∆ABC is an equilateral triangle. D is a point on side BC such that BD: BC = 1/3 If AD = 5√7 cm then the side of the triangle is:

△ABC एक समबाहु त्रिभुज है। D भुजा BC पर एक बिंदु इस प्रकार है कि BD : BC = 1 : 3 है। यदि AD = 5√7सेमी है, तो त्रिभुज की भुजा हैः

[SSC CGL PRE [18 AUG 2020]

(a) 18 cm

(b) 15 cm

(c) 12 cm

(d) 20 cm

In the given triangle ABC, AD is an angle bisector of angle A. If AB = 6cm AC = 9cm and BC = 10cm then find the length of angle bisector AD?

दिए गए त्रिभुज ABC में, AD, LA का एक कोण सम‌द्विभाजक है। यदि AB = 6 सेमी, AC = 9 सेमी और BC = 10 सेमी है, तो कोण सम‌द्विभाजक AD की लंबाई ज्ञात कीजिए।

[SSC CHSL-2019]

(a) 2√3

√30

(c) 2√5

(d) 2√15

3) In ∆ABC, If AB = AC = 16cm BC = 22cm BD = 14cm D is a point on BC then the measure AD is

△ABC में, यदि AB = AC = 16 सेमी, BC = 22 सेमी BD = 14 सेमी D, BC पर एक बिंदु है, तो AD का माप है

[SSC CGL PRE 2020]

(a) 14

(b) 16

(c)12

(d) 8

(4) 142

Q4. Find the length of the common tangent of two externally touch circle with radius 16 cm and & 9 cm respectively?

(a) 12 cm

(b) 24 cm

(c) 13cm

(d) 28 cm

Q5. ABC is an isosceles triangle a circle is such that it passes through tangent at D for the same circle. AC and BC intersects the circle at E and F respectively AC = BC = 4 cm and AB = 6 cm. Also, D is the mid-point of AB. What is the ratio of EC: (AE + AD)?

(a) 9:7

(b) 3:4

(c) 4:3

(d) 1:3



Q6. The radius of two concentric circles are 17 cm and 10 cm. A straight line ABCD intersects the larger circle at the point A and D and intersects the smaller circle at the points B and C. If BC = 12 cm, then the length of AD (in cm) is? m) is?

(a) 20

(b) 24

(c) 30

(d) 34