, we need to use Faraday's laws of electrolysis. According to Faraday's first law, the mass of a substance deposited during electrolysis is directly proportional to the amount of electricity passed through the solution. The equation can be written as:

Mass of Copper / Molar Mass of Copper = Amount of Electricity / Faraday's Constant

Since we know that 0.108 g of silver is being deposited and the molar mass of Ag is 108 g/mol, we can use this information to find the amount of electricity passed through the solution.

0.108 g / 108 g/mol = Amount of Electricity / Faraday's Constant

Solving for the amount of electricity, we get:

Amount of Electricity = (0.108 g / 108 g/mol) × Faraday's Constant

Next, we need to find the mass of copper deposited. Since the molar mass of Cu is 63.5 g/mol, we can set up the equation:

Mass of Copper / 63.5 g/mol = Amount of Electricity / Faraday's Constant

Solving for the mass of copper, we get:

Mass of Copper = (Amount of Electricity / Faraday's Constant) × 63.5 g/mol

Substituting the value of the amount of electricity we found earlier, we get:

Mass of Copper = (0.108 g / 108 g/mol) × Faraday's Constant / Faraday's Constant × 63.5 g/mol

Simplifying, we find:

Mass of Copper = 0.108 g × 63.5 g/mol / 108 g/mol = 0.063 g

Thus, the correct answer is A: 0.063 g.

For question #48, to calculate the mass of chlorine gas produced, we need to use Faraday's law of electrolysis again. The equation can be written as:

Mass of Cl2 / Molar Mass of Cl2 = Amount of Electricity / Faraday's Constant

Chemistry remedial exam answers
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ቁርስ😁😁😁😂😂😂😂 asosa ትለያላችሁ አቦ
Biology remidial exam
ነብስህን በገነት ያኑርልን RIP
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የዩኒቨርስቲ መውጫ ፈተና /Exit Exam / ውጤት ይፋ ሆነ‼️

62 ነጥብ 37 በመቶ የመንግስት ተቋማትና 17 ነጥብ 2 በመቶ የግል ተቋማት ተማሪዎች የማለፊያውን 50 በመቶና ከዛም በላይ ውጤት አስመዝግበዋል።
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ሐምሌ 8/2015 ዓ.ም ( ትምህርት ሚኒስቴር ) የትምህርት ሚኒስቴር ከሰኔ 30 ቀን ጀምሮ ለስድስት ቀናት ሲሰጥ የቆየውን የዩኒቨርስቲ መውጫ ፈተና በስኬት አጠናቋል።

የትምህርት ሚኒስቴር የከፍተኛ ትምህርት ዘርፍ ሚኒስትር ዴኤታ ሳሙኤል ክፍሌ ( ዶ/ር ) ፈተናውን አስመልክተው ዛሬ መግለጫ ሰጥተዋል።

የመውጫ ፈተናውን ከ48 የመንግስት ተቋማት 84ሺ 627 እና ከ171 የግል ተቋማት ደግሞ 109ሺ 239 በድምሩ 194 ሺ 239 ተማሪዎች ፈተናውን ለመውሰድ ብቁ ሆነው መመዝገባቸውን ዶ/ር ሳሙኤል አስታውቀዋል።

ፈተናውን ለመውሰድ ከተመዘገቡት ከመንግስት 77ሺ 981 ወይም 92ነጥብ 15 በመቶ ከግል 72ሺ 203 ወይም 65ነጥብ 87 በመቶ በድምሩ 150ሺ 184 ተማሪዎች ፈተናውን መውሰዳቸውን ተናግረዋል።

ከመንግስት ተቋማት ለፈተና ከተቀመጡት 48ሺ 632 ተማሪዎች ውስጥ 62ነጥብ 37 በመቶ ከግል ተቋማት ተማሪዎች ውስጥ ደግሞ 17ነጥብ 2 በመቶ የማለፊያውን 50 እና ከዚያ በላይ ውጤት አስመዝግበዋል።


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