Lead Coding 2.0
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I am Mohammad Fraz.
This channel is for Interview Preparation
You can check out the main channel (Lead Coding)
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2Q- Next greater element
Q3 Remove k digits
4Q Maximum of all the subarray of size k
Aaj video 8 baje Start hoga
Q-Kth largest element in a stream
We will start another series soon

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Will start at 9
Aajao sab 🔥🔥
Full power
Class 1 went well 🔥
Solve these

1)
int i, j;
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++)
cout << "Fraz Bhaiya";


2)

int a = 0;
for (i = 0; i < N; i++) {
a = a + i;
}

3)

int a = 0;
for (i = 0; i < N; i++) {
for (j = N; j > i; j--) {
a = a + i + j;
}
}



4)

int i, j, k = 0;
for (i = 1; i <= n; i++) {
for (j = 1; j <= n; j = j * 2) {
k = k + n / 2;
}
}



5)
int k = 1;
for(int i=0;i<n;i++){
i*=k;
}

6)

int i, j;
for (i = 1; i <= n; i++)
for (j = 1; j <= log(i); j++)
cout << "Fraz Bhaiya";



7)

for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
for(int k=0;k<n;k++){
cout<<"Keep Smiling";
}
}
}

8)

for(int i=0;i<n*n;i++){
cout<<"Awesome"
}


9)

sqrt => means Square root

for(int i=0;i<sqrt(n);i++){
cout<<"Square Root Function";
}

10)

for(int i=0;i<n;i++){
for(int j=0;j<sqrt(n);j++){
cout<<j;
}

11)
for(int i=1;i<=n;i=i*i){
cout<< i;
}

12)
for(int i=1;i<=n;i = i*i*i){
cout<<i;
}

13)
for(int i=1;i<=n;i++){
for(int j=1;j<n;j=j*j){
cout<< "Hello , Fraz Bhaiya";
}
}

14)
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j=i*i*i){
cout<<"Hello World";
}
}

15)
for(int i=1;i<=n;i++){
for(int j=1;j<n;i++){
cout<<"*";
}
}

16)
for(int i=0;i<n;i++){
for( ; i<n;i++){
cout<<"Hi ";
}
}

17)
for(int i=n;i>0;i++){
cout<<"I am iron man";
}

18)
for(int i=n*n;i>i;i--){
cout<<"I am Groot!!!";
}

19)
for(int i=n*n;i>0;i--){
for(int j=0;j<n;j++){
cout<<"I am Peter Parker!!!";
}
}

20)
for(int i=0;i<n;i=i+n){
for(int j=0;j<n;j++){
cout<<"I am inevitable!!!";
}
}