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2/7 मध्ये 3/7 किती वेळा मिळवावे म्हणजे बेरीज 5 येईल?
1) 33 2)11 3)22 4)12
1) 33 2)11 3)22 4)12
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2/7 मध्ये 3/7 किती वेळा मिळवावे म्हणजे बेरीज 5 येईल? 1) 33 2)11 3)22 4)12
2/7 + 3x/7 = 5
3x/7 = 5 - 2/7 = 33/7
X = 33/7 × 7/3 = 11
*11 वेळा*
3x/7 = 5 - 2/7 = 33/7
X = 33/7 × 7/3 = 11
*11 वेळा*
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(4^3)^ -2/3 × (1/4)^-2
1/(4)2 × 4^2
= 4^2 /4^2 = 1
1/(4)2 × 4^2
= 4^2 /4^2 = 1
(4m²) + (1/4m²) + 2= 4
(4m²) + (1/4m²) = 4 - 2 = 2
पर्याय (2) बरोबर✅
(4m²) + (1/4m²) = 4 - 2 = 2
पर्याय (2) बरोबर✅
क्रमागत संख्या-
X + (x +1) + (x + 2) + (x + 3) = 42 × 4 = 168
4x + 6 = 168
4X = 168 - 6 = 162
X = 162 / 4 = 40.5
A = X = 40.5
B = X + 1 = 41 .5
C = X + 2 = 42 .5
D = X + 3 = 43.5
B × D = 41.5 × 43.5 = 1805.25
उत्तर :- यापैकी नाही
X + (x +1) + (x + 2) + (x + 3) = 42 × 4 = 168
4x + 6 = 168
4X = 168 - 6 = 162
X = 162 / 4 = 40.5
A = X = 40.5
B = X + 1 = 41 .5
C = X + 2 = 42 .5
D = X + 3 = 43.5
B × D = 41.5 × 43.5 = 1805.25
उत्तर :- यापैकी नाही
200 ÷ 4= 0 बाकी
(18 - 1)²⁰⁰
-----------
18
- 1²⁰⁰
--------
18
1/18 = 1 बाकी
पर्याय (1) ✅
(18 - 1)²⁰⁰
-----------
18
- 1²⁰⁰
--------
18
1/18 = 1 बाकी
पर्याय (1) ✅