➡️ *SSC Selection Post Phase IX Recruitment 2021* ~Apply Start~

✅ *Total Posts:-* 3261

❇️ *Post Name:-* SSC various post phase IX

📋 *Important dates👇🏻👇🏻*

See• Online apply date:- 24 September 2021

• Online apply last date:- 25 October 2021

• Fee payment last date:- 28 October 2021

➡️ *Application fee👇🏻👇🏻*

• General/OBC/EWS Candidates:- 100₹

• ST/SC/Women Candidates:- No application fee

➡️ *Educational Qualification:-*

• *Graduation Level Posts –*
Candidates having Graduation Degree in any stream from any recognized university will be eligible for this post.

• *Matriculation Posts –*
Candidates who have passed their matriculation (Class 10th) level of Examination from any recognized board will be eligible for this post.

• *Intermediate Level Posts –*
Candidates who have
Passed Class 12th (Intermediate) Exam
form any recognized board will be eligible for this post.

*(मैट्रिक, इंटर या ग्रेजुएशन वाले सभी व्यक्ति इस फार्म को भर सकते हैं)*

💻 *Apply link:-* https://ssc.nic.in/Portal/Apply

➡️ *Download Notification:-* https://www.sarkariexam.com/wp-content/uploads/2020/02/notice_rhq_24092021.pdf

🌎 *Official website:-* https://ssc.nic.in/

✅ *Join Telegram Channel:- https://t.me/mathsquiz07


*Sarkari Jobs Notification*

🎲 Quiz 'Copy quiz'
https://t.me/Maths_Quiz_Pdf_Solution/9661
🖊 2 questions · ⏱ 2 min

➡️ CBSE exam 2021 class 12th Compartment Result Out

❇️ Check Result:- https://cbseresults.nic.in/class12Comprt/Class12th21Comprt.htm

📊 त्रिकोणमिति : महत्वपूर्ण सूत्र 📊

🍎 योग सूत्र
➭ Sin(A+B) = SinACosB+CosASinB
➭ Sin(A-B) = SinACosB-CosASinB
➭ Cos(A+B) = CosACosB-SinASinB
➭ Cos(A-B) = CosACosB+SinASinB

🍏 अन्तर सूत्र
➭ tan(A+B) = tanA+tanB/1-tanAtanB
➭ tan(A-B) = tanA-tanB/1+tanAtanB

🍎 C-D सूत्र
➭ SinC+SinD = 2Sin(C+D/2) Cos(C-D/2)
➭ SinC-SinD = 2Cos(C+D/2) Sin(C-D/2)
➭ CosC+CosD = 2Cos(C+D/2) Cos(C-D/2)
➭ CosC-CosD = 2Sin(C+D/2) Sin(D-C/2)
➭ CosC-CosD = -2Sin(C+D/2) Sin(C-D/2)

🍏 रूपांतरण सूत्र
➛ 2SinACosB = Sin(A+B)+Sin(A-B)
➛ 2CosASinB = Sin(A+B)-Sin(A-B)
➛ 2CosACosB = Cos(A+B)+Cos(A-B)
➛ 2SinASinB = Cos(A-B)-Cos(A+B)

🍎 द्विक कोण सूत्र
➛ Sin2A = 2SinACosA
➛ Cos2A = Cos²A-Sin²A = 2Cos²-1 = 1-2Sin²A
➛ tan2A = 2tanA/1-tan²A
➛ Sin2A = 2tanA/1+tan²A
➛ Cos2A = 1-tan²A/1+tan²A

🍏 विशिष्ट सूत्र
➛ Sin(A+B)Sin(A-B) = Sin²A-Sin²B
= Cos²B-Cos²A
➛ Cos(A+B)Cos(A-B) = Cos²A-Sin²B = Cos²B-Sin²A

🍎 त्रिक कोण सूत्र
➛ Sin3A = 3SinA-4Sin³A
➛ Cos3A = 4Cos³A-3CosA
➛ tan3A = 3tanA-tan³A/1-3tan²A

🍏 महत्वपूर्ण सर्वसमिकाएं
➛ Sin²θ+Cos²θ = 1
➭ Sin²θ = 1-Cos²θ
➭ Cos²θ = 1-Sin²θ
➛ 1+tan²θ = Sec²θ
➭ Sec²θ-tan²θ = 1
➭ tan²θ = Sec²θ-1
➛ 1+Cot²θ = Cosec²θ
➭ Cosec²θ-Cot²θ = 1
➭ Cot²θ = Cosec²θ-1

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Ꭻᴏɪɴ ➠ @mathsquiz07
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Can anyone solve 7 no question