Assalamualaikum guys... harini dan esok saya tak jadi buat kelas sebab saya ade hal banyak😭😭 kite ganti hari isnin dan selasa boleh?? Sorry tau.
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Koordinat S1: titik A berada di (3,5) dan titik B berada di (3,9). Berapakah jarak antara A dan B?
Anonymous Quiz
13%
3 unit
79%
4 unit
6%
5 unit
2%
6 unit
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S2: Titik tengah bagi (2,4) dan (8,10) ialah:
Anonymous Quiz
60%
(5,7)
10%
(10,14)
18%
(4,6)
13%
(6,8)
S3: Titik M berada di tengah2 antara A(1,3) dan B(5,7). Apakah koordinat M?
Anonymous Quiz
11%
(2,4)
76%
(3,5)
10%
(4,6)
3%
(6,10)
S4: Garis lurus melalui titik (2,5) dan (4,11). Berapakh kecurunan garis itu?
Anonymous Quiz
8%
2
76%
3
10%
4
6%
6
S5: Garis lurus y=2x+6 memotong paksi-x pada titik:
Anonymous Quiz
52%
(-3,0)
19%
(3,0)
26%
(0,6)
3%
(-6,0)
S6: Cari persamaan garis lurus yang melalui titik (1,4) dengan kecerunan 3:
Anonymous Quiz
50%
y=3x+1
35%
y=3x+4
8%
y=x+3
6%
y=3x+7
S7: Kecurunan garis yg melalui (3,7) dan (3,12) ialah:
Anonymous Poll
15%
0
25%
5
69%
tidak terdefinisi
3%
1
S8: Suatu segi tiga mempunyai bucu di A(0, 0), B(4, 0) dan C(2, 3). Apakah koordinat titik tengah bagi sisi AB?
Anonymous Quiz
6%
(1,0)
79%
(2.0)
13%
(3,0)
3%
(2,15)
📐 SOALAN PROBLEM SOLVING - KOORDINAT 📐
Ada 8 soalan untuk korang practice!
Soalan dari mudah → sederhana → susah ✅
CARA NAK JAWAB:
✏️ Answer DALAM CHANNEL ni je
✏️ Atau boleh jawab satu-satu pun okay!
Jom cuba! Let's see siapa dapat full marks! 💪
Ada 8 soalan untuk korang practice!
Soalan dari mudah → sederhana → susah ✅
CARA NAK JAWAB:
✏️ Answer DALAM CHANNEL ni je
✏️ Atau boleh jawab satu-satu pun okay!
Jom cuba! Let's see siapa dapat full marks! 💪
FORMULA PENTING KOORDINAT: 1️⃣ Jarak antara 2 titik:
Kalau x sama: Jarak = |y₂ - y₁|
Kalau y sama: Jarak = |x₂ - x₁|
Kalau both berbeza: Jarak = √[(x₂-x₁)² + (y₂-y₁)²]
2️⃣ Titik Tengah (Midpoint):
M = ((x₁+x₂)/2, (y₁+y₂)/2)
3️⃣ Kecerunan (Gradient):
m = (y₂ - y₁) / (x₂ - x₁)
4️⃣ Persamaan Garis Lurus:
y = mx + c
m = kecerunan, c = pintasan-y
5️⃣ Pantulan:
Paksi-x: (x, y) → (x, -y)
Paksi-y: (x, y) → (-x, y)
Kalau x sama: Jarak = |y₂ - y₁|
Kalau y sama: Jarak = |x₂ - x₁|
Kalau both berbeza: Jarak = √[(x₂-x₁)² + (y₂-y₁)²]
2️⃣ Titik Tengah (Midpoint):
M = ((x₁+x₂)/2, (y₁+y₂)/2)
3️⃣ Kecerunan (Gradient):
m = (y₂ - y₁) / (x₂ - x₁)
4️⃣ Persamaan Garis Lurus:
y = mx + c
m = kecerunan, c = pintasan-y
5️⃣ Pantulan:
Paksi-x: (x, y) → (x, -y)
Paksi-y: (x, y) → (-x, y)
👍5
Hints? Given. Tips? Served. Formula? In your sheet.
Some of you: "OHHH finally faham!" ✅
Some of you: "Cikgu I try but..." — acceptable, let's work on it 🤝
And some of you: proceed to kira gradient as (x+y)/2 then blames soalan — bro what are we doing wehh 😭
Susah sangat ke? Really? It's just x and y. Not x, y, z, your future, your hopes, your dreams.
Tell me where you lost. Then we move. Simple.
Some of you: "OHHH finally faham!" ✅
Some of you: "Cikgu I try but..." — acceptable, let's work on it 🤝
And some of you: proceed to kira gradient as (x+y)/2 then blames soalan — bro what are we doing wehh 😭
Susah sangat ke? Really? It's just x and y. Not x, y, z, your future, your hopes, your dreams.
Tell me where you lost. Then we move. Simple.
❤4👏1
1. Koordinat-x sama (kedua-dua 3), jadi jarak = |9 - 5| = 4 unit ✅
4. Kecerunan (m) = (y₂ - y₁) / (x₂ - x₁)
m = (11 - 5) / (4 - 2) = 6/2 = 3 ✅ 5. y = mx + c
4 = 3(1) + c
4 = 3 + c
c = 1
Persamaan: y = 3x + 1 ✅ 6. m = (12-7)/(3-3) = 5/0 = tidak terdefinisi (garis menegak) ✅ 7. Titik tengah AB = ((0+4)/2, (0+0)/2) = (2, 0) ✅ 8. Titik tengah AB = ((0+4)/2, (0+0)/2) = (2, 0) ✅
m = (11 - 5) / (4 - 2) = 6/2 = 3 ✅ 5. y = mx + c
4 = 3(1) + c
4 = 3 + c
c = 1
Persamaan: y = 3x + 1 ✅ 6. m = (12-7)/(3-3) = 5/0 = tidak terdefinisi (garis menegak) ✅ 7. Titik tengah AB = ((0+4)/2, (0+0)/2) = (2, 0) ✅ 8. Titik tengah AB = ((0+4)/2, (0+0)/2) = (2, 0) ✅
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Faham ke atau just salin? Sebab salin tak payah otak, faham baru boleh buat sendiri.
One trip. One chance. Don't waste petrol on photocopy skills. ⛽️
One trip. One chance. Don't waste petrol on photocopy skills. ⛽️
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