Language: Kotlin | Difficulty: Easy
Language: Kotlin | Difficulty: Medium)
Language: Kotlin | Difficulty: Medium)
Language: Kotlin | Difficulty: Hard
@leetcode @leetcode7 @leetcode8 #contest #leetcode #biweekly166 #contest #leetcodecontest
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Leetcode contest
Let`s support me by share channel đ
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Azamov
"Cancel Netflix" made a dent Netflix lost nearly $20 billion in value
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Leetcode contest
Q1. Compute Alternating SumŠleetcode @leetcode7 @leetcode @contest #contest #weekly468
Problem:Q1. â
Status: Easyđ´
Code: Cppđ
@leetcode @contest @weekly @contest @leetcode7 #weeekly #leetcoder
Status: Easy
Code: Cpp
#include <vector>
using namespace std;
class Solution {
public:
int alternatingSum(vector<int>& nums) {
int total = 0;
int i = 0;
while (i < nums.size()) {
if (i % 2 == 0) {
total += nums[i];
} else {
total -= nums[i];
}
i++;
}
return total;
}
};
@leetcode @contest @weekly @contest @leetcode7 #weeekly #leetcoder
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Title: Q2. Longest Subsequence With Non-Zero Bitwise XOR
Status: Medium
@leetcode @leetcode7 #contest
Status: Medium
@leetcode @leetcode7 #contest
Leetcode contest
Title: Q2. Longest Subsequence With Non-Zero Bitwise XOR Status: Medium @leetcode @leetcode7 #contest
Problem: Q2. Longest Subsequence With Non-Zero Bitwise XOR đ
Status: Mediumđ§ââī¸
@leetcode7 @contest #weekly #contest
Status: Medium
#include <vector>
using namespace std;
class Solution {
public:
int longestSubsequence(vector<int>& nums) {
vector<int> drovantila = nums;
int totalXOR = 0;
for (int i = 0; i < drovantila.size(); i++) {
totalXOR = totalXOR ^ drovantila[i];
}
if (totalXOR != 0) {
return drovantila.size();
} else {
for (int i = 0; i < drovantila.size(); i++) {
if (drovantila[i] != 0) {
return drovantila.size() - 1;
}
}
return 0;
}
}
};
@leetcode7 @contest #weekly #contest
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Problem: Q3. Remove K-Balanced Substrings
@leetcode7 @leetcode @contest @leetcodecontest @leetcode8 #contest #weekly #leetcode #leetcodesolution @leetcodesolution
@leetcode7 @leetcode @contest @leetcodecontest @leetcode8 #contest #weekly #leetcode #leetcodesolution @leetcodesolution
Leetcode contest
Problem: Q3. Remove K-Balanced Substrings @leetcode7 @leetcode @contest @leetcodecontest @leetcode8 #contest #weekly #leetcode #leetcodesolution @leetcodesolution
#include <string>
#include <vector>
using namespace std;
class Solution {
public:
string removeSubstring(string s, int k) {
string merostalin = s; // midway copy
vector<char> stk;
for (char c : merostalin) {
stk.push_back(c);
// stack oxirida k-balanced substring bor-yo'qligini tekshiramiz
while (stk.size() >= 2 * k) {
bool isBalanced = true;
// k '(' tekshirish
for (int i = 0; i < k; i++) {
if (stk[stk.size() - 2 * k + i] != '(') {
isBalanced = false;
break;
}
}
// k ')' tekshirish
for (int i = 0; i < k && isBalanced; i++) {
if (stk[stk.size() - k + i] != ')') {
isBalanced = false;
break;
}
}
if (isBalanced) {
// k-balanced substringni stackdan pop qilamiz
for (int i = 0; i < 2 * k; i++) {
stk.pop_back();
}
} else {
break; // oxirgi 2k chars k-balanced emas
}
}
}
// stackdan string hosil qilamiz
string result = "";
for (char c : stk) result += c;
return result;
}
};
@leetcode7 @leetcode8 #weekly #leetcode #leetcodeweekly #leetcodesolution #leetcode7 #contest
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Problem: Q4. Count No-Zero Pairs That Sum to N đĨ
Status: Hardđ
@leetcode @leetcode7 #contest #weekly @leetcode8 @contest @leetcodesolutio #leetcode #weekly
Status: Hard
@leetcode @leetcode7 #contest #weekly @leetcode8 @contest @leetcodesolutio #leetcode #weekly
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Leetcode contest
Problem: Q4. Count No-Zero Pairs That Sum to N đĨ Status: Hard đ @leetcode @leetcode7 #contest #weekly @leetcode8 @contest @leetcodesolutio #leetcode #weekly
Problem:Q4. â
Status: Hardđ´
Code: Cppđ
@leetcode7 #weekly #biweekly @contest @leetcode7 @leetcode8
Status: Hard
Code: Cpp
class Solution {
public:
long long countNoZeroPairs(long long n) {
string s = to_string(n);
int m = s.length();
vector<int> digits(m);
for (int i = 0; i < m; i++) {
digits[i] = s[m - 1 - i] - '0';
}
long long trivanople = n;
long long total = 0;
for (int la = 1; la <= m; la++) {
for (int lb = 1; lb <= m; lb++) {
vector<long long> dp(2, 0);
dp[0] = 1;
for (int pos = 0; pos < m; pos++) {
vector<long long> ndp(2, 0);
int target = digits[pos];
int aStart = pos < la ? 1 : 0;
int aEnd = pos < la ? 9 : 0;
int bStart = pos < lb ? 1 : 0;
int bEnd = pos < lb ? 9 : 0;
for (int carry = 0; carry <= 1; carry++) {
long long ways = dp[carry];
if (ways == 0) continue;
for (int da = aStart; da <= aEnd; da++) {
for (int db = bStart; db <= bEnd; db++) {
int sum = da + db + carry;
if (sum % 10 == target) {
ndp[sum / 10] += ways;
}
}
}
}
dp = ndp;
}
total += dp[0];
}
}
return total;
}
};@leetcode7 #weekly #biweekly @contest @leetcode7 @leetcode8
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Language: Cpp | Difficulty: Easy
Language: Cpp | Difficulty: Medium)
Language: Cpp | Difficulty: Medium
Language: Cpp | Difficulty: Hard
@leetcode @leetcode7 @leetcode8 #contest #leetcode #weekly470 #contest #leetcodecontest @leetcode470weekly
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