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Seven persons P, Q, R, S, T, V and X were born in seven different month viz. January, March, April, May, June, July and August of the same year but not necessarily in the same order.
V was born in the month having 30 days. Two persons were born between V and Q. More than three persons were born between X and P. P was born after Q. T was born before V in the month of 31 days. S was born immediately before R. T was not born on January.

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सात व्यक्ति- P, Q, R, S, T, V और X हैं, जिनका जन्म समान वर्ष के सात अलग-अलग महीनों अर्थात्- जनवरी, मार्च, अप्रैल, मई, जून, जुलाई और अगस्त में होता है, लेकिन आवश्यक नहीं कि समान क्रम में हो।
V का जन्म 30 दिनों वाले महीने में हुआ था। V और Q के बीच दो व्यक्तियों का जन्म हुआ था। X और P के बीच तीन से अधिक व्यक्तियों का जन्म हुआ था। P, का जन्म Q से बाद हुआ था। T का जन्म 31 दिनों वाले महीने में V से पहले हुआ था। S का जन्म R से ठीक पहले हुआ था। T का जन्म जनवरी में नहीं हुआ था।

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●Good Morning● 26-4-21

◆Daily The Hindu Vocabulary◆

1. COMBAT (VERB): (सामना करना): fight
Synonyms: tackle, attack
Antonyms: give in to
Example Sentence:Doctors are trying to combat the spread of coronavirus.


2. INTELLECTUAL (ADJECTIVE): (बौद्धिक): mental
Synonyms: cerebral, cognitive
Antonyms: physical
Example Sentence:Children need intellectual stimulation.


3. REPUDIATION (NOUN): (अस्वीकृति): rejection
Synonyms: renunciation, abandonment
Antonyms: confirmation, ratification
Example Sentence:The breach is not so serious as to amount to a repudiation of the whole contract.


4. NUTRITIOUS (ADJECTIVE): (पौष्टिक): nourishing
Synonyms: nutritive, wholesome
Antonyms: unwholesome
Example Sentence:Home-cooked burgers make a nutritious meal.


5. SCOURGE (NOUN): (अभिशाप): affliction
Synonyms: bane, curse
Antonyms: blessing
Example Sentence:India is facing the scourge of mass unemployment.


6. MERCILESS (ADJECTIVE): (निर्मम): ruthless
Synonyms: remorseless, pitiless
Antonyms: merciful
Example Sentence:His murder merciless attack with a blunt instrument.


7. ADVENT (NOUN): (आगमन): arrival
Synonyms: appearance, emergence
Antonyms: departure
Example Sentence:The advent of email has simultaneously brought our society closer together and farther apart.


8. UNERRING (ADJECTIVE): (अचूक): unfailing
Synonyms: infallible unswerving
Antonyms: fallible
Example Sentence:His sense of direction is unerring.


9. SEIZE (VERB): (पकड़ना): grab
Synonyms: grasp, snatch
Antonyms: let go of
Example Sentence:She jumped up and seized his arm.


10. FRAIL (ADJECTIVE): (दुर्बल): infirm
Synonyms: weak, weakened
Antonyms: strong
Example Sentence:He gave the frail woman a hug.

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DI SET DAY - 70 😍

The table shows the number of students participated in different sections from different schools.

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1) A group of four students has to form from school C such that the group contains one student in each section and the remaining from any of the section. The number of ways in which this can be possible is 25920. Find the number of students in section III from school C?
चार छात्रों के एक समूह को स्कूल C से बनना है, ताकि समूह में प्रत्येक खंड में एक छात्र शामिल हो और शेष किसी भी अनुभाग से। यह संभव करने के तरीकों की संख्या 25920 है। स्कूल C से अनुभाग III में छात्रों की संख्या ज्ञात करें?
a) 15

b) 12

c) 10

d) 20

e) 18

2) A group of two students has to form from school E such that the group contains at least one student in section III. The number of ways in which this can be possible is 195. A committee of five students is to be formed from school E such that the committee contains 2 students from section I, 1 student from section II and 2 students from section III. Find the number of ways in which this can be possible?
दो छात्रों के एक समूह को स्कूल ई से फार्म करना है जैसे समूह में धारा III में कम से कम एक छात्र शामिल है। यह संभव हो सकता है तरीकों की संख्या 195 है। स्कूल ई से पांच छात्रों की एक समिति बनाई जानी है, जिसमें समिति में खंड I के 2 छात्र, अनुभाग II के 1 छात्र और अनुभाग III के 2 छात्र शामिल हैं। उन तरीकों की संख्या ज्ञात करें जिनमें यह संभव हो सकता है?
a) 15920

b) 16478

c) 23420

d) 17820

e) None of these

3) Find the total number of students in school A?
स्कूल A में छात्रों की कुल संख्या ज्ञात कीजिये?

Statement I: All the students in section II from school A is handshaking with each other and the total number of handshakes is 105.
कथन I: स्कूल A के अनुभाग II के सभी छात्र एक-दूसरे के साथ हैंडशेक कर रहे हैं और हैंडशेक की कुल संख्या 105 है।

Statement II: All the students in school A is handshaking with each other and the total number of handshakes is 780.
कथन II: स्कूल A के सभी छात्र एक-दूसरे के साथ हैंडशेक कर रहे हैं और हैंडशेक की कुल संख्या 780 है।
a) Only I

b) Only II

c) Both I and II

d) Either I or II

e) Neither I nor II

4) In school B, number of students in section III is 75% of the number of students in section II.
स्कूल बी में, धारा III में छात्रों की संख्या अनुभाग II में छात्रों की संख्या का 75% है।

Quantity I: In committee P, five students is to be formed from school B such that the committee contains 1 student from each section and the remaining students from any of the section.
मात्रा I: समिति P में, स्कूल B से पांच छात्रों का गठन किया जाना है जैसे कि समिति में प्रत्येक अनुभाग से 1 छात्र और किसी भी अनुभाग से शेष छात्र शामिल हैं।

Quantity II: In committee Q, five students is to be formed from school B such that committee contains at least one student from section I.
मात्रा II: समिति Q में, स्कूल B से पांच छात्रों का गठन किया जाना है, क्योंकि समिति में I से कम से कम एक छात्र शामिल है।
a) Quantity I > Quantity II

b) Quantity I < Quantity II

c) Quantity I ≥ Quantity II

d) Quantity I ≤ Quantity II

e) Quantity I = Quantity II (or) Relationship cannot be determined

5) A committee of three members is to be formed from each school B and school D. Number of possible ways of a committee contains three students in section III from school D is what percentage of the number of possible ways of committee contains three students in section I from school B?
प्रत्येक स्कूल बी और स्कूल डी से तीन सदस्यों की एक समिति बनाई जानी है।
समिति के संभावित तरीकों की संख्या में स्कूल D से खंड III में तीन छात्रों को शामिल किया गया है समिति के संभावित तरीकों की संख्या का कितना प्रतिशत स्कूल B से खंड I में तीन छात्रों में है?
a) 180%

b) 380%

c) 160%

d) 280%

e) None of these

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1) Answer: c)

No of students in section III from school C = x

Total number of students in school C = x + 8 + 12 = 20 + x

Number of possible ways = 8C1 * 12C1 * xC1 * (20 + x – 3) C1 = 25920

8 * 12 * x * (17+x) = 25920

17x + x2 = 270

= > x2 + 17x – 270 = 0

= > x2 – 10x + 27x – 270 = 0

= > x (x – 10) + 27 (x – 10) = 0

= > x = 10, – 27 (Eliminate the –Ve value)

Number of students in section III from school C = 10

2) Answer: d)

Number of students in section III from school E = y

Total number of students in school E = (y + 12 + 18)

= y + 30

Number of possible ways = yC1 * 30C1 + yC2 = 195

= > y * 30 + (y*(y-1)/(1 *2)) = 195

= > 30y + (y2 – y)/2 = 195

= > 60y + y2 – y = 390

= > y2 + 59y – 390 = 0

= > y2 + 65y – 6y – 390 = 0

= > y (y + 65) – 6 (y + 65) = 0

= > (y + 65) (y – 6) = 0

= > y = 6, -65 (Eliminate –Ve value)

Total number of students in school E = 30 + 6 = 36

Required number of ways = 12C2 * 18C1 * 6C2

= (12*11 / 1*2) *18 *(6*5 / 1*2)

= 6*11*18*3*5

= 17820

3) Answer: b)

From I,

Number of students in section II from school A = n

Number of handshakes = nC2 = 105

= > [n*(n -1)] / (1 * 2) = 105

= > n2 – n = 210

= > n2 – n – 210 = 0

= > n2 – 15n + 14n – 210 = 0

= > (n – 15) (n – 14) = 0

= > n = 15, -14 (Eliminate –Ve value)

From statement I, We have to find only number of students in section II from school A. We can’t find the total number of students.

Hence, statement I alone is not sufficient to answer the given question.

From II,

Total number of students in school A = x

Number of handshakes = xC2 = 780

= > x * (x – 1)/1*2 = 780

= > x2 – x = 780*2

= > x2 – x – 1560 = 0

= > x2 – 40x + 39x – 1560 = 0

= > x (x – 40) + 39 (x – 40) = 0

= > (x – 40) (x + 39) = 0

= > x = 40, -39 (Eliminate –Ve value)

Total number of students in school A is 40.

Hence, Statement II alone is sufficient to answer the given question.

4) Answer: a)

Number of students in section II from school B = x

Number of students in section III from school B = 75/100 * x

= 3x/4

Total number of students in section II and III from school B = 20 – 6 = 14

= > x + 3x/4 = 14

= > 7x/4 = 14

= > x = 8

Number of students in section III from school B = 8 * 75/100 = 6

Quantity I:

Number of ways = 6C1*8C1*6C1*(20-3)C2

= 6 * 8 * 6 *(17*16/1*2)

= 6*8*6*17*8

= 39168

Quantity II: In committee Q, five students is to be formed from school B such that committee contains at least one student from section I.

Number of ways = 6C1*14C4 + 6C2*14C3 + 6C3*14C2 + 6C4*14C1 + 6C5

= 6006 + 5460 + 1820 + 210 + 6

= 13502

Hence, Quantity I > Quantity II

5) Answer: d)

Number of ways in school D = 8C3

= 8*7*6 / 1*2*3 = 56

Number of ways in school B = 6C3

= 6*5*4 / 1*2*3 = 20

Required percentage = (56/20) * 100 = 280%

Study the following information carefully and answer the questions given below:

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6) Number of items produced by company A in 2010 is what percent of the number of items produced by company C in 2011?
2010 में कंपनी A द्वारा उत्पादित वस्तुओं की संख्या 2011 में कंपनी C द्वारा उत्पादित वस्तुओं की संख्या का कितना प्रतिशत है?
a) 170%

b) 350%

c) 320%

d) 230%

e) None of these

7) Find the sum of total number of items produced by companies D and E in all the years together.
सभी वर्षों में एक साथ कंपनियों D और E द्वारा उत्पादित वस्तुओं की कुल संख्या का योग ज्ञात कीजिए।
a) 9250

b) 9025

c) 5290

d) 5029

e) None of these

8) Number of items sold by all the companies in 2010 is what percent more than the number of items sold by company C in all the years together?
2010 में सभी कंपनियों द्वारा बेची गई वस्तुओं की संख्या कंपनी c द्वारा सभी वर्षों में एक साथ बेची गई वस्तुओं की संख्या से कितने प्रतिशत अधिक है?
a) 57.8%

b) 75.8%

c) 70.58%

d) 50.78%

e) None of these

9) Find the difference between total number of items sold by all the companies in 2011 and 2012.
2011 और 2012 में सभी कंपनियों द्वारा बेची गई कुल वस्तुओं के बीच का अंतर ज्ञात करें।
a) 2000

b) 5000

c) 3000

d) 4000

e) None of these

10) Find the respective ratio between total number of items sold by companies B, E in 2010 and total number of items sold by A and D in 2012.
कंपनियों द्वारा बेची गई वस्तुओं की कुल संख्या, 2010 में E और 2012 में A और D द्वारा बेची गई वस्तुओं की कुल संख्या के बीच संबंधित अनुपात ज्ञात कीजिए।
a) 12:19

b) 13:11

c) 19:12

d) 11:13

e) None of these

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6) Answer: b)

Required percentage = (1750/500) x 100 = 350%

7) Answer: a)

Required sum = 1250 + 1750 + 2000 + 750 + 2500 + 1000 = 9250

8) Answer: c)

Number of items sold by all the companies in 2010 = 1750 + 2000 + 1500 + 1250 + 750 = 7250

Number of items sold by company C in all the years together = 1500 + 500 + 2250 = 4250

Required percentage = (7250 – 4250)/4250 x 100 = 70.58%

9) Answer: a)

Total number of items sold by all the companies in 2011 = 2250 + 3000 + 500 + 1750 + 2500 = 10000

Total number of items sold by all the companies in 2012 = 1250 + 1500 + 2250 + 2000 + 1000 = 8000

Required difference = 10000 – 8000 = 2000

10) Answer: d)

Total number of items sold by companies B, E in 2010 = 2000 + 750 = 2750

Total number of items sold by companies A and D in 2012 = 1250 + 2000 = 3250

Required ratio = 2750 : 3250 = 11:13

The following pie chart – 1 shows the percentage distribution of total number of students (Boys + Girls) enrolled for different activities in School A and the pie chart -2 shows the percentage distribution of total number of girl students enrolled for different activities in School A.

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1) Total number of boy students enrolled for Dancing and Singing together is approximately what percentage of total number of girl students enrolled for same activities?
नृत्य और गायन के लिए नामांकित लड़कों की कुल संख्या लगभग समान गतिविधियों के लिए नामांकित छात्राओं की कुल संख्या का कितना प्रतिशत है?
a) 86 %

b) 124 %

c) 102 %

d) 68 %

e) 74 %

2) Find the difference between the total number of students enrolled for Drawing and Karathe together to that of total number of girl students enrolled for Karathe and Swimming together?
ड्राइंग और कराटे के लिए नामांकित छात्रों की कुल संख्या के बीच का अंतर ज्ञात करें कि कुलथी और तैराकी के लिए नामांकित छात्राओं की कुल संख्या एक साथ है?
a) 560

b) 700

c) 850

d) 920

e) None of these

3) Find the ratio between the total number of boy students enrolled for Dancing and Swimming together to that of total number of girl students enrolled for Drawing and Karathe together?
ड्रॉइंग और तैराकी के लिए नामांकित लड़के लड़कियों की कुल संख्या के बीच अनुपात का पता लगाएं, ड्राइंग और कराहे के लिए नामांकित छात्राओं की कुल संख्या एक साथ?
a) 143 : 212

b) 125 : 198

c) 133 : 248

d) 161 : 264

e) None of these

4) Find the average number of boy students enrolled for Singing, Drawing and Karathe together?
सिंगिंग, ड्रॉइंग और करथे के लिए नामांकित लड़के छात्रों की औसत संख्या ज्ञात कीजिए?
a) 326

b) 378

c) 412

d) 434

e) None of these

5) Total number of students enrolled for Singing and Swimming together is approximately what percentage more/less than the total number of girl students enrolled for Dancing, Drawing and Karathe together?
एक साथ गायन और तैराकी के लिए नामांकित छात्रों की कुल संख्या, नृत्य, ड्राइंग और कराटे के लिए नामांकित छात्राओं की कुल संख्या से लगभग कितने प्रतिशत अधिक / कम है?
a) 16 % less

b) 4 % more

c) 4 % less

d) 25 % less

e) 16 % more

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1) Answer: c)

Total number of students enrolled for Dancing = 2500*(18/100) = 450

Total number of students enrolled for Singing = 2500*(14/100) = 350

Total number of girl students enrolled for Dancing =1200*(21/100) = 252

Total number of girl students enrolled for Singing = 1200*(12/100) = 144

Total number of boy students enrolled for Dancing = 450 – 252 = 198

Total number of boy students enrolled for Singing = 350 – 144 = 206

Required % = [(198 + 206)/(252 + 144)]*100

= > (404/396)*100 = 102.02 % = 102 %

2) Answer: b)

The total number of students enrolled for Drawing and Karathe together

= > 2500*(52/100) = 1300

The total number of girl students enrolled for Karathe and Swimming together

= > 1200*(50/100) = 600

Required difference = 1300 – 600 = 700

3) Answer: d)

Total number of students enrolled for Dancing = 2500*(18/100) = 450

Total number of girl students enrolled for Dancing =1200*(21/100) = 252

Total number of boy students enrolled for Dancing = 450 – 252 = 198

Total number of students enrolled for Swimming = 2500*(16/100) = 400

Total number of girl students enrolled for Swimming = 1200*(23/100) = 276

Total number of boy students enrolled for Swimming = 400 – 276 = 124

The total number of boy students enrolled for Dancing and Swimming together

= > 198 + 124 = 322

The total number of girl students enrolled for Drawing and Karathe together

= > 1200*(44/100) = 528

Required ratio = 322 : 528 = 161 : 264

4) Answer: a)

Total number of students enrolled for Singing = 2500*(14/100) = 350

Total number of girl students enrolled for Singing= 1200*(12/100) = 144

Total number of boy students enrolled for Singing = 350 – 144 = 206

Total number of students enrolled for Drawing = 2500*(24/100) = 600

Total number of girl students enrolled for Drawing = 1200*(17/100) = 204

Total number of boy students enrolled for Drawing = 600 – 204 = 396

Total number of students enrolled for Karathe = 2500*(28/100) = 700

Total number of girl students enrolled for Karathe = 1200*(27/100) = 324

Total number of boy students enrolled for Karathe = 700 – 324 = 376

Total number of boy students enrolled for Singing, Drawing and Karathe together

= > 206 + 396 + 376 = 978

Required average = 978/3 = 326

5) Answer: c)

Total number of students enrolled for Singing and Swimming together

= > 2500*(30/100) = 750

Total number of girl students enrolled for Dancing, Drawing and Karathe together

= > 1200*(65/100) = 780

Required % = [(780 – 750)/780]*100 = (30/780)*100 = 4 % less