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тЧПGood MorningтЧП 16-3-21

тЧЖDaily The Hindu VocabularyтЧЖ

1. EQUILIBRIUM (NOUN): (рд╢рд╛рдВрддрд┐): calm
Synonyms: calmness, composure
Antonyms: agitation
Example Sentence:His intense behaviour could unsettle his equilibrium.


2 CREDIBILITY (NOUN) (рд╡рд┐рд╢реНрд╡рд╕рдиреАрдпрддрд╛): plausibility
Synonyms: believability, acceptability
Antonyms: implausibility
Example Sentence:The book's anecdotes have scant regard for credibility.


3. PURSUE (VERB): (рд╕рдВрдЪрд╛рд▓рд┐рдд рдХрд░рдирд╛): conduct
Synonyms: undertake, follow
Antonyms: give up
Example Sentence:We shall not pursue the matter any further.


4. VIRTUOUS (ADJECTIVE): (рдиреНрдпрд╛рдп рдкрд░рд╛рдпрдг): righteous
Synonyms: good, moral
Antonyms: bad
Example Sentence:He considered himself very virtuous because he neither drank nor smoked.


5. DWINDLE (VERB): (рдХреНрд╖реАрдг рд╣реЛрдирд╛): diminish
Synonyms: decrease, reduce
Antonyms: increase
Example Sentence:The majorities behind the government dwindled and grew.


6. ANTIPATHY (NOUN): (рд╡рд┐рд░реЛрдзрднрд╛рд╡): hostility
Synonyms: antagonism, animosity
Antonyms: liking
Example Sentence:He certainly had antipathy to capitalism.


7. IMPLICATION (NOUN): (рдирд┐рд╣рд┐рддрд╛рд░реНрде): suggestion
Synonyms: inference, insinuation
Antonyms: explicit statement
Example Sentence:The implication is that no one person at the bank is responsible.


8. INTERIM (ADJECTIVE): (рдЕрдВрддрд░рд┐рдо): provisional
Synonyms: temporary, pro tem
Antonyms: permanent
Example Sentence:An interim arrangement was made.


9. FLICKER (VERB): (рдЯрд┐рдордЯрд┐рдорд╛рдирд╛): glimmer
Synonyms: glint, gleam
Antonyms: burn steadily
Example Sentence:The interior lights flickered, and came on.


10. CAPTIVATE (VERB): (рдореЛрд╣ рд▓реЗрдирд╛): enthrall
Synonyms: charm, enchant
Antonyms: repel
Example Sentence:He was captivated by her beauty.

Join @practice_note
DI SET DAY - 37тЭДя╕П
Read the following information carefully and answer the following questions carefully.

ЁЯСЙJoin @practice_note
1. Inlet pipes A, B and outlet pipe S took 10 hours to fill the empty tank then find how much time Pipe S will take to empty a full tank?
рдЦрд╛рд▓реА рдЯреИрдВрдХ рдХреЛ рднрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдЗрдирд▓реЗрдЯ рдкрд╛рдЗрдк A, B рдФрд░ рдЖрдЙрдЯрд▓реЗрдЯ рдкрд╛рдЗрдк S рдХреЛ 10 рдШрдВрдЯреЗ рдХрд╛ рд╕рдордп рд▓рдЧрддрд╛ рд╣реИ, рдлрд┐рд░ рдкрд╛рддреЗ рд╣реИрдВ рдХрд┐ рдкрд╛рдЗрдк S рдХреЛ рдПрдХ рдкреВрд░реНрдг рдЯреИрдВрдХ рдХреЛ рдЦрд╛рд▓реА рдХрд░рдиреЗ рдореЗрдВ рдХрд┐рддрдирд╛ рд╕рдордп рд▓рдЧреЗрдЧрд╛?
a) 24(1/9)

b) 18(7/13)

c) 18(6/23)

d) 1(2/7)

e) 4(8/9)

2. Inlet pipe E and outlet pipe Q can fill the empty tank in 42 hours then how much time is required for inlet pipe C if it is opened with outlet Q to fill the tank?
рдЗрдирд▓реЗрдЯ рдкрд╛рдЗрдк E рдФрд░ рдЖрдЙрдЯрд▓реЗрдЯ рдкрд╛рдЗрдк Q 42 рдШрдВрдЯреЗ рдореЗрдВ рдЦрд╛рд▓реА рдЯреИрдВрдХ рдХреЛ рднрд░ рд╕рдХрддреЗ рд╣реИрдВ рдлрд┐рд░ рдЗрдирд▓реЗрдЯ рдкрд╛рдЗрдк C рдХреЗ рд▓рд┐рдП рдХрд┐рддрдирд╛ рд╕рдордп рдЪрд╛рд╣рд┐рдП рдЕрдЧрд░ рдЗрд╕реЗ рдЯреИрдВрдХ рдХреЛ рднрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдЖрдЙрдЯрд▓реЗрдЯ Q рд╕реЗ рдЦреЛрд▓рд╛ рдЬрд╛рдП?
a) 24(1/9)

b) 18(7/13)

c) 15(3/4)

d) 21(21/29)

e) 4(8/9)

3. Inlet pipes B, C and D were opened to fill tank so after how much time pipe C should be closed so that the tank gets filled in 8 hours?
рдЗрдирд▓реЗрдЯ рдкрд╛рдЗрдк B, C рдФрд░ D рдХреЛ рдЯреИрдВрдХ рднрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдЦреЛрд▓рд╛ рдЧрдпрд╛ рдерд╛ рддрд╛рдХрд┐ рдХрд┐рддрдиреЗ рд╕рдордп рдмрд╛рдж рдкрд╛рдЗрдк C рдХреЛ рдмрдВрдж рдХрд┐рдпрд╛ рдЬрд╛рдП рддрд╛рдХрд┐ рдЯреИрдВрдХ 8 рдШрдВрдЯреЗ рдореЗрдВ рднрд░ рдЬрд╛рдП?
a) 24(1/9)

b) 18(7/13)

c) 1(5/7)

d) 1(2/7)

e) 4(8/9)

4.Pipe F was opened alternatively with pipe T for one hour starting with F then find how much time will be required to fill the empty tank, if pipe F is three times efficeint as pipe T.
рдкрд╛рдЗрдк рдПрдл рдХреЛ рд╡реИрдХрд▓реНрдкрд┐рдХ рд░реВрдк рд╕реЗ рдПрдл рдХреЗ рд╕рд╛рде рд╢реБрд░реВ рд╣реЛрдиреЗ рд╡рд╛рд▓реЗ рдПрдХ рдШрдВрдЯреЗ рдХреЗ рд▓рд┐рдП рдкрд╛рдЗрдк рдЯреА рдХреЗ рд╕рд╛рде рдЦреЛрд▓рд╛ рдЧрдпрд╛ рдерд╛, рдлрд┐рд░ рдЦрд╛рд▓реА рдЯреИрдВрдХ рдХреЛ рднрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдХрд┐рддрдирд╛ рд╕рдордп рд▓рдЧреЗрдЧрд╛,
рдпрджрд┐ рдкрд╛рдЗрдк F, рдкрд╛рдЗрдк T рдХреЗ рд░реВрдк рдореЗрдВ рддреАрди рдЧреБрдирд╛ рд╣реИред

a) 25

b) 18

c) 15

d) 24

e) 48

5. The time taken by inlet pipe D and outlet pipe P to fill the tank is 2 hours less than time taken by inlet pipe C and outlet S to fill the tank then find the time required by outlet pipe S to empty the full tank if the outlet pipe P can empty the full tank in 40 hours?
рдЯреИрдВрдХ рдХреЛ рднрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдЗрдирд▓реЗрдЯ рдкрд╛рдЗрдк D рдФрд░ рдЖрдЙрдЯрд▓реЗрдЯ рдкрд╛рдЗрдк P рджреНрд╡рд╛рд░рд╛ рд▓рд┐рдпрд╛ рдЧрдпрд╛ рд╕рдордп рдЗрдирд▓реЗрдЯ рдкрд╛рдЗрдк C рдФрд░ рдЖрдЙрдЯрд▓реЗрдЯ S рджреНрд╡рд╛рд░рд╛ рдЯреИрдВрдХ рдХреЛ рднрд░рдиреЗ рдореЗрдВ рд▓рдЧрдиреЗ рд╡рд╛рд▓реЗ рд╕рдордп рд╕реЗ 2 рдШрдВрдЯреЗ рдХрдо рд╣реИ рддреЛ рдЖрдЙрдЯрд▓реЗрдЯ рдкрд╛рдЗрдк S рджреНрд╡рд╛рд░рд╛ рдкреВрд░рд╛ рдЯреИрдВрдХ рдЦрд╛рд▓реА рдХрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдЖрд╡рд╢реНрдпрдХ рд╕рдордп рдЬреНрдЮрд╛рдд рдХрд░реЗрдВ рдпрджрд┐ рдЖрдЙрдЯрд▓реЗрдЯ рдкрд╛рдЗрдк P 40 рдШрдВрдЯреЗ рдореЗрдВ рдкреВрд░рд╛ рдЯреИрдВрдХ рдЦрд╛рд▓реА рдХрд░ рд╕рдХрддрд╛ рд╣реИ?

a) 24(1/9)

b) 25(4/11)

c) 15(3/4)

d) 1(2/7)

e) 4(8/9)

ЁЯСЙJoin @practice_note
1.Answer c
Total units of work= 420

AтАЩs one hour work= 35 units

BтАЩs one hour work= 30 units

A+B+S= 42 units

Units of work done by S in one hour= 65- 42= 23 units

Time required by S to empty the tank= 420/23= 18(6/23) hours.

2.Answer d
Total units of work= 210 units

EтАЩs one hour work= 7 units

QтАЩs and EтАЩs one hour work= 5 units

Work done by Q in an hour= 7-5= 2 units

Time required by Q to empty the tank= 210/2= 105 hours.

Total units of work= 630

QтАЩs one work= 6 units

CтАЩs one hour work= 35 units

QтАЩs and CтАЩs one hour work= 35 тАУ 6 = 29 units

Time required= 630/29= 21(21/29) hours.

3.Answer c
Total units of work= 504

BтАЩs one hour work= 36 units

CтАЩs one hours work= 28 units

DтАЩs one hour work= 21 units

Work done by B and D in 8 hours= (36+21)*8= 456 units

Units of work remaining= 504-456= 48 units

Time after which pipe C should be closed= 48/28= 1(5/7) hours.

4.Answer d
Efficiency ratio of F and T = 3: 1

Time ratio of F and T = 1: 3

T takes 48 days to complete the whole work

Total units of work= 48 units

FтАЩs one hour work= 3 units

TтАЩs one hour work= 1 units

Work done by pipe F and T in 2 hours= 3+1= 4 units

Work done in 24 hours= 4*12= 48 units

So the time required to fill the tank= 24 hours.

5.Answer b
Total units of work= 120 units

DтАЩs one hour work= 5 units

PтАЩs one hour work= 3 units

Work done by D and P in one hour= 5-3= 2 units

Time taken by D and P to fill the tank = 120/2= 60 hours

Time taken by C and S to fill the tank= 62 hours

Time taken by C to fill the tank = 18 hours

Total units of work= 558 units (LCM of 18 and 62)

Work done by pipe C = 31 units

Work done by pipe C and S= 9 units

Work done by pipe S= 31-9= 22 units

Time required by pipe S to fill the tank= 558/22= 25(4/11) hours.
The following bar graph represents number of days taken by husbands and wives of six different families to complete a piece of work.

рдирд┐рдореНрдирд▓рд┐рдЦрд┐рдд рдмрд╛рд░ рдЧреНрд░рд╛рдл рдХрд╛рдо рдХреЗ рдПрдХ рдЯреБрдХрдбрд╝реЗ рдХреЛ рдкреВрд░рд╛ рдХрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдЫрд╣ рдЕрд▓рдЧ-рдЕрд▓рдЧ рдкрд░рд┐рд╡рд╛рд░реЛрдВ рдХреЗ рдкрддрд┐ рдФрд░ рдкрддреНрдирд┐рдпреЛрдВ рджреНрд╡рд╛рд░рд╛ рд▓рд┐рдП рдЧрдП рджрд┐рдиреЛрдВ рдХреА рд╕рдВрдЦреНрдпрд╛ рдХрд╛ рдкреНрд░рддрд┐рдирд┐рдзрд┐рддреНрд╡ рдХрд░рддрд╛ рд╣реИред

ЁЯСЙJoin @practice_note
6.If the husband of Sharma, Chaudhary and Singh family works together, in how many days the work will be completed?
рдпрджрд┐ рд╢рд░реНрдорд╛, рдЪреМрдзрд░реА рдФрд░ рд╕рд┐рдВрд╣ рдкрд░рд┐рд╡рд╛рд░ рдХреЗ рдкрддрд┐ рдПрдХ рд╕рд╛рде рдХрд╛рдо рдХрд░рддреЗ рд╣реИрдВ, рддреЛ рдХрд╛рдо рдХрд┐рддрдиреЗ рджрд┐рдиреЛрдВ рдореЗрдВ рдкреВрд░рд╛ рд╣реЛрдЧрд╛?

a) 4(54/143) days

b) 4(58/143) days

c) 3(58/143) days

d) 4(58/141) days

e) None of these

7.Time taken by Malhotara family to complete the work is what percent of the time taken by Banerjee family to complete the work?
рдХрд╛рдо рдкреВрд░рд╛ рдХрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдорд▓реНрд╣реЛрддреНрд░рд╛ тАЛтАЛрдкрд░рд┐рд╡рд╛рд░ рджреНрд╡рд╛рд░рд╛ рд▓рд┐рдпрд╛ рдЧрдпрд╛ рд╕рдордп рдХрд╛рдо рдкреВрд░рд╛ рдХрд░рдиреЗ рдХреЗ рд▓рд┐рдП рдмрдирд░реНрдЬреА рдкрд░рд┐рд╡рд╛рд░ рджреНрд╡рд╛рд░рд╛ рд▓рд┐рдпрд╛ рдЧрдпрд╛ рд╕рдордп рдХрд╛ рдХрд┐рддрдирд╛ рдкреНрд░рддрд┐рд╢рдд рд╣реИ?

a) 200%

b) 220%

c) 280%

d) 100%

e) None of these

8.If Banerjee family and Chaudhary family works together, in how many days the work will get complete?
рдЕрдЧрд░ рдмрдирд░реНрдЬреА рдкрд░рд┐рд╡рд╛рд░ рдФрд░ рдЪреМрдзрд░реА рдкрд░рд┐рд╡рд╛рд░ рдПрдХ рд╕рд╛рде рдХрд╛рдо рдХрд░рддреЗ рд╣реИрдВ, рддреЛ рдХрд╛рдо рдХрд┐рддрдиреЗ рджрд┐рдиреЛрдВ рдореЗрдВ рдкреВрд░рд╛ рд╣реЛ рдЬрд╛рдПрдЧрд╛?
a) 5(4/167) days

b) 4(4/167) days

c) 3(4/167) days

d) 4(3/167) days

e) None of these

9.If the husband of Chaudhary family worked for 3 days and then left, in how many days Deshmukh family can complete the remaining work?
рдпрджрд┐ рдЪреМрдзрд░реА рдкрд░рд┐рд╡рд╛рд░ рдХреЗ рдкрддрд┐ рдиреЗ 3 рджрд┐рди рдХрд╛рдо рдХрд┐рдпрд╛ рдФрд░ рдлрд┐рд░ рдЫреЛрдбрд╝ рджрд┐рдпрд╛, рддреЛ рджреЗрд╢рдореБрдЦ рдкрд░рд┐рд╡рд╛рд░ рдХрд┐рддрдиреЗ рджрд┐рдиреЛрдВ рдореЗрдВ рд╢реЗрд╖ рдХрд╛рдо рдкреВрд░рд╛ рдХрд░ рд╕рдХрддрд╛ рд╣реИ?

a) 7(19/35) days

b) 5(19/35) days

c) 3(19/35) days

d) 5(19/35) days

e) None of these

10.Find the time required by wife of all the families to complete the work.
рдХрд╛рд░реНрдп рдХреЛ рдкреВрд░рд╛ рдХрд░рдиреЗ рдХреЗ рд▓рд┐рдП рд╕рднреА рдкрд░рд┐рд╡рд╛рд░реЛрдВ рдХреА рдкрддреНрдиреА рджреНрд╡рд╛рд░рд╛ рдЖрд╡рд╢реНрдпрдХ рд╕рдордп рдХрд╛ рдкрддрд╛ рд▓рдЧрд╛рдПрдВред

a) 3(7/17) days

b) 3(9/17) days

c) 3(7/17) days

d) 4(9/17) days

e) None of these

ЁЯСЙJoin @practice_note
6.Answer b
Let the work will be completed in x days.

X (1/10 + 1/14 + 1/18) = 1

=> x (63 + 45 + 35)/630 = 1

=> x = 630/143 = 4(58/143) days

7..Answer a
Let the time taken by Malhotara family to complete the work = x days

Let the time taken by Banerjee family to complete the work = y days

X (1/24 + 1/32) = 1

=> x(4 + 3)/96 = 1

=> x = 96/7

Y(1/12 + 1/16) = 1

=> y(4 + 3)/48 = 1

=> y = 48/7

Required percentage = [(96/7)/(48/7)] x 100 = 200%

8.Answer b
Let the work will get complete in x days.

x(1/12 + 1/16 + 1/14 + 1/32) = 1

=> x(56 + 42 + 48 + 21)/672 = 1

=> x = 672/167 days = 4(4/167) days

9.Answer a
Let Deshmukh family can complete the remaining work in x days.

3/14 + x (1/16 + 1/24) = 1

=> x (3 + 2)/48 = 11/14

=> x = 264/35 days = 7(19/35) days

10.Answer b
Let the time taken by wife of all the families to complete the work = x days

X (1/12 + 1/32 + 1/16 + 1/32 + 1/24 + 1/30) = 1

=> x (40 + 15 + 30 + 15 + 20 + 16)/480 = 1

=> x = 480/136

=> x = 60/17 = 3(9/17) days
The following table represents percentage of marks obtained by six different students in six different subjects and maximum marks of each subject.

рдирд┐рдореНрди рддрд╛рд▓рд┐рдХрд╛ рдЫрд╣ рдЕрд▓рдЧ-рдЕрд▓рдЧ рдЫрд╛рддреНрд░реЛрдВ рджреНрд╡рд╛рд░рд╛ рдЫрд╣ рдЕрд▓рдЧ-рдЕрд▓рдЧ рд╡рд┐рд╖рдпреЛрдВ рдореЗрдВ рдкреНрд░рд╛рдкреНрдд рдЕрдВрдХреЛрдВ рдХрд╛ рдкреНрд░рддрд┐рд╢рдд рдФрд░ рдкреНрд░рддреНрдпреЗрдХ рд╡рд┐рд╖рдп рдХреЗ рдЕрдзрд┐рдХрддрдо рдЕрдВрдХреЛрдВ рдХрд╛ рдкреНрд░рддрд┐рдирд┐рдзрд┐рддреНрд╡ рдХрд░рддреА рд╣реИред

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1. Marks obtained by Madan in Hindi is what percent of marks obtained by Krishna in General Knowledge?
рдорджрди рджреНрд╡рд╛рд░рд╛ рд╣рд┐рдВрджреА рдореЗрдВ рдкреНрд░рд╛рдкреНрдд рдЕрдВрдХ рд╕рд╛рдорд╛рдиреНрдп рдЬреНрдЮрд╛рди рдореЗрдВ рдХреГрд╖реНрдг рджреНрд╡рд╛рд░рд╛ рдкреНрд░рд╛рдкреНрдд рдЕрдВрдХреЛрдВ рдХрд╛ рдкреНрд░рддрд┐рд╢рдд рдХреНрдпрд╛ рд╣реИ?
a) 35.62%

b) 31.25%

c) 21.22%

d) 16.25%

e) None of these

2. Find the total marks obtained by all the students in Science.
рд╡рд┐рдЬреНрдЮрд╛рди рдореЗрдВ рд╕рднреА рдЫрд╛рддреНрд░реЛрдВ рджреНрд╡рд╛рд░рд╛ рдкреНрд░рд╛рдкреНрдд рдХреБрд▓ рдЕрдВрдХ рдкреНрд░рд╛рдкреНрдд рдХрд░реЗрдВред
a) 465

b) 645

c) 654

d) 456

e) None of these

3. Find the overall percentage of marks obtained by Kunal in all the subjects.
рд╕рднреА рд╡рд┐рд╖рдпреЛрдВ рдореЗрдВ рдХреБрдгрд╛рд▓ рджреНрд╡рд╛рд░рд╛ рдкреНрд░рд╛рдкреНрдд рдЕрдВрдХреЛрдВ рдХрд╛ рдХреБрд▓ рдкреНрд░рддрд┐рд╢рдд рдЬреНрдЮрд╛рдд рдХреАрдЬрд┐рдПред

a) 45%

b) 76%

c) 74%

d) 67%

e) None of these

4. Find the respective ratio of marks obtained by Nitin in Science, Maths and English together and marks obtained by Mohan in Hindi, Social Science and General Knowledge together.
рд╡рд┐рдЬреНрдЮрд╛рди, рдЧрдгрд┐рдд рдФрд░ рдЕрдВрдЧреНрд░реЗрдЬреА рдореЗрдВ рдирд┐рддрд┐рди рджреНрд╡рд╛рд░рд╛ рдкреНрд░рд╛рдкреНрдд рдЕрдВрдХреЛрдВ рдХреЗ рд╕рдВрдмрдВрдзрд┐рдд рдЕрдиреБрдкрд╛рдд рдФрд░ рд╕рд╛рде рдореЗрдВ рд╣рд┐рдВрджреА, рд╕рд╛рдорд╛рдЬрд┐рдХ рд╡рд┐рдЬреНрдЮрд╛рди рдФрд░ рд╕рд╛рдорд╛рдиреНрдп рдЬреНрдЮрд╛рди рдореЗрдВ рдореЛрд╣рди рджреНрд╡рд╛рд░рд╛ рдкреНрд░рд╛рдкреНрдд рдЕрдВрдХреЛрдВ рдХрд╛ рдкрддрд╛ рд▓рдЧрд╛рдПрдВред

a) 455 : 344

b) 344 : 455

c) 341 : 435

d) 134 : 344

e) None of these

5. Find the difference between total marks obtained by Krishna and Rohan in all the subjects together.
рдХреГрд╖реНрдг рдФрд░ рд░реЛрд╣рди рджреНрд╡рд╛рд░рд╛ рд╕рднреА рд╡рд┐рд╖рдпреЛрдВ рдореЗрдВ рдПрдХ рд╕рд╛рде рдкреНрд░рд╛рдкреНрдд рдХрд┐рдП рдЧрдП рдХреБрд▓ рдЕрдВрдХреЛрдВ рдХреЗ рдмреАрдЪ рдХрд╛ рдЕрдВрддрд░ рдЬреНрдЮрд╛рдд рдХрд░реЗрдВред

a) 135

b) 154.25

c) 145.5

d) 125.75

e) None of these

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1.Answer: b
Marks obtained by Madan in Hindi = 55/100 x 125 = 68.75

Marks obtained by Krishna in General Knowledge = 88/100 x 250 = 220

Required percentage = 68.75/220 x 100 = 31.25%

2.Answer: b
Total marks obtained by all the students in Science

= (60 + 45 + 86 + 65 + 84 + 90) * 150/100

= 430 x 150/100 = 645

3.Answer: b
Marks obtained by Kunal in,

Science = (86/100) x 150 = 129

Maths = (95/100) x 200 = 190

English = (48/100) x 100 = 48

Hindi = (86/100) x 125 = 107.5

Social Science = (68/100) x 125 = 85

General Knowledge = (65/100) x 250 = 162.5

Overall percentage

= [(129 + 190 + 48 + 107.5 + 85 + 162.5)/(150 + 200 + 100 + 125 + 125 + 250)] x 100

= 722/950 x 100 = 76%

4.Answer: b
Marks obtained by Nitin in:

Science = (60/100) x 150 = 90

Maths = (85/100) x 200 = 170

English = (84/100) x 100 = 84

Marks obtained by Mohan in:

Hindi = (92/100) x 125 = 115

Social Science = (92/100) x 125 = 115

General Knowledge = (90/100) x 250 = 225

Required ratio = (90 + 170 + 84) : (115 + 115 + 225) = 344 : 455

5.Answer: b
Marks obtained by Krishna in all the subjects

= (65/100) x 150 + (45/100) x 200 + (65/100) x 100 + (48/100) x 125 + (78/100) x 125 + (88/100) x 250

= 97.5 + 90 + 65 + 60 + 97.5 + 220

= 630

Marks obtained by Rohan in all the subjects

= (90/100) x 150 + (80/100) x 200 + (58/100) x 100 + (88/100) x 125 + (87/100) x 125 + (85/100) x 250

= 135 + 160 + 58 + 110 + 108.75 + 212.5

= 784.25

Required difference = 784.25 тАУ 630 = 154.25
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Eight persons P, Q, R, S, T, U, V, and W are sitting around a square table facing the centre not necessarily in the same order. Each one of them has a different item in his/her purse viz. Rose, Cigar, Cap, Candy, Teddy, Sandwich, Water bottle and Pen. Two persons are sitting on each side facing the other two.
V sits second to the right of the one who has candy. The one who has a water bottle is an immediate neighbour of the one who has candy. S and the one having a rose are immediate neighbours of each other. U does not have a rose. Only one person sits between T and Q, when counted clockwise from Q. R sits third to left of the one who has a pen. The one who has a sandwich sits second to left of the person having a teddy. Two people sit between the one who has a Water bottle and U, when counted clockwise from the person who has the water bottle. T and P are immediate neighbours of each other. Neither T nor P is an immediate neighbour of either U or the one who has a Candy in his purse. The one who has a cap sits second to the right of Q, who has a cigar.

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рдЖрда рд╡реНрдпрдХреНрддрд┐- P, Q, R, S, T, U, V рдФрд░ W рд╣реИрдВ, рдЬреЛ рдПрдХ рд╡рд░реНрдЧрд╛рдХрд╛рд░ рдореЗрдЬ рдХреЗ рдЪрд╛рд░реЛ рдУрд░ рдХреЗрдВрджреНрд░ рдХреА рдУрд░ рдЙрдиреНрдореБрдЦ рд╣реЛрдХрд░ рдмреИрдареЗ рд╣реИрдВ рд▓реЗрдХрд┐рди рдЖрд╡рд╢реНрдпрдХ рдирд╣реАрдВ рдХрд┐ рд╕рдорд╛рди рдХреНрд░рдо рдореЗрдВ рд╣реЛрдВред рдЙрдирдореЗрдВ рд╕реЗ рдкреНрд░рддреНрдпреЗрдХ рдХреЗ рдкрд░реНрд╕ рдореЗрдВ рдПрдХ рд╡рд╕реНрддреБ рдЕрд░реНрдерд╛рддреН рдЧреБрд▓рд╛рдм, рд╕рд┐рдЧрд╛рд░, рдХреИрдк, рдХреИрдВрдбреА, рдЯреЗрдбреА, рд╕реИрдВрдбрд╡рд┐рдЪ, рдкрд╛рдиреА рдХреА рдмреЛрддрд▓ рдФрд░ рдкреЗрди рд╣реИред рдкреНрд░рддреНрдпреЗрдХ рднреБрдЬрд╛ рдкрд░ рджреЛ рд╡реНрдпрдХреНрддрд┐ рдЕрдиреНрдп рджреЛ рд╡реНрдпрдХреНрддрд┐рдпреЛрдВ рдХреА рдУрд░ рдЙрдиреНрдореБрдЦ рд╣реЛрдХрд░ рдмреИрдареЗ рд╣реИрдВред
V, рдЙрд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рджрд╛рдпреЗрдВ рд╕реЗ рджреВрд╕рд░реЗ рд╕реНрдерд╛рди рдкрд░ рдмреИрдард╛ рд╣реИ, рдЬрд┐рд╕рдХреЗ рдкрд╛рд╕ рдХреИрдВрдбреА рд╣реИред рдЬрд┐рд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдкрд╛рд╕ рдкрд╛рдиреА рдХреА рдмреЛрддрд▓ рд╣реИ, рд╡рд╣ рдЙрд╕ рд╡реНрдпрдХреНрддрд┐ рдХрд╛ рдирд┐рдХрдЯрддрдо рдкреЬреЛрд╕реА рд╣реИ, рдЬрд┐рд╕рдХреЗ рдкрд╕рд╛ рдХреИрдВрдбреА рд╣реИред S рдФрд░ рдЬрд┐рд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдкрд╛рд╕ рдЧреБрд▓рд╛рдм рд╣реИ, рд╡реЗ рдПрдХ рджреВрд╕рд░реЗ рдХреЗ рдирд┐рдХрдЯрддрдо рдкреЬреЛрд╕реА рд╣реИрдВред U рдХреЗ рдЧреБрд▓рд╛рдм рдирд╣реАрдВ рд╣реИред T рдФрд░ Q рдХреЗ рдмреАрдЪ рдХреЗрд╡рд▓ рдПрдХ рд╡реНрдпрдХреНрддрд┐ рдмреИрдард╛ рд╣реИ, рдЬрдм Q рдХреЗ рджрдХреНрд╖рд┐рдгрд╛рд╡рд░реНрдд рдЧрд┐рдирд╛ рдЬрд╛рддрд╛ рд╣реИред R, рдЙрд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдмрд╛рдпреЗрдВ рд╕реЗ рддреАрд╕рд░реЗ рд╕реНрдерд╛рди рдкрд░ рдмреИрдард╛ рд╣реИ, рдЬрд┐рд╕рдХреЗ рдкрд╛рд╕ рдкреЗрди рд╣реИред рдЬрд┐рд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдкрд╛рд╕ рд╕реИрдВрдбрд╡рд┐рдЪ рд╣реИ, рд╡рд╣ рдЙрд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдмрд╛рдпреЗрдВ рд╕реЗ рджреВрд╕рд░реЗ рд╕реНрдерд╛рди рдкрд░ рдмреИрдард╛ рд╣реИ рдЬрд┐рд╕рдХреЗ рдкрд╛рд╕ рдЯреЗрдбреА рд╣реИред рдЬрд┐рд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдкрд╛рд╕ рдкрд╛рдиреА рдХреА рдмреЛрддрд▓ рд╣реИ рдФрд░ U рдХреЗ рдмреАрдЪ рджреЛ рд╡реНрдпрдХреНрддрд┐ рдмреИрдареЗ рд╣реИрдВ, рдЬрдм рдЬрд┐рд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдкрд╛рд╕ рдкрд╛рдиреА рдХреА рдмреЛрддрд▓ рд╣реИ, рдЙрд╕рдХреЗ рджрдХреНрд╖рд┐рдгрд╛рд╡рд░реНрдд рджрд┐рд╢рд╛ рдореЗрдВ рдЧрд┐рдирд╛ рдЬрд╛рддрд╛ рд╣реИред T рдФрд░ P рдПрдХ рджреВрд╕рд░реЗ рдХреЗ рдирд┐рдХрдЯрддрдо рдкреЬреЛрд╕реА рд╣реИрдВред рди рддреЛ T рди рд╣реА P, U рдпрд╛ рдЬрд┐рд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдкрд╛рд╕ рдХреИрдВрдбреА рд╣реИ, рдЙрд╕рдХреЗ рдирд┐рдХрдЯрддрдо рдкреЬреЛрд╕реА рд╣реИрдВред рдЬрд┐рд╕ рд╡реНрдпрдХреНрддрд┐ рдХреЗ рдкрд╛рд╕ рдХреИрдк рд╣реИ рд╡рд╣ Q рдХреЗ рджрд╛рдпреЗрдВ рд╕реЗ рджреВрд╕рд░реЗ рд╕реНрдерд╛рди рдкрд░ рдмреИрдард╛ рд╣реИ рдЬрд┐рд╕рдХреЗ рдкрд╛рд╕ рд╕рд┐рдЧрд╛рд░ рд╣реИред

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