Kalau ada F4 dalam ni yang rasa struggle dgn fizik, cuba fahamkan formula. When to use and the meaning of each symbol. It helped me improve my marks😊. Algebra pon kena pandai juga ye, biasanya soalan kira kira dalam physics ni simple je, pusing pusing formula sikit. Kalau advanced sikit dia minta kaitkan dengan formula lain.

Overall physics is fun! Never give up! Jangan pernah fikir benda ni susah. Cuba dulu baru tahu👍

Paling terbaik kalau kau buat sendiri mcm ni,bukan print. That way.. melekat la dalam kepala tu👍

Hi guys... Jeremy here. Sorry for being inactive... heres a physics question i would like you guys to try!

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give your explanation for whatever truck u choose...😅😅

if anyone can choose the fastest truck with explanation will definitely receive rm 10..

ok the answer is impossible to determine, A can be fastest or B can be fastest or C can be fastest, just think why... or they can have same speed... guys the reasoning is related to inertia and acceleration...

guys try answering this question, tmr night will give full explanation

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Ok U actually can't use. Any formula here

But at least describe how it moves properly

And also give reasoning on why U can't use any formula here.

.

For truck A, if it decelerates from 200 km per hour to 180km, the water will go to the right side , so we cant really eliminate truck A, for other trucks many people gave reasoning on why it could be the fastest

I see a big misconception here. Not only you, many are doing it as well
If you want to use v = displacement/ time, you are assuming that the velocity is constant and there is no acceleration
But then you find the acceleration for OA, taking v = 20 m/s.
Do you guys see the contradiction here?

We should apply suvat formulas
Journey OA
s = 20
u = 0
v = ?
a = ?
t = 1

s = ut + ½at²
20 = 0 + ½a
a = 40 m/s²
Assume that the acceleration is constant
Then use v = u + at
v = 0 + 40(1) = 40 m/s

If you remember this question, I think there's something interesting to discuss.

If you recalled, I said that when the car is at A, the velocity cannot be equal to 20 m/s, assuming a constant acceleration along OA. I stopped there and didn't continue with the discussion. However, if the car continues the journey (taking my case to be true), then you'll find out the OA, BC, DE will have acceleration, making B also a correct answer.

So, what will be the real case? Turns out, you'll need to have a non-uniform acceleration along journey OA, then you can have the car travelling at 20m/s at A, and later having a constant velocity throughout the journey, making option A the only correct answer.

But still, even it's possible to have the car travelling at 20m/s at A, the working did by Harraz in his Physics Spmnetic was still wrong. He didnt understand how to use v = d/t and a = (v-u)/t correctly