π1
Essay question 1(modification)
U guys boleh try to do n type in the comment
nanti kul 7 min akan sharekan skema
U guys boleh try to do n type in the comment
nanti kul 7 min akan sharekan skema
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CHAPTER 1 : MEASUREMENT
PREFIXES ( acronyms )
T ( he ) era β> 10ΒΉΒ²
G ( irl ) iga β> 10βΉ
M ( ight ) ega β> 10βΆ
K ( ill ) ilo β> 10Β³
H ( erself ) ecto β> 10Β²
D ( ancing ) eca β> 10ΒΉ
d ( uck ) eci β> 10^-1
c ( harlie ) enti β> 10^-2
m ( ight ) ili β> 10^-3
[ Β΅ ( nderstand ) / micro ] β> 10^-6
n ( othing ) ano β> 10^-9
( but )
p ( erfect ) ico β> 10^-12
-mai
PREFIXES ( acronyms )
T ( he ) era β> 10ΒΉΒ²
G ( irl ) iga β> 10βΉ
M ( ight ) ega β> 10βΆ
K ( ill ) ilo β> 10Β³
H ( erself ) ecto β> 10Β²
D ( ancing ) eca β> 10ΒΉ
d ( uck ) eci β> 10^-1
c ( harlie ) enti β> 10^-2
m ( ight ) ili β> 10^-3
[ Β΅ ( nderstand ) / micro ] β> 10^-6
n ( othing ) ano β> 10^-9
( but )
p ( erfect ) ico β> 10^-12
-mai
β€19π5π€©5
*SPM MAX PREP*
Cuti, fokus, cemerlang π―π
Tak tahu nak buat apa cuti no?
JOM SERTAI SEMINAR SPM MAX PREP π€©
Jom belajar dgn abangΒ² cemeralng SPM tentang cara-cara utk menguasai topik SPN dgn mudah dgn trick menjawab soalan SPM
apa tunggu lagi? daftar sekarang!!!
Untuk pendaftaran dan pertanyaan boleh berhubung dgn
+60 17-220 3081
Shafiqah
Cuti, fokus, cemerlang π―π
Tak tahu nak buat apa cuti no?
JOM SERTAI SEMINAR SPM MAX PREP π€©
Jom belajar dgn abangΒ² cemeralng SPM tentang cara-cara utk menguasai topik SPN dgn mudah dgn trick menjawab soalan SPM
apa tunggu lagi? daftar sekarang!!!
Untuk pendaftaran dan pertanyaan boleh berhubung dgn
+60 17-220 3081
Shafiqah
π4β€2
goodluck utqh semua, insyaAllah korang semua lancar je harini π€²π»π€²π»
β€60π4
π11π6
Forwarded from Serene NotesChannel Κγ£β’α΄₯β’Κγ£ (Tahirah Sultana)
π‘Physics with Heeraπ©βπ«
Chapter 1 - Force and Motion II
π·1.4 Elasticity
Elasticity
πThe property of material that enables an object to return to its original shape and size after the force applied on it is removed
Hooke's Law
πThe extension of spring (x) is directly proportional to the force applied on the spring (F) provided the elastic limit of the spring is not exceeded
k is spring constant
F=kx
#physics #f5 #c1
#heera
π¦*ΰ©β©β§βΛ γ @serenenotes γ
Chapter 1 - Force and Motion II
π·1.4 Elasticity
Elasticity
π
Hooke's Law
π
k is spring constant
F=kx
#physics #f5 #c1
#heera
π¦*ΰ©β©β§βΛ γ @serenenotes γ
β€7π4
Forwarded from Serene NotesChannel Κγ£β’α΄₯β’Κγ£ (Tahirah Sultana)
π‘Physics with Heeraπ©βπ«
Important Definitions !
π·Chapter 1 - Force and Motion II
1β£Weight
πThe gravitational force acting on an object
2β£Force
πA push or pull upon an object
3β£Resultant Force
πThe single force that represents the vector sum of 2 or more forces acting on an object
πThe total force acting on the object
4β£Free body diagram of an Object
πDiagram that shows all the forces acting on that object only
5β£Newton's 2nd Law of Motion (F=ma)
πThe rate of change of momentum is directly proportional to the force
πActs in the direction of the applied force
6β£Acceleration (a= v-u / t)
πRate of change of velocity
7β£Resolution of Forces
πThe process of resolving a force into 2 components
- Vertical and horizontal
8β£Equilibrium of Forces or (Forces in Equilibrium)
πThe force acting on it produce a zero resultant force
9β£Elasticity
πThe property of material that enables an object to return to its original shape and size after the force applied on it is removed
πHooke's Law
πThe extension of a spring (x) is directly proportional to the force applied on the spring provided the elastic limit of the spring is not exceeded.
#physics #f5 #c1
#heera
π¦*ΰ©β©β§βΛ γ @serenenotes γ
Important Definitions !
π·Chapter 1 - Force and Motion II
1β£Weight
π
2β£Force
π
3β£Resultant Force
π
π
4β£Free body diagram of an Object
π
5β£Newton's 2nd Law of Motion (F=ma)
π
π
6β£Acceleration (a= v-u / t)
π
7β£Resolution of Forces
π
- Vertical and horizontal
8β£Equilibrium of Forces or (Forces in Equilibrium)
π
9β£Elasticity
π
πHooke's Law
π
#physics #f5 #c1
#heera
π¦*ΰ©β©β§βΛ γ @serenenotes γ
π18β€9