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7. The density of a 2.03 M solution of Acetic acid is water is 1.017 g/mL. The molality of the solution is
1.52 m
2.5 m
2.27 m
2 m
8. we mix three solution of same solute of Molarity 1M, 2M ,3M and Volume 1 L,2L ,3L. Find the molarity of the resultant solution

Molarity of the resulting solution is given by
3.3 M
2.33 M
3 M
1 M
9. What will be the molarity of a solution, which contains 5.85 g of NaCl per 500ml?
.5 M
.4 M
.2 M
1 M
10. Molarity of Solution having 5 moles of solutes present in 2 L of solution is
2 M
2.5 M
.5 M
4 M
11. The molality of the solution which contains 10 g of Cane sugar(
C
12
H
22
O
11
) dissolved in 150 g of water?
1.1 moles/kg
.194 moles/kg
.5 moles/kg
.22 moles/kg
12. If 100 ml of 1.0 M NaOH solution is diluted to 1 L, the resulting solution contains
.1 Mole of NaOH
10 mole of NaOH
.05 Mole of NaOH
1 Mole of NaOH
find the molarity of the solution where mole fraction of solute is 0.5 and H2SO4(98) and Molar mass of solvent isH2O (18 g/M) and density of solution is 1.769 g/ml

12.24
11.13
10.1
15.24
Forwarded from spherical
Forwarded from spherical
14. A Molal solution is one that contains one mole of solute in
22.4 L of solution
1 L of solvent
1000 g of solvent
1 L of solution
Pharma Scope
14. A Molal solution is one that contains one mole of solute in 22.4 L of solution 1 L of solvent 1000 g of solvent 1 L of solution
تعريف المولالية هي عدد المولات في 1kg بما انو 1kg=1000g فيكون الاختيار 1000g
هذا توضيح
خلصت واجبات المحاضرة الاولى بالتوفيق 🙂🥲
Pharma Scope pinned «1. A solution of glucose in water is labelled as 10% w/w, The molality is .5 moles/kg .74 moles/kg 0.62 moles/kg none of these»