SQL Question Of The Day: what is the output of below query?
Select substr('ASIA',5,2) from dual;
Select substr('ASIA',5,2) from dual;
SQL Question Of The Day: what is the result of below query
Select instr('ASIA','B') from dual
Select instr('ASIA','B') from dual
Hi All, really sorry for not sending the questions, busy with other stuff, from 2morow will share the questions.
SQL Question Of The Day: How to convert an existing unique key constraint to Primary key without dropping the existing unique constraint?
May be thinking like we can just club the columns but it won't work like that... Try 😊
PL/SQL Question Of The Day: what is the range of error codes we can use for raise_application_error?
SQL Question Of The Day: What is the default error limit in sql loader? Is it same for both conventional and direct path loads?
SQL Question Of The Day: What will happen to the existing indexes on the table when we are running sql loader in conventional and direct path loads?
SQL Question Of The Day: I want to load the data into 2 tables using the sql loader. I have one data file which contains informatio/columns for 2 tables. Using sql loader can we do this? if yes how to write the control file? Do we use 2 control files?.....
SQL Question of The Day: What is the difference between Case and Decode function ? When to use which one? Explain with an example...
SQL Question Of The Day: what is the difference between simple and searched case statements? When to use which one explain with an example?
SQL Coding Question Of The Day: When I use minus operator without any where condition will the queries go for full tablescan or it will go to the index scan if they columns selected in the query has a index....
SQL Question Of The Day: If there is no else clause placed in the case statement what value will it display when the conditions are not satisfied?
PL/SQL coding question of the Day: I need to generate a sequence like
AA0001
AA0002
AA0003
AA9999
AB0001
AB0002
AB0003
AB0004
.
.
.
AZ9999
BA0000
BA0001
BA0002
.
.
.
ZZ9999
once reach ZZ9999 need to start with AA0001 again
AA0001
AA0002
AA0003
AA9999
AB0001
AB0002
AB0003
AB0004
.
.
.
AZ9999
BA0000
BA0001
BA0002
.
.
.
ZZ9999
once reach ZZ9999 need to start with AA0001 again