\(I_1 = F^{\mu\nu} F_{\mu\nu} = 2 \left( B^2 - \frac{E^2}{c^2} \right)\)\(I_2 = \tilde{F}^{\mu\nu} F_{\mu\nu} = -\frac{4}{c} \mathbf{E} \cdot \mathbf{B}\)

\(\nabla^d \times \mathbf{H} = \mathbf{J}_d + \frac{\partial \mathbf{D}_d}{\partial t}\)

#div

\(\mathcal{L}=-\frac{1}{4}F_{\mu \nu }F^{\mu \nu }+i\={\psi }\cancel{D}\psi +\psi _{i}y_{ij}\psi _{j}\phi +hc+|D_{\mu }\phi |{}^{2}-V(\phi )+\frac{1}{16\pi G}R\)

\(\nabla \times \mathbf{B}=\mu _{0}\left(\mathbf{j}+\varepsilon _{0}\frac{\partial \mathbf{E}}{\partial t}\right)\)

#span