leetcode.cn 2025-06-21
🟡3085.minimum-deletions-to-make-string-k-special
🏷️ Tags
#greedy #hash_table #string #counting #sorting
🟡3085.minimum-deletions-to-make-string-k-special
🏷️ Tags
#greedy #hash_table #string #counting #sorting
Telegraph
minimum-deletions-to-make-string-k-special
给你一个字符串 word 和一个整数 k。 如果 |freq(word[i]) - freq(word[j])| <= k 对于字符串中所有下标 i 和 j 都成立,则认为 word 是 k 特殊字符串。 此处,freq(x) 表示字符 x 在 word 中的出现频率,而 |y| 表示 y 的绝对值。 返回使 word 成为 k 特殊字符串 需要删除的字符的最小数量。 示例 1: 输入:word = "aabcaba", k = 0 输出:3 解释:可以删除 2 个 "a" 和 1 个 "c" 使…
leetcode.com 2025-06-21
🟡3085.minimum-deletions-to-make-string-k-special
🏷️ Tags
#greedy #hash_table #string #counting #sorting
🟡3085.minimum-deletions-to-make-string-k-special
🏷️ Tags
#greedy #hash_table #string #counting #sorting
Telegraph
minimum-deletions-to-make-string-k-special
You are given a string word and an integer k. We consider word to be k-special if |freq(word[i]) - freq(word[j])| <= k for all indices i and j in the string. Here, freq(x) denotes the frequency of the character x in word, and |y| denotes the absolute value…
leetcode.cn 2025-06-27
🔴2014.longest-subsequence-repeated-k-times
🏷️ Tags
#greedy #string #backtracking #counting #enumeration
🔴2014.longest-subsequence-repeated-k-times
🏷️ Tags
#greedy #string #backtracking #counting #enumeration
Telegraph
longest-subsequence-repeated-k-times
给你一个长度为 n 的字符串 s ,和一个整数 k 。请你找出字符串 s 中 重复 k 次的 最长子序列 。 子序列 是由其他字符串删除某些(或不删除)字符派生而来的一个字符串。 如果 seq * k 是 s 的一个子序列,其中 seq * k 表示一个由 seq 串联 k 次构造的字符串,那么就称 seq 是字符串 s 中一个 重复 k 次 的子序列。
leetcode.com 2025-06-27
🔴2014.longest-subsequence-repeated-k-times
🏷️ Tags
#greedy #string #backtracking #counting #enumeration
🔴2014.longest-subsequence-repeated-k-times
🏷️ Tags
#greedy #string #backtracking #counting #enumeration
Telegraph
longest-subsequence-repeated-k-times
You are given a string s of length n, and an integer k. You are tasked to find the longest subsequence repeated k times in string s. A subsequence is a string that can be derived from another string by deleting some or no characters without changing the order…