📊 त्रिकोणमिति : महत्वपूर्ण सूत्र 📊
🍎 योग सूत्र
➭ Sin(A+B) = SinACosB+CosASinB
➭ Sin(A-B) = SinACosB-CosASinB
➭ Cos(A+B) = CosACosB-SinASinB
➭ Cos(A-B) = CosACosB+SinASinB
🍏 अन्तर सूत्र
➭ tan(A+B) = tanA+tanB/1-tanAtanB
➭ tan(A-B) = tanA-tanB/1+tanAtanB
🍎 C-D सूत्र
➭ SinC+SinD = 2Sin(C+D/2) Cos(C-D/2)
➭ SinC-SinD = 2Cos(C+D/2) Sin(C-D/2)
➭ CosC+CosD = 2Cos(C+D/2) Cos(C-D/2)
➭ CosC-CosD = 2Sin(C+D/2) Sin(D-C/2)
➭ CosC-CosD = -2Sin(C+D/2) Sin(C-D/2)
🍏 रूपांतरण सूत्र
➛ 2SinACosB = Sin(A+B)+Sin(A-B)
➛ 2CosASinB = Sin(A+B)-Sin(A-B)
➛ 2CosACosB = Cos(A+B)+Cos(A-B)
➛ 2SinASinB = Cos(A-B)-Cos(A+B)
🍎 द्विक कोण सूत्र
➛ Sin2A = 2SinACosA
➛ Cos2A = Cos²A-Sin²A = 2Cos²-1 = 1-2Sin²A
➛ tan2A = 2tanA/1-tan²A
➛ Sin2A = 2tanA/1+tan²A
➛ Cos2A = 1-tan²A/1+tan²A
🍏 विशिष्ट सूत्र
➛ Sin(A+B)Sin(A-B) = Sin²A-Sin²B
= Cos²B-Cos²A
➛ Cos(A+B)Cos(A-B) = Cos²A-Sin²B = Cos²B-Sin²A
🍎 त्रिक कोण सूत्र
➛ Sin3A = 3SinA-4Sin³A
➛ Cos3A = 4Cos³A-3CosA
➛ tan3A = 3tanA-tan³A/1-3tan²A
🍏 महत्वपूर्ण सर्वसमिकाएं
➛ Sin²θ+Cos²θ = 1
➭ Sin²θ = 1-Cos²θ
➭ Cos²θ = 1-Sin²θ
➛ 1+tan²θ = Sec²θ
➭ Sec²θ-tan²θ = 1
➭ tan²θ = Sec²θ-1
➛ 1+Cot²θ = Cosec²θ
➭ Cosec²θ-Cot²θ = 1
➭ Cot²θ = Cosec²θ-1
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🍎 योग सूत्र
➭ Sin(A+B) = SinACosB+CosASinB
➭ Sin(A-B) = SinACosB-CosASinB
➭ Cos(A+B) = CosACosB-SinASinB
➭ Cos(A-B) = CosACosB+SinASinB
🍏 अन्तर सूत्र
➭ tan(A+B) = tanA+tanB/1-tanAtanB
➭ tan(A-B) = tanA-tanB/1+tanAtanB
🍎 C-D सूत्र
➭ SinC+SinD = 2Sin(C+D/2) Cos(C-D/2)
➭ SinC-SinD = 2Cos(C+D/2) Sin(C-D/2)
➭ CosC+CosD = 2Cos(C+D/2) Cos(C-D/2)
➭ CosC-CosD = 2Sin(C+D/2) Sin(D-C/2)
➭ CosC-CosD = -2Sin(C+D/2) Sin(C-D/2)
🍏 रूपांतरण सूत्र
➛ 2SinACosB = Sin(A+B)+Sin(A-B)
➛ 2CosASinB = Sin(A+B)-Sin(A-B)
➛ 2CosACosB = Cos(A+B)+Cos(A-B)
➛ 2SinASinB = Cos(A-B)-Cos(A+B)
🍎 द्विक कोण सूत्र
➛ Sin2A = 2SinACosA
➛ Cos2A = Cos²A-Sin²A = 2Cos²-1 = 1-2Sin²A
➛ tan2A = 2tanA/1-tan²A
➛ Sin2A = 2tanA/1+tan²A
➛ Cos2A = 1-tan²A/1+tan²A
🍏 विशिष्ट सूत्र
➛ Sin(A+B)Sin(A-B) = Sin²A-Sin²B
= Cos²B-Cos²A
➛ Cos(A+B)Cos(A-B) = Cos²A-Sin²B = Cos²B-Sin²A
🍎 त्रिक कोण सूत्र
➛ Sin3A = 3SinA-4Sin³A
➛ Cos3A = 4Cos³A-3CosA
➛ tan3A = 3tanA-tan³A/1-3tan²A
🍏 महत्वपूर्ण सर्वसमिकाएं
➛ Sin²θ+Cos²θ = 1
➭ Sin²θ = 1-Cos²θ
➭ Cos²θ = 1-Sin²θ
➛ 1+tan²θ = Sec²θ
➭ Sec²θ-tan²θ = 1
➭ tan²θ = Sec²θ-1
➛ 1+Cot²θ = Cosec²θ
➭ Cosec²θ-Cot²θ = 1
➭ Cot²θ = Cosec²θ-1
Join now:-
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❤1
When the integer n is divided by 7, the remainder is 3. What is the remainder if 5n is divided by 7?
The sum of all possible three-digit numbers formed by digits 3, 0, and 7, using each digit only once is:
The ratios of copper to Zinc in alloys A and B are 3:4 and 5:9 respectively. A and B are taken in the ratio 2:3 and melted to form a new alloy C. What is the ratio of copper to Zinc in C?
📚शालिनी अपनी आय का एक तिहाई बचाती है। यदि उसकी आय x% बढ़ जाती है और खर्च 15% बढ़ जाता है, तो बचत में 21% की वृद्धि हो जाती है। x का मान ज्ञात कीजिए।
Two pipes can independently fill a bucket in 20 minutes and 25 minutes. Both are opened together for 5 minutes after which the second pipe is turned off. What is the time taken by the first pipe alone to fill the remaining portion of the bucket?
Rs. 820 is divided among 6 men, 8 women and 12 boys in such a way that every women gets an amount equal to that received by one man and one boy combined and that every man gets one and a half times the amount received by a boy. What is the total amount received by 8 women?
820 रुपये को 6 पुरुषों, 8 महिलाओं और 12 लड़कों के बीच इस तरह से विभाजित किया जाता है कि प्रत्येक महिला को एक आदमी द्वारा प्राप्त राशि और लड़के द्वारा प्राप्त राशि के बराबर राशि मिलती है। प्रत्येक आदमी को एक लड़के द्वारा प्राप्त राशि का डेढ़ गुना मिलता है। 8 महिलाओं द्वारा प्राप्त कुल राशि कितनी है?
820 रुपये को 6 पुरुषों, 8 महिलाओं और 12 लड़कों के बीच इस तरह से विभाजित किया जाता है कि प्रत्येक महिला को एक आदमी द्वारा प्राप्त राशि और लड़के द्वारा प्राप्त राशि के बराबर राशि मिलती है। प्रत्येक आदमी को एक लड़के द्वारा प्राप्त राशि का डेढ़ गुना मिलता है। 8 महिलाओं द्वारा प्राप्त कुल राशि कितनी है?
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Math practice set railway pinned «📊 त्रिकोणमिति : महत्वपूर्ण सूत्र 📊 🍎 योग सूत्र ➭ Sin(A+B) = SinACosB+CosASinB ➭ Sin(A-B) = SinACosB-CosASinB ➭ Cos(A+B) = CosACosB-SinASinB ➭ Cos(A-B) = CosACosB+SinASinB 🍏 अन्तर सूत्र ➭ tan(A+B) = tanA+tanB/1-tanAtanB ➭ tan(A-B) = tanA-tanB/1+tanAtanB …»