Test kodi: 196799
Javob yuborish uchun
- @best_olimpiad_robot botining β Javobni tekshirish tugmasini bosing.
- keyin test kodiga 196799 ni yuboring.
- keyin kalitlarni yuboring (kodsiz) va natijangizni bilib oling.
π£Ushbu testning to'liq variantini Yuksal.uz ning "Testlar" bo'limida yechib, uning yechimlari va video tahlillarini bepul oβrganishingiz mumkinβΌοΈ
Javob yuborish uchun
- @best_olimpiad_robot botining β Javobni tekshirish tugmasini bosing.
- keyin test kodiga 196799 ni yuboring.
- keyin kalitlarni yuboring (kodsiz) va natijangizni bilib oling.
π£Ushbu testning to'liq variantini Yuksal.uz ning "Testlar" bo'limida yechib, uning yechimlari va video tahlillarini bepul oβrganishingiz mumkinβΌοΈ
π27β€βπ₯8π7π’2π₯1π±1
196799_natijalar.html
205.6 KB
π‘ Test yakunlandi!
π° Test kodi: 196799
π¨ Test qatnashchilari: 884 ta
π Kalitlar: 1-D 2-A 3-B 4-D 5-D 6-B 7-C 8-B 9-D 10-C 11-B 12-B 13-C 14-B 15-D 16-C 17-D 18-B 19-C 20-C 21-C 22-C 23-D 24-D 25-C 26-D 27-C 28-D 29-B 30-C
π° Test kodi: 196799
π¨ Test qatnashchilari: 884 ta
π Kalitlar: 1-D 2-A 3-B 4-D 5-D 6-B 7-C 8-B 9-D 10-C 11-B 12-B 13-C 14-B 15-D 16-C 17-D 18-B 19-C 20-C 21-C 22-C 23-D 24-D 25-C 26-D 27-C 28-D 29-B 30-C
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π±16π8π€©4π’2π2π₯1
Prezident maktabi testlari | Asosiy kanal
Kvizning izohini ushbu videodan ko'rib olishingiz mumkin
Telegram
Prezident maktabi testlari | Asosiy kanal
#kun_savoli_javobi
Tuya imkon qadar ko'proq yukni ko'tarib yurishi kerak. Agar u butun yo'lni bosib o'tmoqchi bo'lsa, borish va kelishda 1000 ta bananni yeb qo'yadi. Natijada ikki marta borib kelish va bir marta borish bilan jami 2500 ta bananni yeydi vaβ¦
Tuya imkon qadar ko'proq yukni ko'tarib yurishi kerak. Agar u butun yo'lni bosib o'tmoqchi bo'lsa, borish va kelishda 1000 ta bananni yeb qo'yadi. Natijada ikki marta borib kelish va bir marta borish bilan jami 2500 ta bananni yeydi vaβ¦
π±5π3π₯2π’2π1
28-29-oktabr Saralash imtihoni tayyorgarlik testi.pdf
1.7 MB
28-29-oktabr kunlari hududlarda oΚ»tkazilgan bepul offline saralash imtihoni tayyorgarlik testi natijalari
π π @pmtests
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π±2π₯1