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In an university, for the B.Tech programme, There are six students i.e. M, N, O, P, Q and R going to college on different days of week from Monday to Sunday. They all belong to different cities i.e. Patna, Goa, Lucknow, Kanpur, Chennai and Delhi.
The one who is going just after holiday, belongs to Delhi. O does not go on Friday. M is going immediately after P. The one who is going on Tuesday belongs to Lucknow. There is a gap of two days between N and R. There are five days gap between the one who belongs to Kanpur and Chennai. There is one holiday except Saturday. R is going on the next day of holiday. Q is going on Wednesday and it is not immediately followed by R. Q belongs to Patna. M does not belong to Kanpur. The one who is going just before M, belongs to Goa.

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एक यूनिवर्सिटी में, बीटेक प्रोग्राम के लिए छह विद्यार्थी अर्थात, M, N, O, P, Q और R सोमवार से रविवार तक सप्ताह के विभिन्न दिनों में कॉलेज जा रहे हैं। वे सभी भिन्न शहरों अर्थात, पटना, गोवा, लखनऊ, कानपुर, चेन्नई और दिल्ली से सम्बंधित हैं। जो व्यक्ति अवकाश के ठीक बाद कॉलेज जा रहा है, वह दिल्ली से सम्बंधित है। O, शुक्रवार को नहीं जाता है। M, P के ठीक बाद जा रहा है। जो व्यक्ति मंगलवार को कॉलेज जा रहा है, वह लखनऊ से सम्बंधित है। N व R के मध्य दो दिनों का अंतराल है। कानपुर व चेन्नई से सम्बंधित व्यक्तियों के मध्य पांच दिनों का अंतराल है। शनिवार को छोड़कर एक दिन का अवकाश है। R, अवकाश के अगले दिन जा रहा है। Q, बुधवार को जा रहा है और यह R के ठीक बाद नहीं है। Q, पटना से सम्बन्ध रखता है। M, कानपुर से सम्बन्ध नहीं रखता है। जो व्यक्ति M से ठीक पहले जा रहा है, गोवा से संबंधित है।

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●Good Morning● 20-4-21

◆Daily The Hindu Vocabulary◆


1. ABROGATE (VERB): (अभिनिषेध करना): repudiate
Synonyms: revoke, repeal
Antonyms: institute
Example Sentence:The ministry proposed to abrogate the dated electoral law.


2. RESOUNDING (ADJECTIVE): (गुंजयमान): reverberant
Synonyms: reverberating, resonant
Antonyms: faint
Example Sentence:I gave him a resounding smack across the face because of his.


3. DEMOLITION (NOUN): (विध्वंस): destruction
Synonyms: flattening, razing
Antonyms: construction
Example Sentence:The monument was thankfully saved from demolition.


4. DISCERNIBLE (ADJECTIVE): (प्रत्यक्ष): visible
Synonyms: detectable, noticeable
Antonyms: imperceptible
Example Sentence:The scandal had no discernible effect on his career.


5. GLOOM (NOUN): (उदासी): depression
Synonyms: despondency, dejection
Antonyms: happiness
Example Sentence:Last year was of economic gloom for the car industry.


6. VULNERABLE (ADJECTIVE): (खतरे में): at risk
Synonyms: endangered, unsafe
Antonyms: safe
Example Sentence:We were in a vulnerable position.


7. HOARD (VERB): (संचय करना): store
Synonyms: store up, stockpile
Antonyms: squander
Example Sentence:Thousands of antiques hoarded by a compulsive collector.


8. RAMPANT (ADJECTIVE): (अनियंत्रित): uncontrolled
Synonyms: unrestrained, unchecked
Antonyms: controlled
Example Sentence:Political violence was rampant in the area.


9. ABET (VERB): (हाँथ बंटाना): assist
Synonyms: aid, help
Antonyms: hinder
Example Sentence:His actions were shown to abet terrorism.


10. MERCY (NOUN): (ढिलाई): leniency
Synonyms: lenience, clemency
Antonyms: ruthlessness
Example Sentence:The boy was screaming and begging for mercy.

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DI SET DAY - 66😍

There are total 6 rectangles A, B, C, D, E and F, pie chart given below shows the distribution (degree) of length (cm) of one side of those 6 different rectangles.

Table given below shows the length of another side of those 6 rectangles as a per cent of length of given side in the pie chart.

Sum of the pie chart = 120 cm

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1) Inside the rectangular filed C a cylindrical pit of radius 7 cm and depth 8.6 cm is dig. The soil coming out after digging is spread out over remaining part of the field, then what is the increment in the level of that rectangular field?
आयताकार दायर C के अंदर त्रिज्या 7 सेमी और गहराई 8.6 सेमी की एक बेलनाकार गड्ढा खोदा गया है। खुदाई के बाद निकलने वाली मिट्टी खेत के बचे हुए हिस्से में फैल जाती है, फिर उस आयताकार खेत के स्तर में क्या वृद्धि होती है?
a) 8.6 cm

b) 15.4 cm

c) 10.4 cm

d) 12.8 cm

e) None of these

2) If the cost of flooring is Rs.15/cm2 and cost of fencing is Rs.25/cm, then what is the ratio of cost of flooring the rectangular field A to the cost of fencing the rectangular field D?
यदि फर्श की लागत 15 रुपये / सेमी ^ 2 है और बाड़ लगाने की लागत 25 रुपये / सेमी है, तो आयताकार क्षेत्र D की बाड़ लगाने की लागत के लिए आयताकार क्षेत्र A फर्श की लागत का अनुपात क्या है?
a) 9: 7

b) 7: 5

c) 11: 9

d) 4: 3

e) None of these

3) There is an empty rectangular pool B of water and a tap is opened to fill the water into the pool. If the tap can fill the water up to a height of 5 cm in 12 minutes, then at what rate (litre/hour) the tap is filling the water in the pool?
पानी का एक खाली आयताकार पूल B है और पूल में पानी भरने के लिए एक नल खोला जाता है। यदि नल 12 मिनट में 5 सेमी की ऊंचाई तक पानी भर सकता है, तो नल किस दर (लीटर / घंटा) पर पूल में पानी भर रहा है?
a) 10

b) 12

c) 9

d) 6

e) None of these

4) A rectangular pool F is filled with water up to a height of 22 cm. If the pool is emptied by using a cylindrical bucket of base radius 3.5 cm and depth 12 cm, then how many such buckets are needed to be emptied the pool completely?
एक आयताकार पूल F 22 सेमी की ऊंचाई तक पानी से भरा है। यदि आधार त्रिज्या 3.5 सेमी और गहराई 12 सेमी के बेलनाकार बाल्टी का उपयोग करके पूल को खाली किया जाता है, तो पूल को पूरी तरह से खाली करने के लिए ऐसे कितने बाल्टी की आवश्यकता होती है?
a) 10

b) 25

c) 30

d) 20

e) None of these

5) If the pools A and C are filled up to a height of 3 cm and 2.75 cm respectively and pool D is initially empty, whole volume of water from the pool A and C are poured into pool D. Similarly, pools E and B are filled up to a height of 5 cm and 12.25 cm respectively and pool F is initially empty and water from pools E and B are poured into pool F, then what is the ratio of height of water in pool D to that in pool F?
यदि पूल A और C क्रमशः 3 सेमी और 2.75 सेमी की ऊंचाई तक भरे हुए हैं और पूल D शुरू में खाली है, तो पूल A और C से पानी की पूरी मात्रा पूल D में डाली जाती है। इसी तरह, पूल ई और B भरे जाते हैं। क्रमशः 5 सेमी और 12.25 सेमी की ऊंचाई तक और पूल एफ शुरू में खाली है और पूल ई और B से पानी पूल एफ में डाला जाता है, फिर पूल F में पूल D में पानी की ऊंचाई का अनुपात क्या है?
a) 7: 5

b) 9: 7

c) 5: 3

d) 11: 8

e) None of these

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Length of one side of rectangle A = 120 * (36/360) = 12 cm

Length of another side of rectangle A = 41(2/3)% of 12 = 5 cm

Length of one side of rectangle B = 120 * (120/360) = 40 cm

Length of another side of rectangle B = 22.5% of 40 = 9 cm

Length of one side of rectangle C = 120 * (72/360) = 24 cm

Length of another side of rectangle C = 41(2/3)% of 24 = 10 cm

Length of one side of rectangle D = 120 * (24/360) = 8 cm

Length of another side of rectangle D = 75% of 8 = 6 cm

Length of one side of rectangle E = 120 * (72/360) = 24 cm

Length of another side of rectangle E = 29(1/6)% of 24 = 7 cm

Length of one side of rectangle F = 120 * (36/360) = 12 cm

Length of another side of rectangle F = 291(2/3)% of 12 = 35 cm



1) Answer: b)

Area of field C = 24 * 10 = 240 cm2

Base area of cylindrical pit = (22/7) * 72 = 154 cm2

Remaining area of the filed = 240 – 154 = 86 cm2

Volume of the soil coming out after digging the pit = (22/7) * 72 * 8.6 = 1324.4 cm3

Increment in the level of the filed = 1324.4/86 = 15.4 cm

2) Answer: a)

Area of field A = 12 * 5 = 60 cm2

Cost of flooring the rectangular field A = 15 * 60 = Rs.900

Perimeter of field D = 2 * (8 + 6) = 28 cm

Cost of fencing the rectangular field D = 28 * 25 = Rs.700

Required ratio = 900: 700 = 9: 7

3) Answer: c)

Base area of pool B = 40 * 9 = 360 cm2

Volume of the water in tank after 12 minutes = 360 * 5 = 1800 cm3 = 1.8 litres

Let the rate at which tap is filling the pool = ‘x’ litres/hour

According the question:

x * (12/60) = 1.8

x = (1.8 * 60)/12

x = 9 litres/hour

4) Answer: d)

Total volume of water in the pool F when it is filled up to height of 22 cm = (12 * 35 * 22) cm3

Volume of 1 such bucket = (22/7) * 3.52 * 12 = (22 * 21) cm3

Let number of such buckets needed = ‘N’

According to the question:

(22 * 21) * N = (12 * 35 * 22)

N = (12 * 35 * 22)/(22 * 21)

N = 20

5) Answer: a)

Let the height of water in pool D and F is ‘x’ and ‘y’ respectively.

Total volume of water in pool D = Total volume of water in pools A and C

= (12 * 5 * 3) + (24 * 10 * 2.75)

(8 * 6 * x) = 180 + 660

48x = 840

x = 17.5 cm

Total volume of water in pool F = Total volume of water in pools E and B = (24 * 7 * 5) + (40 * 9 * 12.25)

(12 * 35 * y) = 840 + 4410

420y = 5250

y = 12.5 cm

Required ratio = x: y = 17.5: 12.5 = 7: 5

The following radar graph shows the total number of students studied in two different schools in 6 different years.

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6) Find the difference between the total number of students studied in School P in the year 2013 and 2015 together to that of total number of students studied in School Q in the year 2014 and 2017 together?
वर्ष 2013 और 2015 में स्कूल P में अध्ययनरत कुल छात्रों की कुल संख्या के बीच का अंतर ज्ञात कीजिए
वर्ष 2014 और 2017 में एक साथ स्कूल Q में अध्ययनरत छात्रों की संख्या?
a) 200

b) 250

c) 150

d) 300

e) None of these

7) Find the average number of students studied in School P in all the given years together?
दिए गए सभी वर्षों में स्कूल P में अध्ययनरत छात्रों की औसत संख्या ज्ञात कीजिए?
a) 1700

b) 1400

c) 1250

d) 1350

e) None of these

8) Find the ratio between the total numbers of students studied in School Q in 2013 to that of total number of students studied in School P in 2016?
2013 में स्कूल क्यू में पढ़े छात्रों की कुल संख्या और 2016 में स्कूल पी में अध्ययनरत कुल छात्रों के बीच का अनुपात ज्ञात कीजिए?
a) 1 : 3

b) 5 : 7

c) 4 : 5

d) 9 : 11

e) None of these

9) Total number of students studied in School Q in the year 2015 and 2016 together is approximately what percentage of total number of students studied in School P in the year 2014 and 2018 together?
वर्ष 2015 और 2016 में एक साथ स्कूल Q में अध्ययनरत छात्रों की कुल संख्या, स्कूल P में वर्ष में अध्ययनरत छात्रों की कुल संख्या का कितना प्रतिशत है
2014 और 2018 एक साथ?
a) 115 %

b) 144 %

c) 162 %

d) 106 %

e) 128 %

10) Find the difference between the average number of students studied in School P in the year 2013, 2015 and 2018 together to that of the average number of students studied in School Q in the year 2013, 2014 and 2017 together?
वर्ष 2013, 2015 और 2018 में स्कूल पी में पढ़े छात्रों की औसत संख्या के बीच का अंतर ज्ञात कीजिए
वर्ष 2013, 2014 और 2017 में एक साथ स्कूल क्यू में पढ़ने वाले छात्रों की औसत संख्या?
a) 200

b) 300

c) 250

d) 100

e) None of these

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6) Answer: A

The total number of students studied in School P in the year 2013 and 2015 together

= > 1800 + 1300 = 3100

The total number of students studied in School Q in the year 2014 and 2017 together

= > 1500 + 1800 = 3300

Required difference = 3300 – 3100 = 200

7) Answer: E

The average number of students studied in School P in all the given years together

= > [1800 + 1400 + 1300 + 1500 + 1600 + 1700] / 6

= > [9300 / 6] = 1550

8) Answer: C

The total number of students studied in School Q in 2013 = 1200

The total number of students studied in School P in 2016 = 1500

Required ratio = 1200: 1500 = 4: 5

9) Answer: D

Total number of students studied in School Q in the year 2015 and 2016 together

= > 1600 + 1700 = 3300

Total number of students studied in School P in the year 2014 and 2018 together

= > 1400 + 1700 = 3100

Required % = (3300 / 3100) * 100 = 106.45 % = 106 %

10) Answer: D

The average number of students studied in School P in the year 2013, 2015 and 2018 together

= > (1800 + 1300 + 1700) / 3 = 1600

The average number of students studied in School Q in the year 2013, 2014 and 2017 together

= > (1200 + 1500 + 1800) / 3 = 1500

Required difference = 1600 – 1500 = 100

Three persons X, Y, Z have undertaken the five different works A, B, C, D, and E as they can complete the work alone shown in the graph.

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6) X and Y started the work A and work for two days and then Y left , after that X and Z take over the work and works alternatively, then in how many days the total work has completed?
X और Y ने काम A शुरू किया और दो दिन काम किया और फिर Y छोड़ दिया, उसके बाद X और Z ने काम संभाला और वैकल्पिक रूप से काम किया, फिर कुल काम कितने दिनों में पूरा हुआ?
a) 11 3/5 days

b) 09 2/5 days

c) 10 3/5 days

d) 11 2/5 days

e) 12 2/5 days

7) Work C is completed by X and Z in the ratio of 1:3 then what is the difference between the number of days taken by them if they worked alone while they completed their part of work C?
कार्य C, X और Z द्वारा 1: 3 के अनुपात में पूरा किया जाता है, तब उनके द्वारा लिए गए दिनों की संख्या में क्या अंतर होता है यदि उन्होंने अपना काम C पूरा कर लिया है?
a) 16 days

b) 28 days

c) 10 days

d) 24 days

e) 25 days

8) How many days P alone can complete the work E?
P अकेले कितने दिनों में काम पूरा कर सकता है?

Statement I: P takes twice the time to complete the work A.
कथन I: P काम को पूरा करने में दोगुना समय लेता है।

Statement II: Q takes twice time as X to complete the wok E.
कथन II: Q, W को E पूरा करने के लिए X से दोगुना समय लेता है।

Statement III: If P and Q can complete the work E in 9 days.
कथन III: यदि P और Q कार्य E को 9 दिनों में पूरा कर सकते हैं।

A) If the data in statement I and II are sufficient to answer the question, while the data in statement III are not sufficient to answer the question.

B) If the data in statement I alone or in the statement II alone or in the statement III alone is sufficient to answer the question.

C) If the data in statement I and III are sufficient to answer the question, while the data in statement II is not sufficient to answer the question.

D) If the data in statement II and III are sufficient to answer the question, while the data in statement I is not sufficient to answer the question.

E) If the data in all the statement I, II and III are necessary to answer the question

9) If R alone completes the work A in 10 days and S alone can complete the work B is equal to the 1/4th of the time taken by Z to complete the work C. If R and S work alternatively then how many days they take to complete the work E if work started by R?
यदि R अकेले काम को A को 10 दिनों में पूरा करता है और S अकेले काम पूरा कर सकता है, B, C को पूरा करने के लिए Z द्वारा लिए गए समय के 1 / 4th के बराबर है। यदि R और S वैकल्पिक रूप से काम करते हैं, तो उन्हें कितने दिन लगते हैं R से काम शुरू होने पर काम पूरा करें?
a) 5 (3/5) days

b) 8 (3/4) days

c) 6 (3/5) days

d) 5 (3/4) days

e) 10 (2/3) days

10) Quantity I: Z started the work E and left after five days. Then X is continuing that work and completed the reaming work.In how many days the total work has completed?
मात्रा I: Z ने काम E शुरू किया और पांच दिनों के बाद छोड़ दिया। तब X उस काम को जारी रखे हुए है और रीमिंग का काम पूरा कर लिया है। कुल काम कितने दिनों में पूरा हुआ है?

Quantity II: Y started the work B for 5 days and left then Z complete the remaining work. In how many days the total work has completed?
मात्रा II: Y ने कार्य B को 5 दिनों के लिए शुरू किया और तब Z ने शेष कार्य पूरा किया। कुल कार्य कितने दिनों में पूरा हुआ?
a) Quantity I < Quantity II

b) Quantity I > Quantity II

c) Quantity I ≥ Quantity II

d) Quantity I ≤ Quantity II

e) Quantity I = Quantity II or relationship cannot be established

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6) Answer: c)

LCM of number of Days for work A done by X, Y, Z alone is 120, consider this is the total parts of work.

Efficiency of work per day for X, Y, Z is in the ratio of 10:15:6

For the first two days 50 parts of total work has completed

Remaining 70 parts are done by X and Z in alternative days. so every two days,16 parts completed

After (8 days) 4 full cycle, 4* 16=64 parts completed 6 parts remained

X again start the work and completed in 3/5 days

So the work completed in 10 3/5 days

7) Answer: d)
LCM of Days for work C is done by X, Y, Z alone is240, consider this is the total part of work.

Efficiency of work per day for X, Y, Z is in the ratio of 10:15:6

Work done by X and Z individually is 60 and 180 parts respectively

X completed its 60 parts in 60/10= 6 days

Z completed its 180 parts in180/6= 30 days

The difference between the number of days is 24.

8) Answer: d)

Statement I: we cannot compare work A and work E and solve it.

Statement II: From the chart, LCM of number Days for work E done by X, Y, Z alone is 90, and Efficiency is in the ratio of 10: 15: 6 for X: Y: Z Respectively and Q can complete the work in 18 days.

By combining, statement II and Statement III,

Total parts per day* Number of Days = Total Parts of Work

(5+P) 9= 90

P=5 parts per day

So P alone can complete the work in 18 days.

9) Answer: c)

LCM of number of Days for work A done by X, Y, Z and R alone is 120, consider this is the total part of work A

The Efficiency of R is 12 parts per day

S takes ¼th of total time by Z for work C= 10 days

LCM of Days for work B done by X, Y, Z and S alone is 150, consider this is the total part of work B

The Efficiency of S is 15 parts per day

LCM of Days for work E done by X, Y, Z alone is 90, consider this is the total part of work E

For every two days they completed 27 parts

After the 3 full cycles (6 days) they completed 27*3 = 81 parts, reaming 9 parts done by S in 3/5 of a Day

So the total work is completed in 6 3/5 days.

10) Answer: a)

Quantity I:

LCM of Days for work E done by X, Y, Z alone is 90, consider this is the total part of work E

Efficiency of work per day for X, Y, Z is in the ratio of 10: 15: 6

Total parts per day* Number of Days = Total Parts of Work

6*5 + 10 XD= 90

XD= 6

So total number of days is 11 days

Quantity II:

LCM of Days for work B done by X, Y, Z and S alone is 150, consider this is the total part of work B

Efficiency of work per day for X, Y, Z is in the ratio of 10:15:6

Total parts per day* Number of Days = Total Parts of Work

15*5 + 6 * ZD= 150

ZD = 12.5, So total number of days is 17.5 days

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