The time complexity of the above solution is O(n) and doesn’t require any extra space, where n is the size of the input.
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#Data_structure

Java Management Service

Java Management Service (JMS) is a reporting and management service within Oracle Cloud Infrastructure (OCI). JMS can track Java usage running on OCI; on on-premises desktops, laptops, and servers; and on third-party cloud services. It also monitors the Java Development Kit, Java Runtime Environment, and GraalVM. We give an overview, vision, roadmap, architecture, and demo of JMS capabilities.

Pattern 6
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#42

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#42

Pattern 7
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#43

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#43

Pattern 8
#Source_code
#43

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#43

Pattern 9
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#44

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#44

Java Modules in Real Life
Get advice on why, when, when not,and how to use Java modules in real life for your Java projects.

💀lul

Pattern 10
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#45

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#45

Pattern 11
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#46

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#46

Find the Duplicate element in a limited range array
Given a limited range array of size n containing elements between 1 and n-1 with one element repeating, find the duplicate number in it without using any extra space.

#Data_structure

Using Hashing
The idea is to use hashing to solve this problem. We can use a visited boolean array to mark if an element is seen before or not. If the element is already encountered before, the visited array will return true.
#Data_structure
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Using Array Indices
We can solve this problem in constant space. Since the array contains all distinct elements except one and all elements lie in range 1 to n-1, we can check for a duplicate element by marking array elements as negative using the array index as a key. For each array element nums[i], invert the sign of the element present at index nums[i]. Finally, traverse the array once again, and if a positive number is found at index i, then the duplicate element is i.

The above approach takes two traversals of the array. We can achieve the same in only a single traversal. For each array element nums[i], invert the sign of the element present at index nums[i] if it is positive; otherwise, if the element is already negative, then it is a duplicate.

#Data_structure
#Source_code