Hi guys Admin Jason is back... @ batch 09, Let's battle SPM 2025 together... hope all of you will learn a lot from this group...❤️❤️❤️ And may the resources here be useful..

Assalamualaikum and hi kids, admin Yasin here from batch 10, I’ve taught physics f4 since i was 15y/o, and i can finally be apart of the admin team.. I hope my prescence here will help a lot of SPM candidates this yearr, i am soo excited to share daily questions, extra free classes and even more related to Physics❤️ lets keep the momentum up!

Assalamualaikum and hello everyone, i am Adib. This year i am the admin for physics,chemistry and addmath. Fyi,I am one of the people who will take SPM this year, so please wish us the best for this year SPM.
Looking forward to work with all of you.

physics is everywhere guys.. if u want to eat also got physics

Hello everyone. I’m admin Anu here 🙋🏼‍♀️, your admin and tutor for Physics, Chemistry, and English. Batch 08 SPM graduate. I’ve suffered through all three, so now it’s my turn to drag you along 🤭 (jk) Physics to confuse you, Chemistry to test your sanity, and English so you can rant about both properly. Looking forward to surviving this together.🤝✨

Solution :

The end of KitKat A’s packaging is a straight line thus when force is applied, there is more surface area present which produces less pressure (Pressure is inversely proportional to surface area). Hence, it is harder to open and requires more force.

The end of KitKat B’s packaging is a zigzag shape thus when force is applied between the peaks of the zigzags, there is less surface area which produces more pressure when opening it. Hence, it is easier to open because it requires less force.

So now u guys know the purpose of the zigzags at the end of yr snacks punya packaging 🤩🤩

Assalammualaikum wbt and greetings! I'm Darwisyah and y'all can call me Wisy.. I'm one of the admins for Chemistry 👩‍🔬 , Physics 👩‍🔧 and Additional Mathematics📐📊📚.. Hope y'all can ask me questions for us to strive together this SPM 🔥.. I'm one of the candidates for SPM 2026 .. ☄️⭐

Diagram above shown is a flattened tire after rain phenomena.
Gambar rajah di atas menunjukkan tayar yang telah pancit selepas fenomena hujan.

Which of the following gas laws are applied to this cause?
Antara yang berikut, hukum gas yang manakah digunakan untuk kejadian tersebut?

Ha pening dah 😂

Solution :

- Gay-Lussac’s Law

- Tyre contains air at nearly constant volume. The rubber tyre does not change volume much. Therefore, the air inside can be considered to have constant volume, satisfying the condition for Gay-Lussac’s Law.

- Decrease in temperature causes pressure to decreases. When the tyre cools during the rain, the air temperature inside decreases. According to Gay-Lussac’s Law, a decrease in temperature leads to a decrease in air pressure inside the tyre. (DIRECTLY PROPORTIONAL)

Lower pressure cannot support the car’s weight. With reduced pressure, the air exerts less outward force on the tyre walls.
The tyre deforms and spreads on the road, making it appear flat.

Seutas gelas boleh pecah apabila terdedah kepada bunyi yang kuat pada frekuensi tertentu. Fenomena fizik manakah yang menerangkan kejadian ini?
A glass breaks when exposed to a loud sound of a certain frequency. Which physics concept explains this phenomenon?

Last for today

Yo everyone 👋
I’m Yusuf, one of the admins for Physics 🚀 & Add Math 📐.

I’m an SPM 2026 candidate (Batch ’09) and this is my first year as an admin.
Same grind as you — here to share solid tips, break things down clearly, and make Physics & Add Math less painful.

Let’s stay consistent, help each other out, and smash this SPM together 📈💥
Glad to be part of the team 🤝

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