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1:2

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Question -
A fighter pilot observes a boy on the ground at an angle of depression of 45°. After flying for some time, the angle of depression changed to 60°. If the fighter plane is flying at a height of 300 m, then find the time (in seconds) for which the fighter plane flew between the two instances of observation. (Speed of fighter plane = 360 km/hr)

Pick ONE option
2 - √3
3 -√3
2
None of these


Answer: 3 - √3

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31%

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Guys, most of the questions are same for everyone as there is a pool of questions.
They are just in random order.

209

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B

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a = 115, b = 9

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60o

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A

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C

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-1

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Cognizant
Database Query Question
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SELECT instructor.first_name AS "First Name", instructor.last_name AS "Last Name"
FROM instructor
WHERE instructor.type = 'full-time'
  AND instructor.last_name LIKE 'C%';

Cognizant
Database Query Question
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Leetcode Weekly 419
A
C++
https://telegram.me/+_hn3cBQVbGliYTI9

#include <vector>
#include <unordered_map>
#include <algorithm>

using namespace std;

class Solution {
public:
vector<int> findXSum(vector<int>& nums, int k, int x) {
int n = nums.size();
vector<int> answer;

for (int i = 0; i <= n - k; ++i) {
unordered_map<int, int> frequency;
for (int j = i; j < i + k; ++j) {
frequency[nums[j]]++;
}

vector<pair<int, int>> freqList;
for (const auto& entry : frequency) {
freqList.push_back({entry.second, entry.first});
}

sort(freqList.begin(), freqList.end(), [](const pair<int, int>& a, const pair<int, int>& b) {
if (a.first != b.first) return a.first > b.first;
return a.second > b.second;
});

int sum = 0;
int count = 0;
for (const auto& entry : freqList) {
int frequency = entry.first;
int value = entry.second;
if (count >= x) break;
sum += frequency * value;
count++;
}

answer.push_back(sum);
}

return answer;
}
};

Leetcode Weekly 419
A
C++
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