I'll say there's not enough information

Assuming uniform acceleration:
Journey OA
s = ut + 0.5at²
20 = 0 + 0.5a(1)²
a = 40 m/s²
v = u + at
v = 0 + 40(1) = 40 m/s

Journey AB
s = ut + 0.5at²
20 = 40(1) + 0.5a(1)²
a = -40m/s²
v = u + at
v = 40 + (-40)(1) = 0

Which means it's accelerating, decelerating and vice versa.
If that's the case, then option B is also correct.

Unless, we are assuming a non-uniform acceleration, where we don't care how the acceleration changes, but we assume this acceleration brings the velocity at point A to be 20 m/s, then it has constant velocity all the way down the journey, making option A the only answer.

from zianhao, an unknown legend

for those who don't know about history, few years back an admin of physics spmnetic banned a guy who corrected him, and its a shame to this group, and as an spmnetic admin, I apologize from our side...admin here including me can be incorrect, so pls correct us when we are wrong.

u should know that the liquid would be responding to acceleration not speed and therefore there is no way to determine which is faster, only which is speeding up, slowing down or maintaining steady speed.

sad to see majority wrong😭😭😭

Kuizz🔥

1

2

3

4

5

Kuizz time🌹