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●Good Morning● 23-05-21
◆Daily The Hindu Vocabulary◆
1. INTRANSIGENT (ADJECTIVE) (हठी): uncompromising
Synonyms: inflexible, unbending
Antonyms: compliant
Example Sentence:
Her father had tried persuasion, but she was intransigent.
2. CONVENE (VERB): (बुलाना): summon
Synonyms: call, order
Antonyms: disperse
Example Sentence:
He had convened a secret meeting of military personnel.
3. SCANDALIZE (VERB): (अपमानित करना): shock
Synonyms: appall, outrage
Antonyms: impress
Example Sentence:
Their lack of manners scandalized their hosts.
4. ACCREDIT (VERB): (मान्य करना): recognize
Synonyms: license, authorize
Antonyms: ban
Example Sentence:
Institutions that do not meet the standards will not be accredited for teacher training.
5. INDIGENOUS (NOUN): (स्वदेशी): native
Synonyms: aboriginal, local
Antonyms: expatriate
Example Sentence:
The most indigenous inhabitants were the American Indians.
6. ANGST (NOUN): (उत्कंठा): anxiety
Synonyms: fear, dread
Antonyms: calmness
Example Sentence:The middle classes go through existential angst.
7. OUST (VERB): (बाहर निकालना): expel
Synonyms: force out, remove
Antonyms: readmit
Example Sentence:The reformists were ousted from power.
8. BLIGHT (NOUN): (क्षति): affliction
Synonyms: scourge, bane
Antonyms: blessing
Example Sentence:The vacant properties are a blight on the neighbourhood.
9. FORGO (VERB): (त्यागना): do without
Synonyms: go without, give up
Antonyms: keep
Example Sentence:I'll forgo dessert tonight—I'm trying to lose weight.
10. AFFLUENT (ADJECTIVE): (धनी): wealthy
Synonyms: rich, prosperous
Antonyms: poor
Example Sentence:I reside in an affluent neighbourhood.
@PRACTICE_ENGLISH_VOCAB
◆Daily The Hindu Vocabulary◆
1. INTRANSIGENT (ADJECTIVE) (हठी): uncompromising
Synonyms: inflexible, unbending
Antonyms: compliant
Example Sentence:
Her father had tried persuasion, but she was intransigent.
2. CONVENE (VERB): (बुलाना): summon
Synonyms: call, order
Antonyms: disperse
Example Sentence:
He had convened a secret meeting of military personnel.
3. SCANDALIZE (VERB): (अपमानित करना): shock
Synonyms: appall, outrage
Antonyms: impress
Example Sentence:
Their lack of manners scandalized their hosts.
4. ACCREDIT (VERB): (मान्य करना): recognize
Synonyms: license, authorize
Antonyms: ban
Example Sentence:
Institutions that do not meet the standards will not be accredited for teacher training.
5. INDIGENOUS (NOUN): (स्वदेशी): native
Synonyms: aboriginal, local
Antonyms: expatriate
Example Sentence:
The most indigenous inhabitants were the American Indians.
6. ANGST (NOUN): (उत्कंठा): anxiety
Synonyms: fear, dread
Antonyms: calmness
Example Sentence:The middle classes go through existential angst.
7. OUST (VERB): (बाहर निकालना): expel
Synonyms: force out, remove
Antonyms: readmit
Example Sentence:The reformists were ousted from power.
8. BLIGHT (NOUN): (क्षति): affliction
Synonyms: scourge, bane
Antonyms: blessing
Example Sentence:The vacant properties are a blight on the neighbourhood.
9. FORGO (VERB): (त्यागना): do without
Synonyms: go without, give up
Antonyms: keep
Example Sentence:I'll forgo dessert tonight—I'm trying to lose weight.
10. AFFLUENT (ADJECTIVE): (धनी): wealthy
Synonyms: rich, prosperous
Antonyms: poor
Example Sentence:I reside in an affluent neighbourhood.
@PRACTICE_ENGLISH_VOCAB
The following Pie chart shows the percentage of students in each class and line graph shows the percentage of students participated in sports.
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6) What is the ratio of the number of students from E to the students participated in sports from C & D?
E से छात्रों की संख्या का C और D से खेलों में भाग लेने वाले छात्रों की संख्या का अनुपात कितना है?
A) 14: 1
B) 1: 14
C) 13: 21
D) 21: 13
E) None of these
7) What % is the total number of students participated in sports from all the classes together?
सभी कक्षाओं से मिलाकर खेलों में भाग लेने वाले विद्यार्थियों की कुल संख्या कितने प्रतिशत है?
A) 15.5%
B) 17.5%
C) 20.5%
D) 13.5%
E) None of these
8) Students participating in sports from C & D together is how much % less than the no. of students in A?
C और D से मिलाकर खेल में भाग लेने वाले विद्यार्थी A में विद्यार्थियों की संख्या से कितने प्रतिशत कम हैं?
A) 71.72%
B) 73.15%
C) 79.16%
D) 76.18%
E) None of these
9) What is the difference between the no. of students participating sports in A & B together and the total no. of students in D & E together?
A और B में मिलाकर खेल में भाग लेने वाले विद्यार्थियों की संख्या और D और E में मिलाकर कुल विद्यार्थियों की संख्या के बीच का अंतर कितना है?
A) 792
B) 996
C) 874
D) 926
E) None of these
10) In which of the following school, the no. of students participating in sports is higher?
निम्नलिखित में से किस विद्यालय में खेलों में भाग लेने वाले विद्यार्थियों की संख्या अधिक है?
A) A
B) E
C) B
D) C
E) None of these
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E से छात्रों की संख्या का C और D से खेलों में भाग लेने वाले छात्रों की संख्या का अनुपात कितना है?
A) 14: 1
B) 1: 14
C) 13: 21
D) 21: 13
E) None of these
7) What % is the total number of students participated in sports from all the classes together?
सभी कक्षाओं से मिलाकर खेलों में भाग लेने वाले विद्यार्थियों की कुल संख्या कितने प्रतिशत है?
A) 15.5%
B) 17.5%
C) 20.5%
D) 13.5%
E) None of these
8) Students participating in sports from C & D together is how much % less than the no. of students in A?
C और D से मिलाकर खेल में भाग लेने वाले विद्यार्थी A में विद्यार्थियों की संख्या से कितने प्रतिशत कम हैं?
A) 71.72%
B) 73.15%
C) 79.16%
D) 76.18%
E) None of these
9) What is the difference between the no. of students participating sports in A & B together and the total no. of students in D & E together?
A और B में मिलाकर खेल में भाग लेने वाले विद्यार्थियों की संख्या और D और E में मिलाकर कुल विद्यार्थियों की संख्या के बीच का अंतर कितना है?
A) 792
B) 996
C) 874
D) 926
E) None of these
10) In which of the following school, the no. of students participating in sports is higher?
निम्नलिखित में से किस विद्यालय में खेलों में भाग लेने वाले विद्यार्थियों की संख्या अधिक है?
A) A
B) E
C) B
D) C
E) None of these
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6) Answer: A
Required ratio = 630: 45 => 126: 9 => 14: 1
7) Answer: A
Required percentage = 279/1800 * 100 = 15.5%
8) Answer: C
Required percentage = [(18 + 27) – 216]/216 * 100
= 171/216 * 100
= 79.16%
9) Answer: A
Required difference = 900 – 108 = 792
10) Answer: B
A – 27
B – 81
C – 18
D – 27
E – 126
Class E has maximum number of students participating in sports.
Required ratio = 630: 45 => 126: 9 => 14: 1
7) Answer: A
Required percentage = 279/1800 * 100 = 15.5%
8) Answer: C
Required percentage = [(18 + 27) – 216]/216 * 100
= 171/216 * 100
= 79.16%
9) Answer: A
Required difference = 900 – 108 = 792
10) Answer: B
A – 27
B – 81
C – 18
D – 27
E – 126
Class E has maximum number of students participating in sports.
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Ram’s age 2 years ago and Bala’s age 5 years ago are in the ratio 6: 5. The sum of their ages is 95, as Ram is (A) years old and Bala is (B) years old. Ram and Bala decided to keep them young by doing swimming. Ram swims 20 km upstream and returns back where current speed is 5 kmph. Swimming in upstream takes 1 hour more than downstream. Bala swims in still water at (C) kmph which is twice that of Ram. While coming back from swimming pool, they sell their cycles at a profit of (D)% after giving a discount of 10% and the markup is 25%.
The profit earned is lent at a rate of 4% compounded annually for 2 years which amounts to 43264. The same principal is lent at 15% simple interest for 2 years. So the simple interest is (E).
After reaching home, they decided to enter into partnership. Ram invests Rs.900 for 6 months and Bala invests (F) for the whole year. At the end of one year the profit ratio of Ram and Bala is 15: 13.
2 वर्ष पहले राम की आयु और 5 वर्ष पहले बाला की आयु का अनुपात 6:5 है। उनकी आयु का योग 95 है, क्योंकि राम (A) वर्ष का है और बाला (B) वर्ष का है। राम और बाला ने स्विमिंग कर उन्हें जवान रखने का फैसला किया। राम धारा के प्रतिकूल 20 किमी तैरता है और वापस लौटता है जहां वर्तमान गति 5 किमी प्रति घंटा है। धारा के प्रतिकूल तैरने में धारा के प्रतिकूल तैरने से 1 घंटा अधिक लगता है। बाला शांत पानी में तैरती है (C) किमी प्रति घंटा जो राम से दोगुना है। स्विमिंग पूल से वापस आते समय, वे 10% की छूट देकर अपनी साइकिल (D)% के लाभ पर बेचते हैं और मार्कअप 25% है।
अर्जित लाभ को 2 वर्षों के लिए 4% वार्षिक चक्रवृद्धि की दर से उधार दिया जाता है जो कि 43264 है। समान मूलधन को 15% साधारण ब्याज पर 2 वर्षों के लिए उधार दिया जाता है। तो साधारण ब्याज (E) है।
घर पहुंचने के बाद, उन्होंने साझेदारी में प्रवेश करने का फैसला किया। राम 6 महीने के लिए 900 रुपये का निवेश करता है और बाला पूरे वर्ष के लिए (F) निवेश करता है। एक वर्ष के अंत में राम और बाला का लाभ अनुपात 15:13 है।
1) What will come in place of A and B?
A और B के स्थान पर क्या आयेगा?
A) 40, 35
B) 35, 40
C) 45, 50
D) 50, 45
E) None of these
2) What will come in place of C?
C के स्थान पर क्या आएगा?
A) 60 kmph
B) 15 kmph
C) 90 kmph
D) 30 kmph
E) None of these
3) What will come in place of D?
D के स्थान पर क्या आएगा?
A) 37.5 %
B) 25%
C) 16.667%
D) 12.5%
E) None of these
4) What will come in place of E?
E के स्थान पर क्या आयेगा ?
A) 24000
B) 36000
C) 10000
D) 12000
E) None of these
5) What will come in place of F?
F के स्थान पर क्या आएगा?
A) 460
B) 490
C) 360
D) 390
E) None of these
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Ram’s age 2 years ago and Bala’s age 5 years ago are in the ratio 6: 5. The sum of their ages is 95, as Ram is (A) years old and Bala is (B) years old. Ram and Bala decided to keep them young by doing swimming. Ram swims 20 km upstream and returns back where current speed is 5 kmph. Swimming in upstream takes 1 hour more than downstream. Bala swims in still water at (C) kmph which is twice that of Ram. While coming back from swimming pool, they sell their cycles at a profit of (D)% after giving a discount of 10% and the markup is 25%.
The profit earned is lent at a rate of 4% compounded annually for 2 years which amounts to 43264. The same principal is lent at 15% simple interest for 2 years. So the simple interest is (E).
After reaching home, they decided to enter into partnership. Ram invests Rs.900 for 6 months and Bala invests (F) for the whole year. At the end of one year the profit ratio of Ram and Bala is 15: 13.
2 वर्ष पहले राम की आयु और 5 वर्ष पहले बाला की आयु का अनुपात 6:5 है। उनकी आयु का योग 95 है, क्योंकि राम (A) वर्ष का है और बाला (B) वर्ष का है। राम और बाला ने स्विमिंग कर उन्हें जवान रखने का फैसला किया। राम धारा के प्रतिकूल 20 किमी तैरता है और वापस लौटता है जहां वर्तमान गति 5 किमी प्रति घंटा है। धारा के प्रतिकूल तैरने में धारा के प्रतिकूल तैरने से 1 घंटा अधिक लगता है। बाला शांत पानी में तैरती है (C) किमी प्रति घंटा जो राम से दोगुना है। स्विमिंग पूल से वापस आते समय, वे 10% की छूट देकर अपनी साइकिल (D)% के लाभ पर बेचते हैं और मार्कअप 25% है।
अर्जित लाभ को 2 वर्षों के लिए 4% वार्षिक चक्रवृद्धि की दर से उधार दिया जाता है जो कि 43264 है। समान मूलधन को 15% साधारण ब्याज पर 2 वर्षों के लिए उधार दिया जाता है। तो साधारण ब्याज (E) है।
घर पहुंचने के बाद, उन्होंने साझेदारी में प्रवेश करने का फैसला किया। राम 6 महीने के लिए 900 रुपये का निवेश करता है और बाला पूरे वर्ष के लिए (F) निवेश करता है। एक वर्ष के अंत में राम और बाला का लाभ अनुपात 15:13 है।
1) What will come in place of A and B?
A और B के स्थान पर क्या आयेगा?
A) 40, 35
B) 35, 40
C) 45, 50
D) 50, 45
E) None of these
2) What will come in place of C?
C के स्थान पर क्या आएगा?
A) 60 kmph
B) 15 kmph
C) 90 kmph
D) 30 kmph
E) None of these
3) What will come in place of D?
D के स्थान पर क्या आएगा?
A) 37.5 %
B) 25%
C) 16.667%
D) 12.5%
E) None of these
4) What will come in place of E?
E के स्थान पर क्या आयेगा ?
A) 24000
B) 36000
C) 10000
D) 12000
E) None of these
5) What will come in place of F?
F के स्थान पर क्या आएगा?
A) 460
B) 490
C) 360
D) 390
E) None of these
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1) Answer: D
5x + 5 + 6x + 2 = 95
x = 8
Ram: 6x + 2 = 50
Bala: 5x + 5 = 45
2) Answer: D
20/(x – 5) – 20/(x + 5) = 1
x2 = 225
x = 15
2x = 30 kmph
3) Answer: D
Let us take cost price of the bicycle be Rs.100
MP = 100 * 125/100 = Rs.125
SP = 125 * (100 – 10)/100 = Rs.112.5
Required percentage = (112.5 – 100)/100 * 100 = 12.5%
4) Answer: D
Amount = P (1 + R/100)2
43264 = P (1 + 4/100)2
43264 * 100/104 * 100/104 = 40000
Simple interest = PNR/100
= (40000 * 15 * 2)/100 = Rs.12000
5) Answer: D
Profit ratio of Ram and Bala = (900 * 6)/(x * 12) = 15/13
x = 390
5x + 5 + 6x + 2 = 95
x = 8
Ram: 6x + 2 = 50
Bala: 5x + 5 = 45
2) Answer: D
20/(x – 5) – 20/(x + 5) = 1
x2 = 225
x = 15
2x = 30 kmph
3) Answer: D
Let us take cost price of the bicycle be Rs.100
MP = 100 * 125/100 = Rs.125
SP = 125 * (100 – 10)/100 = Rs.112.5
Required percentage = (112.5 – 100)/100 * 100 = 12.5%
4) Answer: D
Amount = P (1 + R/100)2
43264 = P (1 + 4/100)2
43264 * 100/104 * 100/104 = 40000
Simple interest = PNR/100
= (40000 * 15 * 2)/100 = Rs.12000
5) Answer: D
Profit ratio of Ram and Bala = (900 * 6)/(x * 12) = 15/13
x = 390
The following table shows the number of days taken by 5 different persons to complete the work.
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1) Person P and S started working together, after 4 days P and S left the job and the remaining work was completed by person S and A together in 2 2/3 days. Find the number of days taken by person A alone to complete the work?
व्यक्ति P और S ने एक साथ काम करना शुरू किया, 4 दिनों के बाद P और S ने काम छोड़ दिया और शेष कार्य व्यक्ति S और A ने मिलकर 2 2/3 दिनों में पूरा किया। व्यक्ति A द्वारा अकेले कार्य को पूरा करने में लिए गए दिनों की संख्या ज्ञात कीजिए?
a) 12 days
b) 9 days
c) 10 days
d) 15 days
e) None of these
2) Q and R started working together, R left the job after some days. Then find the number of days taken to complete the whole work?
Q और R ने एक साथ काम करना शुरू किया, कुछ दिनों के बाद R ने काम छोड़ दिया। तो पूरे कार्य को पूरा करने में लगने वाले दिनों की संख्या ज्ञात कीजिये?
Statement I: R gets Rs. 1500 out of the total wage of Rs. 4500.
कथन I: R को रु। कुल वेतन में से 1500 रु. 4500.
Statement II: The number of days Q and R worked to complete the whole work is in the ratio of 8 : 5.
कथन II: पूरे कार्य को पूरा करने के लिए Q और R द्वारा कार्य किए गए दिनों की संख्या 8 : 5 के अनुपात में है।
a) Only statement I
b) Only statement II
c) Either statement I or II
d) Neither statement I nor II
e) Both the statements together
3) R and T started working together for 10 days, after which R was replaced by A. If the work was finished in next 4 4/9 days, then find the number of days taken by A alone to complete the work?
R और T 10 दिनों के लिए एक साथ काम करना शुरू करते हैं, जिसके बाद R को A से बदल दिया जाता है। यदि कार्य अगले 4 4/9 दिनों में समाप्त हो जाता है, तो कार्य को पूरा करने के लिए अकेले A द्वारा लिए गए दिनों की संख्या ज्ञात करें?
a) 50 days
b) 46 days
c) 54 days
d) 42 days
e) None of these
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व्यक्ति P और S ने एक साथ काम करना शुरू किया, 4 दिनों के बाद P और S ने काम छोड़ दिया और शेष कार्य व्यक्ति S और A ने मिलकर 2 2/3 दिनों में पूरा किया। व्यक्ति A द्वारा अकेले कार्य को पूरा करने में लिए गए दिनों की संख्या ज्ञात कीजिए?
a) 12 days
b) 9 days
c) 10 days
d) 15 days
e) None of these
2) Q and R started working together, R left the job after some days. Then find the number of days taken to complete the whole work?
Q और R ने एक साथ काम करना शुरू किया, कुछ दिनों के बाद R ने काम छोड़ दिया। तो पूरे कार्य को पूरा करने में लगने वाले दिनों की संख्या ज्ञात कीजिये?
Statement I: R gets Rs. 1500 out of the total wage of Rs. 4500.
कथन I: R को रु। कुल वेतन में से 1500 रु. 4500.
Statement II: The number of days Q and R worked to complete the whole work is in the ratio of 8 : 5.
कथन II: पूरे कार्य को पूरा करने के लिए Q और R द्वारा कार्य किए गए दिनों की संख्या 8 : 5 के अनुपात में है।
a) Only statement I
b) Only statement II
c) Either statement I or II
d) Neither statement I nor II
e) Both the statements together
3) R and T started working together for 10 days, after which R was replaced by A. If the work was finished in next 4 4/9 days, then find the number of days taken by A alone to complete the work?
R और T 10 दिनों के लिए एक साथ काम करना शुरू करते हैं, जिसके बाद R को A से बदल दिया जाता है। यदि कार्य अगले 4 4/9 दिनों में समाप्त हो जाता है, तो कार्य को पूरा करने के लिए अकेले A द्वारा लिए गए दिनों की संख्या ज्ञात करें?
a) 50 days
b) 46 days
c) 54 days
d) 42 days
e) None of these
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1) Answer: B
(P + S)’s 1 day work = 1/12 + 1/18 = 30/(12*18) = 5/36
(P + S)’s 4 days work = (5/36) * 4 = 5/9
Remaining work = 1 – (5/9) = 4/9
Given,
(4/9) * (S + A)’s whole work = 8/3
(S + A)’s whole work = (8/3) * (9/4) = 6 days
A’s 1 day work = (1/6) – (1/18) = 1/9
A alone can complete the work in 9 days.
2) Answer: C
Statement I:
Part of work completed by R = (1500/4500) = 1/3
R worked for, (1/3) * 30 = 10 days
(Q + R)’s 1 day work = (1/24) + (1/30) = 54/(24 * 30)
(Q + R)’s 10 days work = [54/(24 * 30)] * 10 = ¾
Remaining work = 1 – ¾ = ¼
Given,
(1/4) * 24 = 6 days
Required number of days = 10 + 6 = 16 days
Statement I alone is sufficient to answer the question.
Statement II:
Q’s per day work = 1/24
R’s per day work = 1/30
LCM of 24 and 30 = 120 units
Total work = 120 units
Q’s per day work = 120/24 = 5 units
R’s per day work = 120/30 = 4 units
Let the number of days Q and R worked is 8x and 5x respectively,
According to the question,
8x * 5 + 5x * 4 = 120
40x + 20x = 120
60x = 120
x = 2
Required number of days
= > (8 * 2 – 5 * 2) + (5 * 2)
= > (16 – 10) + 10 = 16 days
Statement II alone is sufficient to answer the question.
3) Answer: A
(R + T)’s 1 day work
= > (1/30) + (1/25) = 55/(30 * 25)
= > 11/150
(R + T)’s 10 days work
= > (11/150) * 10 = 11/15
Remaining work = 1 – (11/15) = 4/15
Given,
(4/15) * (A + T)’s whole work = 40/9
(A + T)’s whole work = (40/9) * (15/4) = 50/3
A’s 1 day work = (3/50) – (1/25) = 1/50
A alone can complete the work in 50 days.
(P + S)’s 1 day work = 1/12 + 1/18 = 30/(12*18) = 5/36
(P + S)’s 4 days work = (5/36) * 4 = 5/9
Remaining work = 1 – (5/9) = 4/9
Given,
(4/9) * (S + A)’s whole work = 8/3
(S + A)’s whole work = (8/3) * (9/4) = 6 days
A’s 1 day work = (1/6) – (1/18) = 1/9
A alone can complete the work in 9 days.
2) Answer: C
Statement I:
Part of work completed by R = (1500/4500) = 1/3
R worked for, (1/3) * 30 = 10 days
(Q + R)’s 1 day work = (1/24) + (1/30) = 54/(24 * 30)
(Q + R)’s 10 days work = [54/(24 * 30)] * 10 = ¾
Remaining work = 1 – ¾ = ¼
Given,
(1/4) * 24 = 6 days
Required number of days = 10 + 6 = 16 days
Statement I alone is sufficient to answer the question.
Statement II:
Q’s per day work = 1/24
R’s per day work = 1/30
LCM of 24 and 30 = 120 units
Total work = 120 units
Q’s per day work = 120/24 = 5 units
R’s per day work = 120/30 = 4 units
Let the number of days Q and R worked is 8x and 5x respectively,
According to the question,
8x * 5 + 5x * 4 = 120
40x + 20x = 120
60x = 120
x = 2
Required number of days
= > (8 * 2 – 5 * 2) + (5 * 2)
= > (16 – 10) + 10 = 16 days
Statement II alone is sufficient to answer the question.
3) Answer: A
(R + T)’s 1 day work
= > (1/30) + (1/25) = 55/(30 * 25)
= > 11/150
(R + T)’s 10 days work
= > (11/150) * 10 = 11/15
Remaining work = 1 – (11/15) = 4/15
Given,
(4/15) * (A + T)’s whole work = 40/9
(A + T)’s whole work = (40/9) * (15/4) = 50/3
A’s 1 day work = (3/50) – (1/25) = 1/50
A alone can complete the work in 50 days.